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#1
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![]() My Table Ref# Price Trans Price Trans Type 2 1 476.4 9313 476.4 10915 0 2 413.8 1582 413.8 2183 0 3 542.8 7751 542.8 10045 0 4 612.3 1131 412.3 1822 1 5 374.08 10074 374.1 10074 0 6 196.9 771 196.9 1973 0 7 529.3 5969 466.3 8783 1 8 265.6 2384 255.4 2484 1 9 268.3 4937 287.3 4637 0 10 467.6 7571 452.6 8272 1 What I need is to lookup each instance that Type 2 is value 1, and return the Ref # in a concatenated cell. I am using: =INDEX(A5:A404, MATCH(1, H5:H404, 0), 1) but it will only change once it has passed the first instance of 1 in Type 2. Example: Ref# Price Trans Price Trans Type 2 1 476.4 9313 476.4 10915 0 4 2 413.8 1582 413.8 2183 0 4 3 542.8 7751 542.8 10045 0 4 4 612.3 1131 412.3 1822 1 4 5 374.08 10074 374.1 10074 0 7 6 196.9 771 196.9 1973 0 7 7 529.3 5969 466.3 8783 1 7 8 265.6 2384 255.4 2484 1 8 9 268.3 4937 287.3 4637 0 8 10 467.6 7571 452.6 8272 1 10 My sheet has approx 4K Ref # and I have several sheets. -- Hamilton013 ------------------------------------------------------------------------ Hamilton013's Profile: http://www.excelforum.com/member.php...o&userid=18440 View this thread: http://www.excelforum.com/showthread...hreadid=390761 |
#2
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![]() To concatenate several values, the best thing is to install the Morefunc Add-in: http://xcell05.free.fr/ click on English pages. Use the MCONCAT function. Example: =MCONCAT(IF(H5:H404=1,A5:A404&" ","")) It's not easy to concatenate an Array with normal Excel functions or formulas. Hope it helped Ola Sandström -- olasa ------------------------------------------------------------------------ olasa's Profile: http://www.excelforum.com/member.php...o&userid=17760 View this thread: http://www.excelforum.com/showthread...hreadid=390761 |
#3
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![]() Perfect! Thanks a bunch. That saves me hours. -- Hamilton013 ------------------------------------------------------------------------ Hamilton013's Profile: http://www.excelforum.com/member.php...o&userid=18440 View this thread: http://www.excelforum.com/showthread...hreadid=390761 |
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