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Default Complex Count formula

Correction. The original formula with the SIGN function included was from
Biff, not from Jacob.
--
David Biddulph

"David Biddulph" <groups [at] biddulph.org.uk wrote in message
...
You've left out the SIGN function which Jacob had in his original formula,
and which I think he intended to be in the new one (and which I included
in mine).
--
David Biddulph

"GoBucks" wrote in message
...
thank you Jacob. I tried the formula and result I recv'd was 7 when I was
looking for 6. There are 3 rows in Column B that match (=3, <=3.9) and 4
rows in Column C that match (=0). But overall, there are 6 rows total
that
match the entire criteria. I can't seem to figure this one out.

"Jacob Skaria" wrote:

Add one more condition as

=SUMPRODUCT((B2:B11=3)*(B2:B11<=3.9)+(C2:C11=0))

If this post helps click Yes
---------------
Jacob Skaria


"GoBucks" wrote:

Sorry edit to to previous post:

How would you write the formula if the criteria for
column B is =3 and <=3.9 along with column C=0??

"GoBucks" wrote:

Thank you for the help!! How would you write the formula if the
criteria for
column B is =3 and <-3.9 along with column C=0??

"T. Valko" wrote:

I assume the "-" means the cell is empty?

=SUMPRODUCT(SIGN((B2:B11=3)+(C2:C11=0)))

I don't see a single 0 in
--
Biff
Microsoft Excel MVP


"GoBucks" wrote:

I am looking to get a formula that count the number of rows that
match some
criteria. The sample table is listed below. I would to have a
formula
calculate the # of rows in which values in column B =3 along
with values in
Column C = 0

ID RATING AMOUNT formula match
00304 4.0 (5.0) x
00299 2.5 - x
00069 2.5 2.0
01380 4.0 - x
01729 3.0 - x
01783 2.5 - x
01934 2.0 (1.0)
01901 3.8 (1.0) x
01482 3.0 (1.0) x
02076 2.5 (1.0)

COUNT 5 3 7


B=3 = 5 rows
C=0 = 3 rows

But if you combine both criteria, there are 7 rows that match. I
'm having a
difficult time figuring our how to write the formula for this.
Any
suggestions will be much appreciated.





 
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