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#1
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Conditions Not Accurate when subtracting time
When I subtract two times e.g.
b1 is 21:35 a1 is 20:55 the answer shows correctly i.e. 40:00 (using [m]:ss format) but when I set the condition b1-a115 the answer is FALSE. How do I subract two times and then check if the result is greater than a value I specify? |
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#2
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Conditions Not Accurate when subtracting time
Hi,
=B1-A1TIME(0,15,0) -- Mike When competing hypotheses are otherwise equal, adopt the hypothesis that introduces the fewest assumptions while still sufficiently answering the question. "sly411" wrote: When I subtract two times e.g. b1 is 21:35 a1 is 20:55 the answer shows correctly i.e. 40:00 (using [m]:ss format) but when I set the condition b1-a115 the answer is FALSE. How do I subract two times and then check if the result is greater than a value I specify? |
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#3
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Conditions Not Accurate when subtracting time
=(B1-A1)*144015
"sly411" wrote: When I subtract two times e.g. b1 is 21:35 a1 is 20:55 the answer shows correctly i.e. 40:00 (using [m]:ss format) but when I set the condition b1-a115 the answer is FALSE. How do I subract two times and then check if the result is greater than a value I specify? |
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#4
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Conditions Not Accurate when subtracting time
Perfect, thanks
"Mike H" wrote: Hi, =B1-A1TIME(0,15,0) -- Mike When competing hypotheses are otherwise equal, adopt the hypothesis that introduces the fewest assumptions while still sufficiently answering the question. "sly411" wrote: When I subtract two times e.g. b1 is 21:35 a1 is 20:55 the answer shows correctly i.e. 40:00 (using [m]:ss format) but when I set the condition b1-a115 the answer is FALSE. How do I subract two times and then check if the result is greater than a value I specify? |
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