I know COUNTIF isn't the right function because I know it cannot use logic
operators. Here's what I am trying to accomplish:

Col A Col B
A 5
B 6
C 3
A 3
A
B 7

The question is, how many numbers in Column B correspond to EITHER A or C?

Recommendations?

See if this works for you:

=SUMPRODUCT((A1:A6="A")+(A1:A6="C"),--(ISNUMBER(B1:B6)))

HTH
Elkar


"Janie" wrote:

I know COUNTIF isn't the right function because I know it cannot use logic
operators. Here's what I am trying to accomplish:

Col A Col B
A 5
B 6
C 3
A 3
A
B 7

The question is, how many numbers in Column B correspond to EITHER A or C?

Recommendations?

I depends on what you mean by "correspond to". Regardless, an "or" condition
involves simple addition. Try:

To count the occurrences:
=countif(a:a,"A")+countif(a:a,"C")

To sum column B if:
=sumif(a:a,"A",b:b)+sumif(a:a,"C",b:b)

Regards,
Fred.

"Janie" wrote in message
...
I know COUNTIF isn't the right function because I know it cannot use logic
operators. Here's what I am trying to accomplish:

Col A Col B
A 5
B 6
C 3
A 3
A
B 7

The question is, how many numbers in Column B correspond to EITHER A or C?

Recommendations?

try this after changing columns to suit
=SUMPRODUCT((H2:H22={"a","b"})*(I2:I220))

--
Don Guillett
Microsoft MVP Excel
SalesAid Software

"Janie" wrote in message
...
I know COUNTIF isn't the right function because I know it cannot use logic
operators. Here's what I am trying to accomplish:

Col A Col B
A 5
B 6
C 3
A 3
A
B 7

The question is, how many numbers in Column B correspond to EITHER A or C?

Recommendations?

=SUM(SUMIF(A1:A10,{"A","B"},B1:B9))

--
HTH

Bob

(there's no email, no snail mail, but somewhere should be gmail in my addy)

"Janie" wrote in message
...
I know COUNTIF isn't the right function because I know it cannot use logic
operators. Here's what I am trying to accomplish:

Col A Col B
A 5
B 6
C 3
A 3
A
B 7

The question is, how many numbers in Column B correspond to EITHER A or C?

Recommendations?