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Thank you very much - this solution worked perfectly!
Happy New Year! "Gary''s Student" wrote: For example: =LOOKUP(A1,{7,8,9,10,11,12;"1/4","1/2","2/3","1","1 and 1/4","1 and 1/2"}) so if A1 contains 12 ( or 12.00) then the formula displays: 1 and 1/2 -- Gary''s Student - gsnu200823 "Lawrence" wrote: Have column with dollar values that correspond to fractions representing thickness of materials (ie cell shows $7.00 - which is the cost of 1/4" material) I want to create another column which will parse the cell with the dollar value and enter the corresponding fractional value for material thickness based on the 6 different cost values that could be in the cell and the related fraction that I want to be populated in the cell of the new column. How do I create this formula? |
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