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Hello,
Is there a formula which could answer the following? Monthly deduction is $1,500 in January of 2009 and drops by $15 per month. What are the totals for 2009, 2010 and 2011? Thanks in advance for the help. |
#2
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Hi,
Try this formula for 2009. C5 has 1,500 and C6 has 15. In D5:D7, enter 2009, 2010 and 2011. In E5, enter =SUMPRODUCT((C5-(C6*{0,1,2,3,4,5,6,7,8,9,10,11}))). In E6, enter =SUMPRODUCT((($C$5-(11*$C$6*(D6-$D$5)))-($C$6*{0,1,2,3,4,5,6,7,8,9,10,11}))). You can now copy this down to cell E7 -- Regards, Ashish Mathur Microsoft Excel MVP www.ashishmathur.com "JV" wrote in message ... Hello, Is there a formula which could answer the following? Monthly deduction is $1,500 in January of 2009 and drops by $15 per month. What are the totals for 2009, 2010 and 2011? Thanks in advance for the help. |
#3
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"JV" wrote:
Is there a formula which could answer the following? Monthly deduction is $1,500 in January of 2009 and drops by $15 per month. What are the totals for 2009, 2010 and 2011? Put the following formula into B1 and copy down through B3: =SUMPRODUCT(1500-12*15*(ROW(1:1)-1)-15*(ROW($1:$12)-1)) Alternatively, you can remove the constants as follows: =12*(1500-12*15*(ROW(1:1)-1))-15*SUMPRODUCT(ROW($1:$12)-1) Caveat: The use of ROW(1:1) makes it difficult to move and insert cells. If that's a concern, you could put 2009, 2010 and 2011 into A1:A3, and enter one of the following formula into B1 and copy down: =SUMPRODUCT(1500-12*15*(A1-$A$1)-15*(ROW($1:$12)-1)) =12*(1500-12*15*(A1-$A$1))-15*SUMPRODUCT(ROW($1:$12)-1) |
#4
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w/o using SUMPRODUCT and using formula for sum of arithmetic
progression you might use the following: A1=100000 A2=1500 A3=15 A4=12 (or number of months generally) =A4*(2*(A1-A2)-(A4-1)*A3)/2 HIH On 7 Maj, 07:56, JV wrote: Hello, Is there a formula which could answer the following? Monthly deduction is $1,500 in January of 2009 and drops by $15 per month.. * What are the totals for 2009, 2010 and 2011? Thanks in advance for the help. |
#5
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Hi. If I am not mistaken,
= 19170 - 2160*yr where yr is 1, 2, or 3...etc Returns: {17010, 14850, 12690...} = = = = HTH Dana DeLouis JV wrote: Hello, Is there a formula which could answer the following? Monthly deduction is $1,500 in January of 2009 and drops by $15 per month. What are the totals for 2009, 2010 and 2011? Thanks in advance for the help. |
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