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This leaves me confused too! I guess I'm faced with a simular problem as yours. I am trying to estimate the number of spare parts required to keep in stock to give me a 90% Service level (protection level). At the moment, the reverse calculation for demand with normal distribution is no problem ( x = NORMSINV ("ServiceLevel") ) however I could not find such for Poisson demand. So, simular to your earlier question; input = Service level and Mean demand (cumulative = True) and output the number of spare parts required? I follow your reasoning and I fully agree with your conclusion; Quote:
Can anyone help me to solve this using Excel 2010 and/or by not using the "crit_poisson()" function? Thanks a lot! KRG Erik |
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