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-   -   Formula For Finding a Quotation Mark In a String (https://www.excelbanter.com/excel-worksheet-functions/233938-formula-finding-quotation-mark-string.html)

Tiziano

Formula For Finding a Quotation Mark In a String
 
I have a bunch of part numbers in Col. A formatted as Text.
Some of these part numbers include a quotation mark (") to signify
diameter in inches.

For instance: 1411-04-RD 1/4" Red Nylon Tubing

What I want to do is write a formula that locates all those parts that
have the quotation mark in their string.

So, I wrote the following (which obviously does not work!!):

=if(find("""",a2), do something, do something else)

I think that my problem is the triple quotation marks in the formula,
but I don't know how to get around it.

Thanks for your suggestions.
--
tb

Fred Smith[_4_]

Formula For Finding a Quotation Mark In a String
 
Try it this way:
=if(isnumber(find("""",a2)), do something, do something else)

Regards,
Fred

"Tiziano" wrote in message
...
I have a bunch of part numbers in Col. A formatted as Text.
Some of these part numbers include a quotation mark (") to signify
diameter in inches.

For instance: 1411-04-RD 1/4" Red Nylon Tubing

What I want to do is write a formula that locates all those parts that
have the quotation mark in their string.

So, I wrote the following (which obviously does not work!!):

=if(find("""",a2), do something, do something else)

I think that my problem is the triple quotation marks in the formula, but
I don't know how to get around it.

Thanks for your suggestions.
--
tb



T. Valko

Formula For Finding a Quotation Mark In a String
 
This might help reduce the confusion.

Assuming it's a double quote and not 2 single quotes.

=IF(COUNT(FIND(CHAR(34),A2)),"Yes","No")

CHAR(34) = " (double quote)

--
Biff
Microsoft Excel MVP


"Tiziano" wrote in message
...
I have a bunch of part numbers in Col. A formatted as Text.
Some of these part numbers include a quotation mark (") to signify
diameter in inches.

For instance: 1411-04-RD 1/4" Red Nylon Tubing

What I want to do is write a formula that locates all those parts that
have the quotation mark in their string.

So, I wrote the following (which obviously does not work!!):

=if(find("""",a2), do something, do something else)

I think that my problem is the triple quotation marks in the formula, but
I don't know how to get around it.

Thanks for your suggestions.
--
tb





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