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#1
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Can anyone help? I am trying to copy cells across a row using the fill handle
that are referencing another sheet down a column. I am placing a "$" in front of the letter as to not change it, but since I am copying across, the number will not change. Is there any way to tell Excel that i want the number to advance as I copy across? |
#2
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If you want "the number" to advance as you copy across, then don't put a $
in front of it, as in: =$A1*2 Regards, Fred "RRG" wrote in message ... Can anyone help? I am trying to copy cells across a row using the fill handle that are referencing another sheet down a column. I am placing a "$" in front of the letter as to not change it, but since I am copying across, the number will not change. Is there any way to tell Excel that i want the number to advance as I copy across? |
#3
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What you seek is to transpose contents from a source col into a destination row
One way, in say Sheet1, in B2: =INDEX(Sheet2!$A:$A,COLUMNS($A:A)) Copy B2 across as far as required. This links/returns the contents of Sheet2's A1, A2, A3, etc in Sheet1's B2, B3, B4, etc. Joy? hit the YES below -- Max Singapore --- "RRG" wrote: Can anyone help? I am trying to copy cells across a row using the fill handle that are referencing another sheet down a column. I am placing a "$" in front of the letter as to not change it, but since I am copying across, the number will not change. Is there any way to tell Excel that i want the number to advance as I copy across? |
#4
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Let's say in Sheet2 column A you have numbers 1 to 10 in A1:A10
You want them in Sheet1 from A1 to J1 Enter =INDIRECT("Sheet2!A"&COLUMN(A1)) in A1 and drag across. Gord Dibben MS Excel MVP On Thu, 22 Apr 2010 15:35:01 -0700, RRG wrote: Can anyone help? I am trying to copy cells across a row using the fill handle that are referencing another sheet down a column. I am placing a "$" in front of the letter as to not change it, but since I am copying across, the number will not change. Is there any way to tell Excel that i want the number to advance as I copy across? |
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