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Good morning all. I'm currently working on a attendance tracker, I have a
formula that will give us either half or full occurrence. Before we didnt
need to track 0 but now we have. I tried to change the formula to give us a
full occurrence (1) but Im getting an error. Can anyone help me with this€¦
Thanks

=(COUNTIF(L9:BF9,"0")-COUNTIF(L9:BF9,"=5"))+((COUNTIF(L9:BF9,"=5")-COUNTIF(L9:BF9,"=8"))/2)


--
Regards
YM

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Yitzhack,

Could you give me the example data? L9:BF9
Secondly, what is it that you would like to happen? Would you just like to
include 0 into the formula? You could change that with "=0" in the first
COUNTIF. I could be mistaken. In all essence, what would you like the
formula to return?

--
--Thomas [PBD]
Working hard to make working easy.
Answered your question? Click ''Yes'' below.


"Yitzhack" wrote:

Good morning all. I'm currently working on a attendance tracker, I have a
formula that will give us either half or full occurrence. Before we didnt
need to track 0 but now we have. I tried to change the formula to give us a
full occurrence (1) but Im getting an error. Can anyone help me with this€¦
Thanks

=(COUNTIF(L9:BF9,"0")-COUNTIF(L9:BF9,"=5"))+((COUNTIF(L9:BF9,"=5")-COUNTIF(L9:BF9,"=8"))/2)


--
Regards
YM

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Posts: 28
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what it needds to return is if 0 = 1 the current formula returns if then 5
= .5.
BAsicaly what i need is if L9 is 0 = 1 if is than 0 but< than5 = 1 if than
5 but <than 8 = .05.
If you miss up to 3 hours out of 8 = .05
if you miss full day = 1
If you miss more than 3 = 1
--
Regards
YM



"Thomas [PBD]" wrote:

Yitzhack,

Could you give me the example data? L9:BF9
Secondly, what is it that you would like to happen? Would you just like to
include 0 into the formula? You could change that with "=0" in the first
COUNTIF. I could be mistaken. In all essence, what would you like the
formula to return?

--
--Thomas [PBD]
Working hard to make working easy.
Answered your question? Click ''Yes'' below.


"Yitzhack" wrote:

Good morning all. I'm currently working on a attendance tracker, I have a
formula that will give us either half or full occurrence. Before we didnt
need to track 0 but now we have. I tried to change the formula to give us a
full occurrence (1) but Im getting an error. Can anyone help me with this€¦
Thanks

=(COUNTIF(L9:BF9,"0")-COUNTIF(L9:BF9,"=5"))+((COUNTIF(L9:BF9,"=5")-COUNTIF(L9:BF9,"=8"))/2)


--
Regards
YM

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Also, I'm not sure if this is even posible but we have some "part-timers"
that work different hours,
mon and wed 11 to 5 (6), and tues, thurs, and fri 8 to 5. (8)
mon and wed 8 to 5 (8), tues and thurs 2 to 5 (3), and fri 1 to 5 (4)

--
Regards
YM



"Yitzhack" wrote:

what it needds to return is if 0 = 1 the current formula returns if then 5
= .5.
BAsicaly what i need is if L9 is 0 = 1 if is than 0 but< than5 = 1 if than
5 but <than 8 = .05.
If you miss up to 3 hours out of 8 = .05
if you miss full day = 1
If you miss more than 3 = 1
--
Regards
YM



"Thomas [PBD]" wrote:

Yitzhack,

Could you give me the example data? L9:BF9
Secondly, what is it that you would like to happen? Would you just like to
include 0 into the formula? You could change that with "=0" in the first
COUNTIF. I could be mistaken. In all essence, what would you like the
formula to return?

--
--Thomas [PBD]
Working hard to make working easy.
Answered your question? Click ''Yes'' below.


"Yitzhack" wrote:

Good morning all. I'm currently working on a attendance tracker, I have a
formula that will give us either half or full occurrence. Before we didnt
need to track 0 but now we have. I tried to change the formula to give us a
full occurrence (1) but Im getting an error. Can anyone help me with this€¦
Thanks

=(COUNTIF(L9:BF9,"0")-COUNTIF(L9:BF9,"=5"))+((COUNTIF(L9:BF9,"=5")-COUNTIF(L9:BF9,"=8"))/2)


--
Regards
YM

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Posts: 28
Default Help

Mon Tue Wed Thu Fri
8 8 2 0 0
=(COUNTIF(L11:BF11,"0")-COUNTIF(L11:BF11,"=5"))+((COUNTIF(L11:BF11,"=5")-COUNTIF(L11:BF11,"=8"))/2)

The formula returs 1 But now i need to return 0
Regards
YM



"Yitzhack" wrote:

what it needds to return is if 0 = 1 the current formula returns if then 5
= .5.
BAsicaly what i need is if L9 is 0 = 1 if is than 0 but< than5 = 1 if than
5 but <than 8 = .05.
If you miss up to 3 hours out of 8 = .05
if you miss full day = 1
If you miss more than 3 = 1
--
Regards
YM



"Thomas [PBD]" wrote:

Yitzhack,

Could you give me the example data? L9:BF9
Secondly, what is it that you would like to happen? Would you just like to
include 0 into the formula? You could change that with "=0" in the first
COUNTIF. I could be mistaken. In all essence, what would you like the
formula to return?

--
--Thomas [PBD]
Working hard to make working easy.
Answered your question? Click ''Yes'' below.


"Yitzhack" wrote:

Good morning all. I'm currently working on a attendance tracker, I have a
formula that will give us either half or full occurrence. Before we didnt
need to track 0 but now we have. I tried to change the formula to give us a
full occurrence (1) but Im getting an error. Can anyone help me with this€¦
Thanks

=(COUNTIF(L9:BF9,"0")-COUNTIF(L9:BF9,"=5"))+((COUNTIF(L9:BF9,"=5")-COUNTIF(L9:BF9,"=8"))/2)


--
Regards
YM



  #6   Report Post  
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Posts: 154
Default Help

Yitzhack,

Ok, seems like I have what you need. I think.

Basic Parameters:
<cell=0 then 1
<cell0 and <5 then 1
<cell=5 and <8 then .5
<cell=8 then 0

=SUMPRODUCT(--((L9:BF9)=0),--((L9:BF9)<""))+SUMPRODUCT(--((L9:BF9)0),--((L9:BF9<5)))+(SUMPRODUCT(--((L9:BF9)=5),--((L9:BF9)<8))*0.5)

--
--Thomas [PBD]
Working hard to make working easy.
Answered your question? Click ''Yes'' below.


"Yitzhack" wrote:

what it needds to return is if 0 = 1 the current formula returns if then 5
= .5.
BAsicaly what i need is if L9 is 0 = 1 if is than 0 but< than5 = 1 if than
5 but <than 8 = .05.
If you miss up to 3 hours out of 8 = .05
if you miss full day = 1
If you miss more than 3 = 1
--
Regards
YM



"Thomas [PBD]" wrote:

Yitzhack,

Could you give me the example data? L9:BF9
Secondly, what is it that you would like to happen? Would you just like to
include 0 into the formula? You could change that with "=0" in the first
COUNTIF. I could be mistaken. In all essence, what would you like the
formula to return?

--
--Thomas [PBD]
Working hard to make working easy.
Answered your question? Click ''Yes'' below.


"Yitzhack" wrote:

Good morning all. I'm currently working on a attendance tracker, I have a
formula that will give us either half or full occurrence. Before we didnt
need to track 0 but now we have. I tried to change the formula to give us a
full occurrence (1) but Im getting an error. Can anyone help me with this€¦
Thanks

=(COUNTIF(L9:BF9,"0")-COUNTIF(L9:BF9,"=5"))+((COUNTIF(L9:BF9,"=5")-COUNTIF(L9:BF9,"=8"))/2)


--
Regards
YM

  #7   Report Post  
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Posts: 28
Default Help

Thomas, Thank you so much. This is definetely what i needed.. Do you think
that the formula for the "part-timers" is something doable?

Thanks again


Regards
YM



"Thomas [PBD]" wrote:

Yitzhack,

Ok, seems like I have what you need. I think.

Basic Parameters:
<cell=0 then 1
<cell0 and <5 then 1
<cell=5 and <8 then .5
<cell=8 then 0

=SUMPRODUCT(--((L9:BF9)=0),--((L9:BF9)<""))+SUMPRODUCT(--((L9:BF9)0),--((L9:BF9<5)))+(SUMPRODUCT(--((L9:BF9)=5),--((L9:BF9)<8))*0.5)

--
--Thomas [PBD]
Working hard to make working easy.
Answered your question? Click ''Yes'' below.


"Yitzhack" wrote:

what it needds to return is if 0 = 1 the current formula returns if then 5
= .5.
BAsicaly what i need is if L9 is 0 = 1 if is than 0 but< than5 = 1 if than
5 but <than 8 = .05.
If you miss up to 3 hours out of 8 = .05
if you miss full day = 1
If you miss more than 3 = 1
--
Regards
YM



"Thomas [PBD]" wrote:

Yitzhack,

Could you give me the example data? L9:BF9
Secondly, what is it that you would like to happen? Would you just like to
include 0 into the formula? You could change that with "=0" in the first
COUNTIF. I could be mistaken. In all essence, what would you like the
formula to return?

--
--Thomas [PBD]
Working hard to make working easy.
Answered your question? Click ''Yes'' below.


"Yitzhack" wrote:

Good morning all. I'm currently working on a attendance tracker, I have a
formula that will give us either half or full occurrence. Before we didnt
need to track 0 but now we have. I tried to change the formula to give us a
full occurrence (1) but Im getting an error. Can anyone help me with this€¦
Thanks

=(COUNTIF(L9:BF9,"0")-COUNTIF(L9:BF9,"=5"))+((COUNTIF(L9:BF9,"=5")-COUNTIF(L9:BF9,"=8"))/2)


--
Regards
YM

  #8   Report Post  
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Posts: 154
Default Help

Yitzhack,

That would require you to know what columns the days were in. If you only
had 5 columns, it could be done, but with L:BF that makes it much more
difficult. Secondly, you would also have to have some logic into each
person, or a variable-based function. For the variable based function, you
would have to create a cell for each different criteria. For example: BG9
would have to contain Mondays normal total hours, BH9 Tuesdays normal total
hours, etc... as well as say AA9 to have your criteria to display half days,
say 3 hours or something. It's not IMPOSSIBLE, but much harder to do.

Another possibility would be to create another table for Normal total work
hours and half day hours and place a VLOOKUP against the person's name for
the number that you were looking for and change the coding as such:

=SUMPRODUCT(--((L9:BF9)=0),--((L9:BF9)<""))+SUMPRODUCT(--((L9:BF9)0),--((L9:BF9<VLOOKUP(name,table_array,column_number,FA LSE))))+(SUMPRODUCT(--((L9:BF9)=VLOOKUP(name,table_array,column_number, FALSE)),--((L9:BF9)<VLOOKUP(name,table_array,column_number,F ALSE)))*0.5)

This is very hard to accomplish correctly, but not impossible if you spend a
little time on it.

--
--Thomas [PBD]
Working hard to make working easy.
Answered your question? Click ''Yes'' below.


"Yitzhack" wrote:

Thomas, Thank you so much. This is definetely what i needed.. Do you think
that the formula for the "part-timers" is something doable?

Thanks again


Regards
YM



"Thomas [PBD]" wrote:

Yitzhack,

Ok, seems like I have what you need. I think.

Basic Parameters:
<cell=0 then 1
<cell0 and <5 then 1
<cell=5 and <8 then .5
<cell=8 then 0

=SUMPRODUCT(--((L9:BF9)=0),--((L9:BF9)<""))+SUMPRODUCT(--((L9:BF9)0),--((L9:BF9<5)))+(SUMPRODUCT(--((L9:BF9)=5),--((L9:BF9)<8))*0.5)

--
--Thomas [PBD]
Working hard to make working easy.
Answered your question? Click ''Yes'' below.


"Yitzhack" wrote:

what it needds to return is if 0 = 1 the current formula returns if then 5
= .5.
BAsicaly what i need is if L9 is 0 = 1 if is than 0 but< than5 = 1 if than
5 but <than 8 = .05.
If you miss up to 3 hours out of 8 = .05
if you miss full day = 1
If you miss more than 3 = 1
--
Regards
YM



"Thomas [PBD]" wrote:

Yitzhack,

Could you give me the example data? L9:BF9
Secondly, what is it that you would like to happen? Would you just like to
include 0 into the formula? You could change that with "=0" in the first
COUNTIF. I could be mistaken. In all essence, what would you like the
formula to return?

--
--Thomas [PBD]
Working hard to make working easy.
Answered your question? Click ''Yes'' below.


"Yitzhack" wrote:

Good morning all. I'm currently working on a attendance tracker, I have a
formula that will give us either half or full occurrence. Before we didnt
need to track 0 but now we have. I tried to change the formula to give us a
full occurrence (1) but Im getting an error. Can anyone help me with this€¦
Thanks

=(COUNTIF(L9:BF9,"0")-COUNTIF(L9:BF9,"=5"))+((COUNTIF(L9:BF9,"=5")-COUNTIF(L9:BF9,"=8"))/2)


--
Regards
YM

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Posts: 28
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Thomas, Thanks so much for your help.
--
Regards
YM



"Thomas [PBD]" wrote:

Yitzhack,

That would require you to know what columns the days were in. If you only
had 5 columns, it could be done, but with L:BF that makes it much more
difficult. Secondly, you would also have to have some logic into each
person, or a variable-based function. For the variable based function, you
would have to create a cell for each different criteria. For example: BG9
would have to contain Mondays normal total hours, BH9 Tuesdays normal total
hours, etc... as well as say AA9 to have your criteria to display half days,
say 3 hours or something. It's not IMPOSSIBLE, but much harder to do.

Another possibility would be to create another table for Normal total work
hours and half day hours and place a VLOOKUP against the person's name for
the number that you were looking for and change the coding as such:

=SUMPRODUCT(--((L9:BF9)=0),--((L9:BF9)<""))+SUMPRODUCT(--((L9:BF9)0),--((L9:BF9<VLOOKUP(name,table_array,column_number,FA LSE))))+(SUMPRODUCT(--((L9:BF9)=VLOOKUP(name,table_array,column_number, FALSE)),--((L9:BF9)<VLOOKUP(name,table_array,column_number,F ALSE)))*0.5)

This is very hard to accomplish correctly, but not impossible if you spend a
little time on it.

--
--Thomas [PBD]
Working hard to make working easy.
Answered your question? Click ''Yes'' below.


"Yitzhack" wrote:

Thomas, Thank you so much. This is definetely what i needed.. Do you think
that the formula for the "part-timers" is something doable?

Thanks again


Regards
YM



"Thomas [PBD]" wrote:

Yitzhack,

Ok, seems like I have what you need. I think.

Basic Parameters:
<cell=0 then 1
<cell0 and <5 then 1
<cell=5 and <8 then .5
<cell=8 then 0

=SUMPRODUCT(--((L9:BF9)=0),--((L9:BF9)<""))+SUMPRODUCT(--((L9:BF9)0),--((L9:BF9<5)))+(SUMPRODUCT(--((L9:BF9)=5),--((L9:BF9)<8))*0.5)

--
--Thomas [PBD]
Working hard to make working easy.
Answered your question? Click ''Yes'' below.


"Yitzhack" wrote:

what it needds to return is if 0 = 1 the current formula returns if then 5
= .5.
BAsicaly what i need is if L9 is 0 = 1 if is than 0 but< than5 = 1 if than
5 but <than 8 = .05.
If you miss up to 3 hours out of 8 = .05
if you miss full day = 1
If you miss more than 3 = 1
--
Regards
YM



"Thomas [PBD]" wrote:

Yitzhack,

Could you give me the example data? L9:BF9
Secondly, what is it that you would like to happen? Would you just like to
include 0 into the formula? You could change that with "=0" in the first
COUNTIF. I could be mistaken. In all essence, what would you like the
formula to return?

--
--Thomas [PBD]
Working hard to make working easy.
Answered your question? Click ''Yes'' below.


"Yitzhack" wrote:

Good morning all. I'm currently working on a attendance tracker, I have a
formula that will give us either half or full occurrence. Before we didnt
need to track 0 but now we have. I tried to change the formula to give us a
full occurrence (1) but Im getting an error. Can anyone help me with this€¦
Thanks

=(COUNTIF(L9:BF9,"0")-COUNTIF(L9:BF9,"=5"))+((COUNTIF(L9:BF9,"=5")-COUNTIF(L9:BF9,"=8"))/2)


--
Regards
YM

  #10   Report Post  
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Posts: 154
Default Help

Yitzhack,

You're welcome and thanks for the feedback.

--
--Thomas [PBD]
Working hard to make working easy.
Answered your question? Click ''Yes'' below.


"Yitzhack" wrote:

Thomas, Thanks so much for your help.
--
Regards
YM



"Thomas [PBD]" wrote:

Yitzhack,

That would require you to know what columns the days were in. If you only
had 5 columns, it could be done, but with L:BF that makes it much more
difficult. Secondly, you would also have to have some logic into each
person, or a variable-based function. For the variable based function, you
would have to create a cell for each different criteria. For example: BG9
would have to contain Mondays normal total hours, BH9 Tuesdays normal total
hours, etc... as well as say AA9 to have your criteria to display half days,
say 3 hours or something. It's not IMPOSSIBLE, but much harder to do.

Another possibility would be to create another table for Normal total work
hours and half day hours and place a VLOOKUP against the person's name for
the number that you were looking for and change the coding as such:

=SUMPRODUCT(--((L9:BF9)=0),--((L9:BF9)<""))+SUMPRODUCT(--((L9:BF9)0),--((L9:BF9<VLOOKUP(name,table_array,column_number,FA LSE))))+(SUMPRODUCT(--((L9:BF9)=VLOOKUP(name,table_array,column_number, FALSE)),--((L9:BF9)<VLOOKUP(name,table_array,column_number,F ALSE)))*0.5)

This is very hard to accomplish correctly, but not impossible if you spend a
little time on it.

--
--Thomas [PBD]
Working hard to make working easy.
Answered your question? Click ''Yes'' below.


"Yitzhack" wrote:

Thomas, Thank you so much. This is definetely what i needed.. Do you think
that the formula for the "part-timers" is something doable?

Thanks again


Regards
YM



"Thomas [PBD]" wrote:

Yitzhack,

Ok, seems like I have what you need. I think.

Basic Parameters:
<cell=0 then 1
<cell0 and <5 then 1
<cell=5 and <8 then .5
<cell=8 then 0

=SUMPRODUCT(--((L9:BF9)=0),--((L9:BF9)<""))+SUMPRODUCT(--((L9:BF9)0),--((L9:BF9<5)))+(SUMPRODUCT(--((L9:BF9)=5),--((L9:BF9)<8))*0.5)

--
--Thomas [PBD]
Working hard to make working easy.
Answered your question? Click ''Yes'' below.


"Yitzhack" wrote:

what it needds to return is if 0 = 1 the current formula returns if then 5
= .5.
BAsicaly what i need is if L9 is 0 = 1 if is than 0 but< than5 = 1 if than
5 but <than 8 = .05.
If you miss up to 3 hours out of 8 = .05
if you miss full day = 1
If you miss more than 3 = 1
--
Regards
YM



"Thomas [PBD]" wrote:

Yitzhack,

Could you give me the example data? L9:BF9
Secondly, what is it that you would like to happen? Would you just like to
include 0 into the formula? You could change that with "=0" in the first
COUNTIF. I could be mistaken. In all essence, what would you like the
formula to return?

--
--Thomas [PBD]
Working hard to make working easy.
Answered your question? Click ''Yes'' below.


"Yitzhack" wrote:

Good morning all. I'm currently working on a attendance tracker, I have a
formula that will give us either half or full occurrence. Before we didnt
need to track 0 but now we have. I tried to change the formula to give us a
full occurrence (1) but Im getting an error. Can anyone help me with this€¦
Thanks

=(COUNTIF(L9:BF9,"0")-COUNTIF(L9:BF9,"=5"))+((COUNTIF(L9:BF9,"=5")-COUNTIF(L9:BF9,"=8"))/2)


--
Regards
YM

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