Home |
Search |
Today's Posts |
#1
Posted to microsoft.public.excel.worksheet.functions
|
|||
|
|||
IF Formula
Take 2..
I am trying to get a formula that will assign a numeric value for a each year past "TODAY". The TODAY date needs to change every day. Today to 365days=1; 366 days to 730=2; 730 to 1095=3; 1095+ =4 |
#2
Posted to microsoft.public.excel.worksheet.functions
|
|||
|
|||
IF Formula
More info would have been helpful. Is this what you want.
=INT((TODAY()-H20)/365.25) -- Don Guillett Microsoft MVP Excel SalesAid Software "Matt" wrote in message ... Take 2.. I am trying to get a formula that will assign a numeric value for a each year past "TODAY". The TODAY date needs to change every day. Today to 365days=1; 366 days to 730=2; 730 to 1095=3; 1095+ =4 |
#3
Posted to microsoft.public.excel.worksheet.functions
|
|||
|
|||
IF Formula
One way:
If you're not concerned about leap years: A1: <date B1: =INT((A1-TODAY()-1)/365)+1 or if your max is really 4: B1: =MIN(4, INT((A1-TODAY()-1)/365)+1) If you want to take leap years into account: B1: =DATEDIF(TODAY(),A1-1,"y")+1 In article , Matt wrote: I am trying to get a formula that will assign a numeric value for a each year past "TODAY". The TODAY date needs to change every day. Today to 365days=1; 366 days to 730=2; 730 to 1095=3; 1095+ =4 |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|