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#1
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Using Windows XP and Office2003:
In column AJ we have a formula .... =CONCATENATE(A97;G97;H97) =CONCATENATE(A98;G98;H98) .... the result of this is either 14 or 15 characters (depending on the month of the year) in column AT we do a COUNTIF: .... =COUNTIF($AJ$83:$AJ$4916;AJ97) =COUNTIF($AJ$83:$AJ$4916;AJ98) since all of the values in the AJ column are unique, all of these formulas should have "1" as a result, however, the ones with a string in the AJ column of 15 characters give "3" as a result (conclusion: that's for months 10, 11 and 12 where the 0, 1 and 2 aren't recognized/counted). This would mean that only the first 14 characters are evaluated. I've tried several workarounds, but in itself these functions should work (or am I missing an elephant here). I've also seen questions about formulas that only work when they refer to cells with straight numbers instead of formulas, but even when I replace the 'concatenate' results with the resulting value of the cell, the result stays the same. For another formula on another sheet to work we need to have this error sorted out, and so far I haven't found what causes this. Can you point me in the right direction? |
#2
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=CONCATENATE(A97;G97;H97)
=CONCATENATE(A98;G98;H98) the result of this is either 14 or 15 characters (depending on the month of the year) Sounds like you're "building" date strings. Post some examples of the resulting strings from the above formulas. -- Biff Microsoft Excel MVP "JusMe" wrote in message ... Using Windows XP and Office2003: In column AJ we have a formula ... =CONCATENATE(A97;G97;H97) =CONCATENATE(A98;G98;H98) ... the result of this is either 14 or 15 characters (depending on the month of the year) in column AT we do a COUNTIF: ... =COUNTIF($AJ$83:$AJ$4916;AJ97) =COUNTIF($AJ$83:$AJ$4916;AJ98) since all of the values in the AJ column are unique, all of these formulas should have "1" as a result, however, the ones with a string in the AJ column of 15 characters give "3" as a result (conclusion: that's for months 10, 11 and 12 where the 0, 1 and 2 aren't recognized/counted). This would mean that only the first 14 characters are evaluated. I've tried several workarounds, but in itself these functions should work (or am I missing an elephant here). I've also seen questions about formulas that only work when they refer to cells with straight numbers instead of formulas, but even when I replace the 'concatenate' results with the resulting value of the cell, the result stays the same. For another formula on another sheet to work we need to have this error sorted out, and so far I haven't found what causes this. Can you point me in the right direction? |
#3
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the result is a string of numbers .... like these:
50000356020079 500003560200710 the 'countif' one works with the first one, and doesn't seem to work with the second one "T. Valko" wrote: =CONCATENATE(A97;G97;H97) =CONCATENATE(A98;G98;H98) the result of this is either 14 or 15 characters (depending on the month of the year) Sounds like you're "building" date strings. Post some examples of the resulting strings from the above formulas. -- Biff Microsoft Excel MVP "JusMe" wrote in message ... Using Windows XP and Office2003: In column AJ we have a formula ... =CONCATENATE(A97;G97;H97) =CONCATENATE(A98;G98;H98) ... the result of this is either 14 or 15 characters (depending on the month of the year) in column AT we do a COUNTIF: ... =COUNTIF($AJ$83:$AJ$4916;AJ97) =COUNTIF($AJ$83:$AJ$4916;AJ98) since all of the values in the AJ column are unique, all of these formulas should have "1" as a result, however, the ones with a string in the AJ column of 15 characters give "3" as a result (conclusion: that's for months 10, 11 and 12 where the 0, 1 and 2 aren't recognized/counted). This would mean that only the first 14 characters are evaluated. I've tried several workarounds, but in itself these functions should work (or am I missing an elephant here). I've also seen questions about formulas that only work when they refer to cells with straight numbers instead of formulas, but even when I replace the 'concatenate' results with the resulting value of the cell, the result stays the same. For another formula on another sheet to work we need to have this error sorted out, and so far I haven't found what causes this. Can you point me in the right direction? |
#4
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Could it be since your strings are all numbers, that there are just too many
'significant' numbers for xl to deal with? -- John C "JusMe" wrote: the result is a string of numbers .... like these: 50000356020079 500003560200710 the 'countif' one works with the first one, and doesn't seem to work with the second one "T. Valko" wrote: =CONCATENATE(A97;G97;H97) =CONCATENATE(A98;G98;H98) the result of this is either 14 or 15 characters (depending on the month of the year) Sounds like you're "building" date strings. Post some examples of the resulting strings from the above formulas. -- Biff Microsoft Excel MVP "JusMe" wrote in message ... Using Windows XP and Office2003: In column AJ we have a formula ... =CONCATENATE(A97;G97;H97) =CONCATENATE(A98;G98;H98) ... the result of this is either 14 or 15 characters (depending on the month of the year) in column AT we do a COUNTIF: ... =COUNTIF($AJ$83:$AJ$4916;AJ97) =COUNTIF($AJ$83:$AJ$4916;AJ98) since all of the values in the AJ column are unique, all of these formulas should have "1" as a result, however, the ones with a string in the AJ column of 15 characters give "3" as a result (conclusion: that's for months 10, 11 and 12 where the 0, 1 and 2 aren't recognized/counted). This would mean that only the first 14 characters are evaluated. I've tried several workarounds, but in itself these functions should work (or am I missing an elephant here). I've also seen questions about formulas that only work when they refer to cells with straight numbers instead of formulas, but even when I replace the 'concatenate' results with the resulting value of the cell, the result stays the same. For another formula on another sheet to work we need to have this error sorted out, and so far I haven't found what causes this. Can you point me in the right direction? |
#5
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Try using SUMPRODUCT.
CONCATENATE returns a text value *but* COUNTIF evalauates text numbers and numeric numbers as being equal. That's probably why it's truncating the last digit since Excel will only evaluate to 15 significant digits. You will probably have to format your range $AJ$83:$AJ$4916 as TEXT if it isn't already. =SUMPRODUCT(--($AJ$83:$AJ$4916=AJ97)) -- Biff Microsoft Excel MVP "John C" <johnc@stateofdenial wrote in message ... Could it be since your strings are all numbers, that there are just too many 'significant' numbers for xl to deal with? -- John C "JusMe" wrote: the result is a string of numbers .... like these: 50000356020079 500003560200710 the 'countif' one works with the first one, and doesn't seem to work with the second one "T. Valko" wrote: =CONCATENATE(A97;G97;H97) =CONCATENATE(A98;G98;H98) the result of this is either 14 or 15 characters (depending on the month of the year) Sounds like you're "building" date strings. Post some examples of the resulting strings from the above formulas. -- Biff Microsoft Excel MVP "JusMe" wrote in message ... Using Windows XP and Office2003: In column AJ we have a formula ... =CONCATENATE(A97;G97;H97) =CONCATENATE(A98;G98;H98) ... the result of this is either 14 or 15 characters (depending on the month of the year) in column AT we do a COUNTIF: ... =COUNTIF($AJ$83:$AJ$4916;AJ97) =COUNTIF($AJ$83:$AJ$4916;AJ98) since all of the values in the AJ column are unique, all of these formulas should have "1" as a result, however, the ones with a string in the AJ column of 15 characters give "3" as a result (conclusion: that's for months 10, 11 and 12 where the 0, 1 and 2 aren't recognized/counted). This would mean that only the first 14 characters are evaluated. I've tried several workarounds, but in itself these functions should work (or am I missing an elephant here). I've also seen questions about formulas that only work when they refer to cells with straight numbers instead of formulas, but even when I replace the 'concatenate' results with the resulting value of the cell, the result stays the same. For another formula on another sheet to work we need to have this error sorted out, and so far I haven't found what causes this. Can you point me in the right direction? |
#6
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Thank you for this one. The SUMPRODUCT works like a charm.
Any chance of a similar solution for a SUMIF? The second problem in this sheet is one with SUMIF, and it also triples values by three, so it's a similar problem. To be complete I'll add the formula: =SUMIF('SHEETA'!AJ:AJ;D47;'SHEETA'!AL:AL) where in SHEETA AJ is the column with the CONCENATE values that needs to find a match with column D and AL is the sales for that month for that combination in AJ/D.... I'll go check these forums again for this one right now .... Thank you again. "T. Valko" wrote: Try using SUMPRODUCT. CONCATENATE returns a text value *but* COUNTIF evalauates text numbers and numeric numbers as being equal. That's probably why it's truncating the last digit since Excel will only evaluate to 15 significant digits. You will probably have to format your range $AJ$83:$AJ$4916 as TEXT if it isn't already. =SUMPRODUCT(--($AJ$83:$AJ$4916=AJ97)) -- Biff Microsoft Excel MVP "John C" <johnc@stateofdenial wrote in message ... Could it be since your strings are all numbers, that there are just too many 'significant' numbers for xl to deal with? -- John C "JusMe" wrote: the result is a string of numbers .... like these: 50000356020079 500003560200710 the 'countif' one works with the first one, and doesn't seem to work with the second one "T. Valko" wrote: =CONCATENATE(A97;G97;H97) =CONCATENATE(A98;G98;H98) the result of this is either 14 or 15 characters (depending on the month of the year) Sounds like you're "building" date strings. Post some examples of the resulting strings from the above formulas. -- Biff Microsoft Excel MVP "JusMe" wrote in message ... Using Windows XP and Office2003: In column AJ we have a formula ... =CONCATENATE(A97;G97;H97) =CONCATENATE(A98;G98;H98) ... the result of this is either 14 or 15 characters (depending on the month of the year) in column AT we do a COUNTIF: ... =COUNTIF($AJ$83:$AJ$4916;AJ97) =COUNTIF($AJ$83:$AJ$4916;AJ98) since all of the values in the AJ column are unique, all of these formulas should have "1" as a result, however, the ones with a string in the AJ column of 15 characters give "3" as a result (conclusion: that's for months 10, 11 and 12 where the 0, 1 and 2 aren't recognized/counted). This would mean that only the first 14 characters are evaluated. I've tried several workarounds, but in itself these functions should work (or am I missing an elephant here). I've also seen questions about formulas that only work when they refer to cells with straight numbers instead of formulas, but even when I replace the 'concatenate' results with the resulting value of the cell, the result stays the same. For another formula on another sheet to work we need to have this error sorted out, and so far I haven't found what causes this. Can you point me in the right direction? |
#7
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On Mon, 11 Aug 2008 22:20:00 -0700, JusMe
wrote: Using Windows XP and Office2003: In column AJ we have a formula ... =CONCATENATE(A97;G97;H97) =CONCATENATE(A98;G98;H98) ... the result of this is either 14 or 15 characters (depending on the month of the year) in column AT we do a COUNTIF: ... =COUNTIF($AJ$83:$AJ$4916;AJ97) =COUNTIF($AJ$83:$AJ$4916;AJ98) since all of the values in the AJ column are unique, all of these formulas should have "1" as a result, however, the ones with a string in the AJ column of 15 characters give "3" as a result (conclusion: that's for months 10, 11 and 12 where the 0, 1 and 2 aren't recognized/counted). This would mean that only the first 14 characters are evaluated. I've tried several workarounds, but in itself these functions should work (or am I missing an elephant here). I've also seen questions about formulas that only work when they refer to cells with straight numbers instead of formulas, but even when I replace the 'concatenate' results with the resulting value of the cell, the result stays the same. For another formula on another sheet to work we need to have this error sorted out, and so far I haven't found what causes this. Can you point me in the right direction? The COUNTIF function works on cells that contain formulas, so the problem lies with your data, or with the result of your concatenation. Try using the Formula Evaluation tool to go step-by-step through the countif formula. --ron |
#8
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evaluating the formula doesn't give errors; it gives the correct string, but
it still gives '3' in each line where months 10, 11 or 12 are referenced .... I need to get Excel to evaluate all 15 characters and not just the first 14, or so it seems .... "Ron Rosenfeld" wrote: On Mon, 11 Aug 2008 22:20:00 -0700, JusMe wrote: Using Windows XP and Office2003: In column AJ we have a formula ... =CONCATENATE(A97;G97;H97) =CONCATENATE(A98;G98;H98) ... the result of this is either 14 or 15 characters (depending on the month of the year) in column AT we do a COUNTIF: ... =COUNTIF($AJ$83:$AJ$4916;AJ97) =COUNTIF($AJ$83:$AJ$4916;AJ98) since all of the values in the AJ column are unique, all of these formulas should have "1" as a result, however, the ones with a string in the AJ column of 15 characters give "3" as a result (conclusion: that's for months 10, 11 and 12 where the 0, 1 and 2 aren't recognized/counted). This would mean that only the first 14 characters are evaluated. I've tried several workarounds, but in itself these functions should work (or am I missing an elephant here). I've also seen questions about formulas that only work when they refer to cells with straight numbers instead of formulas, but even when I replace the 'concatenate' results with the resulting value of the cell, the result stays the same. For another formula on another sheet to work we need to have this error sorted out, and so far I haven't found what causes this. Can you point me in the right direction? The COUNTIF function works on cells that contain formulas, so the problem lies with your data, or with the result of your concatenation. Try using the Formula Evaluation tool to go step-by-step through the countif formula. --ron |
#9
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On Tue, 12 Aug 2008 03:41:01 -0700, JusMe
wrote: evaluating the formula doesn't give errors; it gives the correct string, but it still gives '3' in each line where months 10, 11 or 12 are referenced .... I need to get Excel to evaluate all 15 characters and not just the first 14, or so it seems .... I would not have expected the formula to give an error. The next step is to see what Excel is matching on. A first try at that would be to use Edit/Find and copy paste the exact string that your formula is generating into the Find What: box, and see if there are multiple matches. To copy/paste the exact string, I would select the box with the concatenate formula that is giving the unexpected result Edit/Copy Edit/Find select Find What: <ctrl-V (which should paste the value into the Find What box. <Find All and a list of matching cells should appear, along with the value contained in each cell. If that doesn't work, we'll try a different method. --ron |
#10
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Ron,
Thank you for your time and patience. Following what you typed, (changing the 'Look in' from Formulas to Values) I get the right cells back, one for every command I give for any line .... "Ron Rosenfeld" wrote: On Tue, 12 Aug 2008 03:41:01 -0700, JusMe wrote: evaluating the formula doesn't give errors; it gives the correct string, but it still gives '3' in each line where months 10, 11 or 12 are referenced .... I need to get Excel to evaluate all 15 characters and not just the first 14, or so it seems .... I would not have expected the formula to give an error. The next step is to see what Excel is matching on. A first try at that would be to use Edit/Find and copy paste the exact string that your formula is generating into the Find What: box, and see if there are multiple matches. To copy/paste the exact string, I would select the box with the concatenate formula that is giving the unexpected result Edit/Copy Edit/Find select Find What: <ctrl-V (which should paste the value into the Find What box. <Find All and a list of matching cells should appear, along with the value contained in each cell. If that doesn't work, we'll try a different method. --ron |
#11
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On Tue, 12 Aug 2008 12:29:01 -0700, JusMe
wrote: Ron, Thank you for your time and patience. Following what you typed, (changing the 'Look in' from Formulas to Values) I get the right cells back, one for every command I give for any line .... Well, for COUNTIF to return a '3', there must be three cells that it is matching. Since the Find didn't find them, then "easiest" next step would be to enter in, for example A97;G97;H97 some values that, gives a result in your AJ97 concatenation formula so that your formula in column AT gives a result of 3. Then, in some cell, e.g. AK83, enter the formula: =AJ83=$AJ$97 and fill down to $AJ$4916. Look to see which one's are TRUE. Oh, I see you've switched to using SUMPRODUCT, so you may not want to track this down any further. But that would be my next step, along with using conditional formatting to highlight the TRUE result. --ron |
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