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#1
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testing for left 2 characters in set of 3 choices
following returns true even if false
a1=ab1234 b1=if(left A1,2)=or("cd","ef","gh"),1,2) test if A1=cd or ef or gh, true 1, false 2 the above should return 2 false but returns 1 true in error? I tried formula evaluation and it shows "ab"=false but then evalutes combined to true in error. |
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#2
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testing for left 2 characters in set of 3 choices
=IF(OR(LEFT(A1,2)={"cd","ef","gh"}),1,2)
-- Gary''s Student - gsnu200909 |
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#3
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testing for left 2 characters in set of 3 choices
Hi,
=IF(OR(LEFT(A1,2)="cd",LEFT(A1,2)="ef",LEFT(A1,2)= "gh"),1,2) "MusicMan" wrote: following returns true even if false a1=ab1234 b1=if(left A1,2)=or("cd","ef","gh"),1,2) test if A1=cd or ef or gh, true 1, false 2 the above should return 2 false but returns 1 true in error? I tried formula evaluation and it shows "ab"=false but then evalutes combined to true in error. |
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#4
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testing for left 2 characters in set of 3 choices
Use your formula like the below:-
=IF(OR(LEFT(A1,2)="CD",LEFT(A1,2)="EF",LEFT(A1,2)= "GH"),"TRUE 1","FALSE 2") Remember to Click Yes, if this post helps! -------------------- (Ms-Exl-Learner) -------------------- "MusicMan" wrote: following returns true even if false a1=ab1234 b1=if(left A1,2)=or("cd","ef","gh"),1,2) test if A1=cd or ef or gh, true 1, false 2 the above should return 2 false but returns 1 true in error? I tried formula evaluation and it shows "ab"=false but then evalutes combined to true in error. |
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#5
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testing for left 2 characters in set of 3 choices
You'll need to show us exactly what is in your formulae, and explain more
clearly what your problem is. =if(left A1,2)=or("cd","ef","gh"),1,2) would not be a valid formula, as the parentheses don't match. When you've sorted out the parentheses, you've still got =OR("cd","ef","gh") which is feeding text strings into a function that wants Boolean inputs, so it gives a #VALUE! error. Start again, but this time be more precise with the wording of your question. -- David Biddulph "MusicMan" wrote in message ... following returns true even if false a1=ab1234 b1=if(left A1,2)=or("cd","ef","gh"),1,2) test if A1=cd or ef or gh, true 1, false 2 the above should return 2 false but returns 1 true in error? I tried formula evaluation and it shows "ab"=false but then evalutes combined to true in error. |
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#6
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testing for left 2 characters in set of 3 choices
=AND(LEFT(A1,2)<{"cd","ef","gh"})+1
"MusicMan" wrote: following returns true even if false a1=ab1234 b1=if(left A1,2)=or("cd","ef","gh"),1,2) test if A1=cd or ef or gh, true 1, false 2 the above should return 2 false but returns 1 true in error? I tried formula evaluation and it shows "ab"=false but then evalutes combined to true in error. |
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