=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average. Problem...if
the field is blank it's counting it as zero and lowering the results. It
figured 79% when it should have been 94%. 94% was returned using the simple
average formula. I'm guessing I need to nest something to not count nulls?
Help!!!

Spottkitty

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average. Problem...if
the field is blank it's counting it as zero and lowering the results. It
figured 79% when it should have been 94%. 94% was returned using the simple
average formula. I'm guessing I need to nest something to not count nulls?
Help!!!

Thank you SOOOOOOOOO Much!!!! Worked like a charm!

"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

Hi,

I have a question for Excel 2003

=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Dat a!$C:$C,""))

Im trying to get the AVERAGE of this and its giving me a #VALUE! error.. $A2
is the name that is suppose to be equal in the Data! worksheet and B$1 is the
date that is suppose to be equal in the Data! worksheet. Im trying to use AND
in IF for me to have two logical test..

Can you help me with this?

Thank you so much!



"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average. Problem...if
the field is blank it's counting it as zero and lowering the results. It
figured 79% when it should have been 94%. 94% was returned using the simple
average formula. I'm guessing I need to nest something to not count nulls?
Help!!!

You can't use the entire column for array formulas in xl2003 and below.

(Remember to use ctrl-shift-enter, too)

Hijosdelongi wrote:

Hi,

I have a question for Excel 2003

=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Dat a!$C:$C,""))

Im trying to get the AVERAGE of this and its giving me a #VALUE! error.. $A2
is the name that is suppose to be equal in the Data! worksheet and B$1 is the
date that is suppose to be equal in the Data! worksheet. Im trying to use AND
in IF for me to have two logical test..

Can you help me with this?

Thank you so much!

"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average. Problem...if
the field is blank it's counting it as zero and lowering the results. It
figured 79% when it should have been 94%. 94% was returned using the simple
average formula. I'm guessing I need to nest something to not count nulls?
Help!!!


--

Dave Peterson

ic, but is the =AVERAGE(IF(AND( correct?

Thanks



"Dave Peterson" wrote:

You can't use the entire column for array formulas in xl2003 and below.

(Remember to use ctrl-shift-enter, too)

Hijosdelongi wrote:

Hi,

I have a question for Excel 2003

=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Dat a!$C:$C,""))

Im trying to get the AVERAGE of this and its giving me a #VALUE! error.. $A2
is the name that is suppose to be equal in the Data! worksheet and B$1 is the
date that is suppose to be equal in the Data! worksheet. Im trying to use AND
in IF for me to have two logical test..

Can you help me with this?

Thank you so much!

"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average. Problem...if
the field is blank it's counting it as zero and lowering the results. It
figured 79% when it should have been 94%. 94% was returned using the simple
average formula. I'm guessing I need to nest something to not count nulls?
Help!!!


--

Dave Peterson

I have a question for Excel 2003
=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Da ta!$C:$C,""))

You can't use entire columns as range references in array formulas in Excel
2003. Use a smaller specific range.

Try it like this (array entered**)

=AVERAGE(IF((Data!A1:A10=B1)*(Data!B1:B10=A2),Data !C1:C10))

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the SHIFT
key then hit ENTER.

--
Biff
Microsoft Excel MVP


"Hijosdelongi" wrote in message
...
Hi,

I have a question for Excel 2003

=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Dat a!$C:$C,""))

Im trying to get the AVERAGE of this and its giving me a #VALUE! error..
$A2
is the name that is suppose to be equal in the Data! worksheet and B$1 is
the
date that is suppose to be equal in the Data! worksheet. Im trying to use
AND
in IF for me to have two logical test..

Can you help me with this?

Thank you so much!



"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average.
Problem...if
the field is blank it's counting it as zero and lowering the results.
It
figured 79% when it should have been 94%. 94% was returned using the
simple
average formula. I'm guessing I need to nest something to not count
nulls?
Help!!!

EXCELENT! It worked!!! and how can I hide the #DIV/0! if there are still no
scores for that they..

Thank you :)


"T. Valko" wrote:

I have a question for Excel 2003
=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Da ta!$C:$C,""))

You can't use entire columns as range references in array formulas in Excel
2003. Use a smaller specific range.

Try it like this (array entered**)

=AVERAGE(IF((Data!A1:A10=B1)*(Data!B1:B10=A2),Data !C1:C10))

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the SHIFT
key then hit ENTER.

--
Biff
Microsoft Excel MVP


"Hijosdelongi" wrote in message
...
Hi,

I have a question for Excel 2003

=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Dat a!$C:$C,""))

Im trying to get the AVERAGE of this and its giving me a #VALUE! error..
$A2
is the name that is suppose to be equal in the Data! worksheet and B$1 is
the
date that is suppose to be equal in the Data! worksheet. Im trying to use
AND
in IF for me to have two logical test..

Can you help me with this?

Thank you so much!



"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average.
Problem...if
the field is blank it's counting it as zero and lowering the results.
It
figured 79% when it should have been 94%. 94% was returned using the
simple
average formula. I'm guessing I need to nest something to not count
nulls?
Help!!!

Try it like this:

Array entered.

=IF(ISERROR(AVERAGE(IF((Data!A1:A10=B1)*(Data!B1:B 10=A2),Data!C1:C10))),"",AVERAGE(IF((Data!A1:A10=B 1)*(Data!B1:B10=A2),Data!C1:C10)))

--
Biff
Microsoft Excel MVP


"Hijosdelongi" wrote in message
...
EXCELENT! It worked!!! and how can I hide the #DIV/0! if there are still
no
scores for that they..

Thank you :)


"T. Valko" wrote:

I have a question for Excel 2003
=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Da ta!$C:$C,""))

You can't use entire columns as range references in array formulas in
Excel
2003. Use a smaller specific range.

Try it like this (array entered**)

=AVERAGE(IF((Data!A1:A10=B1)*(Data!B1:B10=A2),Data !C1:C10))

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the
SHIFT
key then hit ENTER.

--
Biff
Microsoft Excel MVP


"Hijosdelongi" wrote in message
...
Hi,

I have a question for Excel 2003

=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Dat a!$C:$C,""))

Im trying to get the AVERAGE of this and its giving me a #VALUE!
error..
$A2
is the name that is suppose to be equal in the Data! worksheet and B$1
is
the
date that is suppose to be equal in the Data! worksheet. Im trying to
use
AND
in IF for me to have two logical test..

Can you help me with this?

Thank you so much!



"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average.
Problem...if
the field is blank it's counting it as zero and lowering the
results.
It
figured 79% when it should have been 94%. 94% was returned using
the
simple
average formula. I'm guessing I need to nest something to not count
nulls?
Help!!!

Hi,

I have a Question.. is VLOOKUP plus IF possible? This is my fomula..

=VLOOKUP(IF((Data!A1:A1000=A1)*(Data!B1:B1000=D1), ....

is my logical tests or conditions correct? and how will i put the VLOOKUP
codes?

Can you help me with this..

THank you so much



"T. Valko" wrote:

I have a question for Excel 2003
=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Da ta!$C:$C,""))

You can't use entire columns as range references in array formulas in Excel
2003. Use a smaller specific range.

Try it like this (array entered**)

=AVERAGE(IF((Data!A1:A10=B1)*(Data!B1:B10=A2),Data !C1:C10))

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the SHIFT
key then hit ENTER.

--
Biff
Microsoft Excel MVP


"Hijosdelongi" wrote in message
...
Hi,

I have a question for Excel 2003

=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Dat a!$C:$C,""))

Im trying to get the AVERAGE of this and its giving me a #VALUE! error..
$A2
is the name that is suppose to be equal in the Data! worksheet and B$1 is
the
date that is suppose to be equal in the Data! worksheet. Im trying to use
AND
in IF for me to have two logical test..

Can you help me with this?

Thank you so much!



"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average.
Problem...if
the field is blank it's counting it as zero and lowering the results.
It
figured 79% when it should have been 94%. 94% was returned using the
simple
average formula. I'm guessing I need to nest something to not count
nulls?
Help!!!

Hi T. Valko,

How are you?

Got a Question again... im trying to get a data from the database using
VLOOKUP and why is that even though there is no value in the database it
still displays the 0 value?

And can you teach mo how to get a value from the database even though theres
no value in it?

ex.

A1 = "null value or no value"

how will display a value that is equivalent to a text or number even though
theres no value in the database?

Thank you.



"T. Valko" wrote:

I have a question for Excel 2003
=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Da ta!$C:$C,""))

You can't use entire columns as range references in array formulas in Excel
2003. Use a smaller specific range.

Try it like this (array entered**)

=AVERAGE(IF((Data!A1:A10=B1)*(Data!B1:B10=A2),Data !C1:C10))

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the SHIFT
key then hit ENTER.

--
Biff
Microsoft Excel MVP


"Hijosdelongi" wrote in message
...
Hi,

I have a question for Excel 2003

=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Dat a!$C:$C,""))

Im trying to get the AVERAGE of this and its giving me a #VALUE! error..
$A2
is the name that is suppose to be equal in the Data! worksheet and B$1 is
the
date that is suppose to be equal in the Data! worksheet. Im trying to use
AND
in IF for me to have two logical test..

Can you help me with this?

Thank you so much!



"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average.
Problem...if
the field is blank it's counting it as zero and lowering the results.
It
figured 79% when it should have been 94%. 94% was returned using the
simple
average formula. I'm guessing I need to nest something to not count
nulls?
Help!!!

You'll have to post the formula.

--
Biff
Microsoft Excel MVP


"Hijosdelongi" wrote in message
...
Hi T. Valko,

How are you?

Got a Question again... im trying to get a data from the database using
VLOOKUP and why is that even though there is no value in the database it
still displays the 0 value?

And can you teach mo how to get a value from the database even though
theres
no value in it?

ex.

A1 = "null value or no value"

how will display a value that is equivalent to a text or number even
though
theres no value in the database?

Thank you.



"T. Valko" wrote:

I have a question for Excel 2003
=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Da ta!$C:$C,""))

You can't use entire columns as range references in array formulas in
Excel
2003. Use a smaller specific range.

Try it like this (array entered**)

=AVERAGE(IF((Data!A1:A10=B1)*(Data!B1:B10=A2),Data !C1:C10))

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the
SHIFT
key then hit ENTER.

--
Biff
Microsoft Excel MVP


"Hijosdelongi" wrote in message
...
Hi,

I have a question for Excel 2003

=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Dat a!$C:$C,""))

Im trying to get the AVERAGE of this and its giving me a #VALUE!
error..
$A2
is the name that is suppose to be equal in the Data! worksheet and B$1
is
the
date that is suppose to be equal in the Data! worksheet. Im trying to
use
AND
in IF for me to have two logical test..

Can you help me with this?

Thank you so much!



"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average.
Problem...if
the field is blank it's counting it as zero and lowering the
results.
It
figured 79% when it should have been 94%. 94% was returned using
the
simple
average formula. I'm guessing I need to nest something to not count
nulls?
Help!!!

hi Again,

Got a question again, is there any formula that can automatically erase or
remove an entire row if a specific cell doesnt have any value or an error
value to it???

ex.

I have this vlookup value in column E
=IF(ISERROR(VLOOKUP(A1:A5,Sheet1!B1:E100,3,FALSE)) ,"",VLOOKUP(A1:A5,Sheet1!B1:E100,3,FALSE)))

Is there anyway that i can delete or remove the entire row 4 if theres no
returned value or an error value???

A B C D E
1 x g e e sharon
2 x as vf v sharon
3 y g h j david
4 f b a r
5 p r e f dexter

Thank you..


"T. Valko" wrote:

I have a question for Excel 2003
=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Da ta!$C:$C,""))

You can't use entire columns as range references in array formulas in Excel
2003. Use a smaller specific range.

Try it like this (array entered**)

=AVERAGE(IF((Data!A1:A10=B1)*(Data!B1:B10=A2),Data !C1:C10))

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the SHIFT
key then hit ENTER.

--
Biff
Microsoft Excel MVP


"Hijosdelongi" wrote in message
...
Hi,

I have a question for Excel 2003

=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Dat a!$C:$C,""))

Im trying to get the AVERAGE of this and its giving me a #VALUE! error..
$A2
is the name that is suppose to be equal in the Data! worksheet and B$1 is
the
date that is suppose to be equal in the Data! worksheet. Im trying to use
AND
in IF for me to have two logical test..

Can you help me with this?

Thank you so much!



"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average.
Problem...if
the field is blank it's counting it as zero and lowering the results.
It
figured 79% when it should have been 94%. 94% was returned using the
simple
average formula. I'm guessing I need to nest something to not count
nulls?
Help!!!

No, a formula can't do that. If you want it to be "semi-automatic" you'd
need a macro.

You can do it with a few clicks of a mouse...

Remove the error trap from your formula and let the errors generate.
Select column E
Goto the menu EditGo ToSpecial
Select: Formulas and uncheck everything *except* Errors
OK

That will select all the cells in col E that contain errors

Goto the menu EditDelete
Select: Entire Row
OK

--
Biff
Microsoft Excel MVP


"Hijosdelongi" wrote in message
...
hi Again,

Got a question again, is there any formula that can automatically erase or
remove an entire row if a specific cell doesnt have any value or an error
value to it???

ex.

I have this vlookup value in column E
=IF(ISERROR(VLOOKUP(A1:A5,Sheet1!B1:E100,3,FALSE)) ,"",VLOOKUP(A1:A5,Sheet1!B1:E100,3,FALSE)))

Is there anyway that i can delete or remove the entire row 4 if theres no
returned value or an error value???

A B C D E
1 x g e e sharon
2 x as vf v sharon
3 y g h j david
4 f b a r
5 p r e f dexter

Thank you..


"T. Valko" wrote:

I have a question for Excel 2003
=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Da ta!$C:$C,""))

You can't use entire columns as range references in array formulas in
Excel
2003. Use a smaller specific range.

Try it like this (array entered**)

=AVERAGE(IF((Data!A1:A10=B1)*(Data!B1:B10=A2),Data !C1:C10))

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the
SHIFT
key then hit ENTER.

--
Biff
Microsoft Excel MVP


"Hijosdelongi" wrote in message
...
Hi,

I have a question for Excel 2003

=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Dat a!$C:$C,""))

Im trying to get the AVERAGE of this and its giving me a #VALUE!
error..
$A2
is the name that is suppose to be equal in the Data! worksheet and B$1
is
the
date that is suppose to be equal in the Data! worksheet. Im trying to
use
AND
in IF for me to have two logical test..

Can you help me with this?

Thank you so much!



"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average.
Problem...if
the field is blank it's counting it as zero and lowering the
results.
It
figured 79% when it should have been 94%. 94% was returned using
the
simple
average formula. I'm guessing I need to nest something to not count
nulls?
Help!!!

Hi, got a Question again... is there any formula that can automatically
create a comment in a cell?

ex.

A1 = 80% and can we have a comment on that, that automatically that says
"Passed"

Thanks.

"T. Valko" wrote:

I have a question for Excel 2003
=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Da ta!$C:$C,""))

You can't use entire columns as range references in array formulas in Excel
2003. Use a smaller specific range.

Try it like this (array entered**)

=AVERAGE(IF((Data!A1:A10=B1)*(Data!B1:B10=A2),Data !C1:C10))

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the SHIFT
key then hit ENTER.

--
Biff
Microsoft Excel MVP


"Hijosdelongi" wrote in message
...
Hi,

I have a question for Excel 2003

=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Dat a!$C:$C,""))

Im trying to get the AVERAGE of this and its giving me a #VALUE! error..
$A2
is the name that is suppose to be equal in the Data! worksheet and B$1 is
the
date that is suppose to be equal in the Data! worksheet. Im trying to use
AND
in IF for me to have two logical test..

Can you help me with this?

Thank you so much!



"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average.
Problem...if
the field is blank it's counting it as zero and lowering the results.
It
figured 79% when it should have been 94%. 94% was returned using the
simple
average formula. I'm guessing I need to nest something to not count
nulls?
Help!!!

Hmmm....

I'm not sure. You might be able to do that with an event macro but I don't
know how to do it.

Try posting this question in the programming forum. If A1 contains a formula
make sure you note that in your question.

--
Biff
Microsoft Excel MVP


"Hijosdelongi" wrote in message
...
Hi, got a Question again... is there any formula that can automatically
create a comment in a cell?

ex.

A1 = 80% and can we have a comment on that, that automatically that says
"Passed"

Thanks.

"T. Valko" wrote:

I have a question for Excel 2003
=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Da ta!$C:$C,""))

You can't use entire columns as range references in array formulas in
Excel
2003. Use a smaller specific range.

Try it like this (array entered**)

=AVERAGE(IF((Data!A1:A10=B1)*(Data!B1:B10=A2),Data !C1:C10))

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the
SHIFT
key then hit ENTER.

--
Biff
Microsoft Excel MVP


"Hijosdelongi" wrote in message
...
Hi,

I have a question for Excel 2003

=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Dat a!$C:$C,""))

Im trying to get the AVERAGE of this and its giving me a #VALUE!
error..
$A2
is the name that is suppose to be equal in the Data! worksheet and B$1
is
the
date that is suppose to be equal in the Data! worksheet. Im trying to
use
AND
in IF for me to have two logical test..

Can you help me with this?

Thank you so much!



"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average.
Problem...if
the field is blank it's counting it as zero and lowering the
results.
It
figured 79% when it should have been 94%. 94% was returned using
the
simple
average formula. I'm guessing I need to nest something to not count
nulls?
Help!!!

Hi!

It's me again :)

I would like to ask for your help again..

How can i get the data from 1 worksheet to another?

Sheet 1

A B C
Date Name ACD
March 1 Mike 34
March 1 John 100
March 1 James 75
March 2 John 80


In Sheet 2

How can I lookup or display the data from sheet 1 to sheet to sheet 2?
ex. How can i display the ACD of John for March 1?

A B C
Date NAME ACD
March 1 John ?

What would be my formula in C3 for me to display the ACD of john for march 1?

Thank you so much for your help!

=)




"T. Valko" wrote:

I have a question for Excel 2003
=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Da ta!$C:$C,""))

You can't use entire columns as range references in array formulas in Excel
2003. Use a smaller specific range.

Try it like this (array entered**)

=AVERAGE(IF((Data!A1:A10=B1)*(Data!B1:B10=A2),Data !C1:C10))

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the SHIFT
key then hit ENTER.

--
Biff
Microsoft Excel MVP


"Hijosdelongi" wrote in message
...
Hi,

I have a question for Excel 2003

=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Dat a!$C:$C,""))

Im trying to get the AVERAGE of this and its giving me a #VALUE! error..
$A2
is the name that is suppose to be equal in the Data! worksheet and B$1 is
the
date that is suppose to be equal in the Data! worksheet. Im trying to use
AND
in IF for me to have two logical test..

Can you help me with this?

Thank you so much!



"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average.
Problem...if
the field is blank it's counting it as zero and lowering the results.
It
figured 79% when it should have been 94%. 94% was returned using the
simple
average formula. I'm guessing I need to nest something to not count
nulls?
Help!!!

Try this array formula

=INDEX(Sheet1!$C:$C,MATCH(1,(Sheet1!$A$2:$A$200=A2 )*(Sheet1!$B$2:$B$200=B2),0))


--

HTH

Bob

"Hijosdelongi" wrote in message
...
Hi!

It's me again :)

I would like to ask for your help again..

How can i get the data from 1 worksheet to another?

Sheet 1

A B C
Date Name ACD
March 1 Mike 34
March 1 John 100
March 1 James 75
March 2 John 80


In Sheet 2

How can I lookup or display the data from sheet 1 to sheet to sheet 2?
ex. How can i display the ACD of John for March 1?

A B C
Date NAME ACD
March 1 John ?

What would be my formula in C3 for me to display the ACD of john for march
1?

Thank you so much for your help!

=)




"T. Valko" wrote:

I have a question for Excel 2003
=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Da ta!$C:$C,""))

You can't use entire columns as range references in array formulas in
Excel
2003. Use a smaller specific range.

Try it like this (array entered**)

=AVERAGE(IF((Data!A1:A10=B1)*(Data!B1:B10=A2),Data !C1:C10))

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the
SHIFT
key then hit ENTER.

--
Biff
Microsoft Excel MVP


"Hijosdelongi" wrote in message
...
Hi,

I have a question for Excel 2003

=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Dat a!$C:$C,""))

Im trying to get the AVERAGE of this and its giving me a #VALUE!
error..
$A2
is the name that is suppose to be equal in the Data! worksheet and B$1
is
the
date that is suppose to be equal in the Data! worksheet. Im trying to
use
AND
in IF for me to have two logical test..

Can you help me with this?

Thank you so much!



"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average.
Problem...if
the field is blank it's counting it as zero and lowering the
results.
It
figured 79% when it should have been 94%. 94% was returned using
the
simple
average formula. I'm guessing I need to nest something to not count
nulls?
Help!!!

Hi There!

I Need your help again.

I have This

John VS 100
Mike VD -100
Mike VS 100
John VS 100
John VD -100
John S 0

I would like to compute the score of John, for him only

This is the Formula : ( VS + ( VD )) / Total number of Surveys

So its like this

(200 + ( -100 )) / 4


Thanks,

Hijosdelongi



"T. Valko" wrote:

I have a question for Excel 2003
=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Da ta!$C:$C,""))

You can't use entire columns as range references in array formulas in Excel
2003. Use a smaller specific range.

Try it like this (array entered**)

=AVERAGE(IF((Data!A1:A10=B1)*(Data!B1:B10=A2),Data !C1:C10))

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the SHIFT
key then hit ENTER.

--
Biff
Microsoft Excel MVP


"Hijosdelongi" wrote in message
...
Hi,

I have a question for Excel 2003

=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Dat a!$C:$C,""))

Im trying to get the AVERAGE of this and its giving me a #VALUE! error..
$A2
is the name that is suppose to be equal in the Data! worksheet and B$1 is
the
date that is suppose to be equal in the Data! worksheet. Im trying to use
AND
in IF for me to have two logical test..

Can you help me with this?

Thank you so much!



"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average.
Problem...if
the field is blank it's counting it as zero and lowering the results.
It
figured 79% when it should have been 94%. 94% was returned using the
simple
average formula. I'm guessing I need to nest something to not count
nulls?
Help!!!

Try this...

=SUMPRODUCT(--(A2:A7="John"),--(ISNUMBER(MATCH(B2:B7,{"VS","VD"},0))),C2:C7)/COUNTIF(A2:A7,"John")

Better to use cells to hold the criteria.

E2 = John
F2 = VS
G2 = VD

=SUMPRODUCT(--(A2:A7=E2),--(ISNUMBER(MATCH(B2:B7,F2:G2,0))),C2:C7)/COUNTIF(A2:A7,E2)

--
Biff
Microsoft Excel MVP


"Hijosdelongi" wrote in message
...
Hi There!

I Need your help again.

I have This

John VS 100
Mike VD -100
Mike VS 100
John VS 100
John VD -100
John S 0

I would like to compute the score of John, for him only

This is the Formula : ( VS + ( VD )) / Total number of Surveys

So its like this

(200 + ( -100 )) / 4


Thanks,

Hijosdelongi



"T. Valko" wrote:

I have a question for Excel 2003
=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Da ta!$C:$C,""))

You can't use entire columns as range references in array formulas in
Excel
2003. Use a smaller specific range.

Try it like this (array entered**)

=AVERAGE(IF((Data!A1:A10=B1)*(Data!B1:B10=A2),Data !C1:C10))

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the
SHIFT
key then hit ENTER.

--
Biff
Microsoft Excel MVP


"Hijosdelongi" wrote in message
...
Hi,

I have a question for Excel 2003

=AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Dat a!$C:$C,""))

Im trying to get the AVERAGE of this and its giving me a #VALUE!
error..
$A2
is the name that is suppose to be equal in the Data! worksheet and B$1
is
the
date that is suppose to be equal in the Data! worksheet. Im trying to
use
AND
in IF for me to have two logical test..

Can you help me with this?

Thank you so much!



"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average.
Problem...if
the field is blank it's counting it as zero and lowering the
results.
It
figured 79% when it should have been 94%. 94% was returned using
the
simple
average formula. I'm guessing I need to nest something to not count
nulls?
Help!!!

My situation is similar but I haven't been able to customize this to work
like I thought I should be able to.
I have one cell in multiple tabs I that want to include in the average, as
long as they <0. If anyone of them <0, then I do not want that particular
cell to be factored into the result because it skews the average (because
it's a month that hasn't occured yet so the data is 0). Here's my
(nonworking) formula if anyone can help:

=average(if(jundata!b2,juldata!b2,augdata!b2,sepda ta!b2,octdata!b2,novdata!b2,decdatab2<""),jundata !b2,juldata!b2,augdata!b2,sepdata!b2,octdata!b2,no vdata!b2,decdata!b2)


"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average. Problem...if
the field is blank it's counting it as zero and lowering the results. It
figured 79% when it should have been 94%. 94% was returned using the simple
average formula. I'm guessing I need to nest something to not count nulls?
Help!!!

Will there ever be any negative numbers?

--
Biff
Microsoft Excel MVP


"klic33" wrote in message
...
My situation is similar but I haven't been able to customize this to work
like I thought I should be able to.
I have one cell in multiple tabs I that want to include in the average, as
long as they <0. If anyone of them <0, then I do not want that
particular
cell to be factored into the result because it skews the average (because
it's a month that hasn't occured yet so the data is 0). Here's my
(nonworking) formula if anyone can help:

=average(if(jundata!b2,juldata!b2,augdata!b2,sepda ta!b2,octdata!b2,novdata!b2,decdatab2<""),jundata !b2,juldata!b2,augdata!b2,sepdata!b2,octdata!b2,no vdata!b2,decdata!b2)


"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average.
Problem...if
the field is blank it's counting it as zero and lowering the results.
It
figured 79% when it should have been 94%. 94% was returned using the
simple
average formula. I'm guessing I need to nest something to not count
nulls?
Help!!!

no, nothing less than zero

"T. Valko" wrote:

Will there ever be any negative numbers?

--
Biff
Microsoft Excel MVP


"klic33" wrote in message
...
My situation is similar but I haven't been able to customize this to work
like I thought I should be able to.
I have one cell in multiple tabs I that want to include in the average, as
long as they <0. If anyone of them <0, then I do not want that
particular
cell to be factored into the result because it skews the average (because
it's a month that hasn't occured yet so the data is 0). Here's my
(nonworking) formula if anyone can help:

=average(if(jundata!b2,juldata!b2,augdata!b2,sepda ta!b2,octdata!b2,novdata!b2,decdatab2<""),jundata !b2,juldata!b2,augdata!b2,sepdata!b2,octdata!b2,no vdata!b2,decdata!b2)


"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average.
Problem...if
the field is blank it's counting it as zero and lowering the results.
It
figured 79% when it should have been 94%. 94% was returned using the
simple
average formula. I'm guessing I need to nest something to not count
nulls?
Help!!!

Try this:

Create these named formulas...

InsertNameDefine
Name: SumSheets
Refers to:

=SUMIF(INDIRECT(TEXT(30*{6,7,8,9,10,11,12},"mmm\da ta")&"!B2"),"0")

Name: CountSheets
Refers to:

=COUNTIF(INDIRECT(TEXT(30*{6,7,8,9,10,11,12},"mmm\ data")&"!B2"),"0")

Then, you average formula is:

=SUMPRODUCT(SumSheets)/SUMPRODUCT(CountSheets)

Explanation:

Excel doesn't support *conditional* averaging across multiple sheets so we
need to trick it into doing so. We can't use the AVERAGE function in this
case. Since an average is the sum divided by the count that's what we're
doing with the above formula(s).

If you want to take the "easy" way out on this, on each sheet in the same
cell enter a formula like this:

=IF(B20,B2,"")

Let's assume those formulas are in cell B3. Then, you can use the AVAERAGE
function like this:

=AVERAGE(jundata:decdata!B3)

--
Biff
Microsoft Excel MVP


"klic33" wrote in message
...
no, nothing less than zero

"T. Valko" wrote:

Will there ever be any negative numbers?

--
Biff
Microsoft Excel MVP


"klic33" wrote in message
...
My situation is similar but I haven't been able to customize this to
work
like I thought I should be able to.
I have one cell in multiple tabs I that want to include in the average,
as
long as they <0. If anyone of them <0, then I do not want that
particular
cell to be factored into the result because it skews the average
(because
it's a month that hasn't occured yet so the data is 0). Here's my
(nonworking) formula if anyone can help:

=average(if(jundata!b2,juldata!b2,augdata!b2,sepda ta!b2,octdata!b2,novdata!b2,decdatab2<""),jundata !b2,juldata!b2,augdata!b2,sepdata!b2,octdata!b2,no vdata!b2,decdata!b2)


"JE McGimpsey" wrote:

One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45))

In article ,
"Spottkitty" wrote:

=AVERAGE(IF($A$3:$A$45="Photo",H3:H45))

This is the array I'm using to try to determine an average.
Problem...if
the field is blank it's counting it as zero and lowering the
results.
It
figured 79% when it should have been 94%. 94% was returned using
the
simple
average formula. I'm guessing I need to nest something to not count
nulls?
Help!!!

Hi Spottkitty,

Yes, you can use the AVERAGEIF function to exclude blank cells from the calculation. Here's how you can modify your formula:

1. =AVERAGEIF($A$3:$A$45,"Photo",H3:H45)

This formula will only average the values in the range H3:H45 if the corresponding cell in column A contains the text "Photo". Any blank cells in the range will be excluded from the calculation.