Reply
 
LinkBack Thread Tools Search this Thread Display Modes
  #1   Report Post  
Posted to microsoft.public.excel.worksheet.functions
external usenet poster
 
Posts: 10
Default COUNTIF for 2 columns

I'm trying to set a parameter of the following in a formula in column J:
=COUNTIF($C:$C,$B300)
That also only counts the number of times in column J where a cells (J1:J299)
value is greater than "0". ----this is where I can't figure out the how
to??

In other words, I need to set-up a formula in column J row 300 that I want
to count
the number of times that column C is equal to cell B300 only if the value in
column J's cell is greater than zero.
Thanks, Bill
  #2   Report Post  
Posted to microsoft.public.excel.worksheet.functions
external usenet poster
 
Posts: 834
Default COUNTIF for 2 columns

Try

=SUMPRODUCT(--($J$1:$J$2990),--($C$1:$C$299=$B300))

--

HTH

Bob

"b1llt" wrote in message
...
I'm trying to set a parameter of the following in a formula in column J:
=COUNTIF($C:$C,$B300)
That also only counts the number of times in column J where a cells
(J1:J299)
value is greater than "0". ----this is where I can't figure out the how
to??

In other words, I need to set-up a formula in column J row 300 that I want
to count
the number of times that column C is equal to cell B300 only if the value
in
column J's cell is greater than zero.
Thanks, Bill



  #3   Report Post  
Posted to microsoft.public.excel.worksheet.functions
external usenet poster
 
Posts: 47
Default COUNTIF for 2 columns

Try this


=COUNTIFS(C1:C299,B300,J1:J299,"0")

  #4   Report Post  
Posted to microsoft.public.excel.worksheet.functions
AGV AGV is offline
external usenet poster
 
Posts: 1
Default COUNTIF for 2 columns

Great suggestion Bob, also if your using excel 2007 you can use the COUNTIFS
function:

=COUNTIFS($C$1:$C$299,$B$300,$J$1:$J$299,""&0)

AGV

"Bob Phillips" wrote:

Try

=SUMPRODUCT(--($J$1:$J$2990),--($C$1:$C$299=$B300))

--

HTH

Bob

"b1llt" wrote in message
...
I'm trying to set a parameter of the following in a formula in column J:
=COUNTIF($C:$C,$B300)
That also only counts the number of times in column J where a cells
(J1:J299)
value is greater than "0". ----this is where I can't figure out the how
to??

In other words, I need to set-up a formula in column J row 300 that I want
to count
the number of times that column C is equal to cell B300 only if the value
in
column J's cell is greater than zero.
Thanks, Bill



.

  #5   Report Post  
Posted to microsoft.public.excel.worksheet.functions
external usenet poster
 
Posts: 47
Default COUNTIF for 2 columns

Another 2003 solution is an array formula

=SUM(($K$15:$K$38=K41)*($M$15:$M$38=1))

Set with CTRL-Shift-Enter


  #6   Report Post  
Posted to microsoft.public.excel.worksheet.functions
external usenet poster
 
Posts: 10
Default COUNTIF for 2 columns

I should have mentioned we're still on Excel 2000.
I used these and am getting a #DIV/0! result.
Any suggestions ---thanks,
Bill

"Ziggy" wrote:

Another 2003 solution is an array formula

=SUM(($K$15:$K$38=K41)*($M$15:$M$38=1))

Set with CTRL-Shift-Enter
.

  #7   Report Post  
Posted to microsoft.public.excel.worksheet.functions
external usenet poster
 
Posts: 8,651
Default COUNTIF for 2 columns

There are no divide operations in that formula, so if you're seeing a
#DIV/0! result it's because you've got a #DIV/0! in the data being used by
the formula. Tackle the problem where it's being generated.
--
David Biddulph


"b1llt" wrote in message
...
I should have mentioned we're still on Excel 2000.
I used these and am getting a #DIV/0! result.
Any suggestions ---thanks,
Bill

"Ziggy" wrote:

Another 2003 solution is an array formula

=SUM(($K$15:$K$38=K41)*($M$15:$M$38=1))

Set with CTRL-Shift-Enter
.


  #8   Report Post  
Posted to microsoft.public.excel.worksheet.functions
external usenet poster
 
Posts: 10
Default COUNTIF for 2 columns

My bad! Your correct I did have it pulling a #DIV/O! into the data by mistake.
These all work great! Thanks everyone for all your help.
-B1llt

"David Biddulph" wrote:

There are no divide operations in that formula, so if you're seeing a
#DIV/0! result it's because you've got a #DIV/0! in the data being used by
the formula. Tackle the problem where it's being generated.
--
David Biddulph


"b1llt" wrote in message
...
I should have mentioned we're still on Excel 2000.
I used these and am getting a #DIV/0! result.
Any suggestions ---thanks,
Bill

"Ziggy" wrote:

Another 2003 solution is an array formula

=SUM(($K$15:$K$38=K41)*($M$15:$M$38=1))

Set with CTRL-Shift-Enter
.


.

Reply
Thread Tools Search this Thread
Search this Thread:

Advanced Search
Display Modes

Posting Rules

Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On


Similar Threads
Thread Thread Starter Forum Replies Last Post
COUNTIF across sheets in columns meekjj13 Excel Worksheet Functions 1 March 10th 10 01:00 AM
COUNTIF - across 2 columns Rebekah Excel Worksheet Functions 11 November 9th 09 03:43 PM
Countif for 2 columns earlfj Excel Worksheet Functions 3 September 27th 09 05:42 AM
countif in 2 columns Tonso Excel Discussion (Misc queries) 4 October 23rd 07 04:51 PM
Help with countif using two columns Vipulparbat Excel Worksheet Functions 4 August 18th 06 02:03 AM


All times are GMT +1. The time now is 09:06 PM.

Powered by vBulletin® Copyright ©2000 - 2024, Jelsoft Enterprises Ltd.
Copyright ©2004-2024 ExcelBanter.
The comments are property of their posters.
 

About Us

"It's about Microsoft Excel"