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Please can any one help I am trying to set up an easy worksheet that will record fishing weighs lbs & oz.
I want to list each fishermans weight by name the what they have caught and the an overall weigh column as well. I can get the formular to add the pound and oz together and to round up the oz to make a whole pound. example 3lbs 13oz and 2lbs 11oz it comes up with 5.24 instead of 6.05 |
#2
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#3
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Ron Rosenfeld wrote on 6/18/2012 :
On Mon, 18 Jun 2012 14:17:38 -0700 (PDT), wrote: Please can any one help I am trying to set up an easy worksheet that will record fishing weighs lbs & oz. I want to list each fishermans weight by name the what they have caught and the an overall weigh column as well. I can get the formular to add the pound and oz together and to round up the oz to make a whole pound. example 3lbs 13oz and 2lbs 11oz it comes up with 5.24 instead of 6.05 Please explain in more detail how you expect to obtain 6.05 from the values you've posted. I calc the sum of the two weights as 6.50lbs, NOT 6.05! -- Garry Free usenet access at http://www.eternal-september.org ClassicVB Users Regroup! comp.lang.basic.visual.misc microsoft.public.vb.general.discussion |
#4
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5 lbs + 24 oz = 6.5 lbs
Gord On Mon, 18 Jun 2012 14:17:38 -0700 (PDT), wrote: Please can any one help I am trying to set up an easy worksheet that will record fishing weighs lbs & oz. I want to list each fishermans weight by name the what they have caught and the an overall weigh column as well. I can get the formular to add the pound and oz together and to round up the oz to make a whole pound. example 3lbs 13oz and 2lbs 11oz it comes up with 5.24 instead of 6.05 |
#5
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#6
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I speculate that whatever format the OP is using it does not calc what
the text states for lbs/ozs. 3lbs 13oz is 3.81lbs; 2lbs 11oz is 2.69lbs; 3.81+2.69 = 6.50 all day long!<g -- Garry Free usenet access at http://www.eternal-september.org ClassicVB Users Regroup! comp.lang.basic.visual.misc microsoft.public.vb.general.discussion |
#7
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On Tue, 19 Jun 2012 17:06:33 -0400, GS wrote:
I speculate that whatever format the OP is using it does not calc what the text states for lbs/ozs. 3lbs 13oz is 3.81lbs; 2lbs 11oz is 2.69lbs; 3.81+2.69 = 6.50 all day long!<g He did write "3lbs 13oz and 2lbs 11oz it comes up with 5.24", so I'm guessing he's entering his data as pounds<dotounces since 2.11 + 3.13 -- 5.24 Given that, the DOLLARDE function should work OK. If that turns out to be the case, there may be some basic math issues to be dealt with. |
#8
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After serious thinking Ron Rosenfeld wrote :
On Tue, 19 Jun 2012 17:06:33 -0400, GS wrote: I speculate that whatever format the OP is using it does not calc what the text states for lbs/ozs. 3lbs 13oz is 3.81lbs; 2lbs 11oz is 2.69lbs; 3.81+2.69 = 6.50 all day long!<g He did write "3lbs 13oz and 2lbs 11oz it comes up with 5.24", so I'm guessing he's entering his data as pounds<dotounces since 2.11 + 3.13 -- 5.24 Given that, the DOLLARDE function should work OK. If that turns out to be the case, there may be some basic math issues to be dealt with. I agree! That's what I was eluding to. My position is that some reference to the standard 'Table of Weights and Measures' should be implemented so there's no ambiguity (2.11 nor 3.13 don't relate to anything in the aforementioned table) Typically, single units of measure are used and so <IMO this requires conversion for one of the components at the very least. So to go with lbs it converts as per my post. Alternatively, ounces could be used. Note that my point is based on the decimal not being a delimiter but rather a measure of precision. After all.., is it 2.11 lbs or 2.69 lbs. OR is it some home grown unit like 2.11 lboz which doesn't compute to any know standard (that I know of). -- Garry Free usenet access at http://www.eternal-september.org ClassicVB Users Regroup! comp.lang.basic.visual.misc microsoft.public.vb.general.discussion |
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