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Try this:
=ADDRESS(18,3+MATCH(LOOKUP(99^99,D18:V18),D18:V18) ) -- HTH, RD ================================================== === Please keep all correspondence within the Group, so all may benefit! ================================================== === "sevi61" wrote in message ... hi Biff, thank you for your prompt reply. in answer to your question; the data is numeric and there are formulas in the range but not to return blanks. the formula that would be in the last populated cell would be =(9-SUM(XXX:XXX)) I hope this clarifies things a little thanks again for taking the time to help with this regards, sevi "T. Valko" wrote: find the last cell in that range with data What is the data type? Is it TEXT or NUMERIC or is it a mixture of BOTH? Are there any formulas in this range that return blanks? Do you want to include these blanks as data? Assuming the data type is TEXT and there are no formulas in the range that return blanks: =IF(COUNTA(D18:V18),ADDRESS(18,MATCH(REPT("z",255) ,D18:V18)+3,4),"") -- Biff Microsoft Excel MVP "sevi61" wrote in message ... Hi, I have scoured these posts but haven't quite found what I'm looking for, hopefully someone can help.... Is it possible to write a formula that will search a range (D18:V18), find the last cell in that range with data, then show the cell address, not the value of the cell, in a different cell? I have been thinking that maybe I will need an array formula, or at worst, a macro or VBA? Any response will be greatly appreciated. sevi |
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