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#1
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i have tried =countif(a1:a31,"=passmark") where passmark is a named cell. It
doesn't work... please help! |
#2
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What exactly are you trying to do.
This works fine: =countif(a1:a31,passmark) Unless you are trying to also use an equation with passmark. Paul "boofybrunt" wrote in message ... i have tried =countif(a1:a31,"=passmark") where passmark is a named cell. It doesn't work... please help! |
#3
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I have results in column A. I want to count the number of results that are
equal to or greater than a variable whose value is contained in a named cell (named: passmark) "PCLIVE" wrote: What exactly are you trying to do. This works fine: =countif(a1:a31,passmark) Unless you are trying to also use an equation with passmark. Paul "boofybrunt" wrote in message ... i have tried =countif(a1:a31,"=passmark") where passmark is a named cell. It doesn't work... please help! |
#4
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Try:
=COUNTIF(A1:A31,"="&passmark) HTH Jason Atlanta, GA -----Original Message----- i have tried =countif(a1:a31,"=passmark") where passmark is a named cell. It doesn't work... please help! . |
#5
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=countif(a1:a31,"="&passmark)
"boofybrunt" wrote: i have tried =countif(a1:a31,"=passmark") where passmark is a named cell. It doesn't work... please help! |
#6
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cheers... it works. tried it once and it didn't..... Tried it again and it
did!?? "Duke Carey" wrote: =countif(a1:a31,"="&passmark) "boofybrunt" wrote: i have tried =countif(a1:a31,"=passmark") where passmark is a named cell. It doesn't work... please help! |
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