How can I find the last nonblank value in a column of numbers?

TIA

GWB

Try this:

=LOOKUP(2,1/(1-ISBLANK(F1:F1000)),F1:F1000)
--

HTH,

RD
==============================================
Please keep all correspondence within the Group, so all may benefit!
==============================================


"George W. Barrowcliff" wrote in message
m...
How can I find the last nonblank value in a column of numbers?

TIA

GWB

George,

Provided that you do not mean WHOLE column when you say column of numbers
try:

=LOOKUP(2,1/ISNUMBER(L1:L1000),L1:L1000)

--
HTH

Sandy

Replace@mailinator with @tiscali.co.uk


"George W. Barrowcliff" wrote in message
m...
How can I find the last nonblank value in a column of numbers?

TIA

GWB

=LOOKUP(9.99999999999999E+307,A:A)

which will return the last numeric value from column A if any.

George W. Barrowcliff wrote:
How can I find the last nonblank value in a column of numbers?

TIA

GWB

Thanks, for the quick responses. Does exactly what I needed to do.


"Sandy Mann" wrote in message
...
George,

Provided that you do not mean WHOLE column when you say column of numbers
try:

=LOOKUP(2,1/ISNUMBER(L1:L1000),L1:L1000)

--
HTH

Sandy

Replace@mailinator with @tiscali.co.uk


"George W. Barrowcliff" wrote in message
m...
How can I find the last nonblank value in a column of numbers?

TIA

GWB

That puts efficiency in back seat. <g

George W. Barrowcliff wrote:
Thanks, for the quick responses. Does exactly what I needed to do.


"Sandy Mann" wrote in message
...

George,

Provided that you do not mean WHOLE column when you say column of numbers
try:

=LOOKUP(2,1/ISNUMBER(L1:L1000),L1:L1000)

--
HTH

Sandy

Replace@mailinator with @tiscali.co.uk


"George W. Barrowcliff" wrote in message
. com...

How can I find the last nonblank value in a column of numbers?

TIA

GWB







--

[1] The SumProduct function should implicitly coerce the truth values to
their Excel numeric equivalents.
[2] The lookup functions should have an optional argument for the return
value, defaulting to #N/A in its absence.

Aladin,

I accept that your use of LOOKUP is more efficient than mine, (well my
plagiarised version really, probably the only original thought I have had
was, "I wonder if there is anything on the net about Excel?"), for one thing
'mine' used two function calls. So that I can expand my understanding of
how XL works, do you know if LOOKUP checks all 65,536 rows or just the used
range? If it does check all rows, is it still faster than a limited range -
say 1,000 rows. I other words is it 65 times faster?

--
Regards

Sandy

Replace@mailinator with @tiscali.co.uk


"Aladin Akyurek" wrote in message
...
That puts efficiency in back seat. <g

George W. Barrowcliff wrote:
Thanks, for the quick responses. Does exactly what I needed to do.


"Sandy Mann" wrote in message
...

George,

Provided that you do not mean WHOLE column when you say column of numbers
try:

=LOOKUP(2,1/ISNUMBER(L1:L1000),L1:L1000)

--
HTH

Sandy

Replace@mailinator with @tiscali.co.uk


"George W. Barrowcliff" wrote in message
.com...

How can I find the last nonblank value in a column of numbers?

TIA

GWB







--

[1] The SumProduct function should implicitly coerce the truth values to
their Excel numeric equivalents.
[2] The lookup functions should have an optional argument for the return
value, defaulting to #N/A in its absence.

Sandy Mann wrote:
Aladin,

I accept that your use of LOOKUP is more efficient than mine, (well my
plagiarised version really, probably the only original thought I have had
was, "I wonder if there is anything on the net about Excel?"), for one thing
'mine' used two function calls. So that I can expand my understanding of
how XL works, do you know if LOOKUP checks all 65,536 rows or just the used
range? If it does check all rows, is it still faster than a limited range -
say 1,000 rows. I other words is it 65 times faster?


LOOKUP() effects a binary search (see:
http://www.nist.gov/dads/HTML/binarySearch.html), thus very fast.

In

=LOOKUP(2,1/ISNUMBER(L1:L1000),L1:L1000)

it's not LOOKUP itself that requires time. Rather:

(a) the evaluation of ISNUMBER(L1:L1000), and

(b) 1/Expression

Hence, the formula

=LOOKUP(2,1/ISNUMBER(L1:L1000),L1:L1000)

is significantly less efficient compared to

=LOOKUP(9.99999999999999E+307,L:L)

When the interest is in retrieving the last numeric value, one would
should invoke the latter, not the former.

"Aladin Akyurek" wrote in message
...

LOOKUP() effects a binary search (see:
http://www.nist.gov/dads/HTML/binarySearch.html), thus very fast.


Thank you Aladin.

I don't profess to understand all the information in link that you posted
but I took from it that in the worst case scenario it would only take 17
comparisons to produce a result for 65536 rows which, as you said, is very
fast

--
Regards

Sandy

Replace@mailinator with @tiscali.co.uk

Can someone please explain how this formula works

=LOOKUP(2,1/ISNUMBER(L1:L1000),L1:L1000)

in the context LOOKUP vector having the following syntax
LOOKUP(LOOKUP_VALUE,LOOKUP_VECTOR,RESULT_VECTOR)

If Column L contains data, ISNUMBER(L1:L1000) evaluates to TRUE (or 1)
with the reciprocal also being 1. Parsed to the LOOKUP function, the
result yields
=LOOKUP(2,1,L1:L1000) - which is nothing like the conventional syntax
quoted above. I am stumped.

TIA


--
davidm
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See my contrib in:

http://tinyurl.com/7ysq5

davidm wrote:
Can someone please explain how this formula works

=LOOKUP(2,1/ISNUMBER(L1:L1000),L1:L1000)

in the context LOOKUP vector having the following syntax
LOOKUP(LOOKUP_VALUE,LOOKUP_VECTOR,RESULT_VECTOR)

If Column L contains data, ISNUMBER(L1:L1000) evaluates to TRUE (or 1)
with the reciprocal also being 1. Parsed to the LOOKUP function, the
result yields
=LOOKUP(2,1,L1:L1000) - which is nothing like the conventional syntax
quoted above. I am stumped.

TIA

Many thanks, Aladin. It is crystal plain now, thanks to your elaborate
discourse in the link provided. I cannot cease to be amazed at some of
the discoveries made about the behaviour of worksheet functions-as yet
not documented!


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Aladin,

I sense a downside to the "Bignumber" deployment. While the formulas
work flawlessly for soted data, LOOKUP seems to get into a tailspin if
the data is *unsorted*. Any comments?


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