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Default Creating a series of cells with multiple incrimenting characters

Hi,

I need to create a series of 1000 cells down a column. They will be in this
format:

MM1A
MM1B
MM1C
MM1D
MM1E
MM3A
MM3B
MM3C
MM3D
MM3E
MM5A
MM5B
MM5C
......

So, the first 2 characters are always the same, the 3rd character, an odd
number incriments by 2 every 6th row, and the fourth character changes
alphabetically through 5 rows, then it resets to "A"...

Please give me some ideas?

Thanks,
--
Markb
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Default Creating a series of cells with multiple incrimenting characters

Here's a formula that will do what you've described, if I read it correctly.
Assuming you're starting in cell A1.

In A1 enter:
MM1A

IN A2 enter:
=IF(RIGHT(A1,1)<"E",LEFT(A1,3)&CHAR(CODE(RIGHT(A1 ,1))+1),"MM"&MOD(MID(A1,3,1)+2,10)&"A")

Copy down through A1000

Note that the sequence repeats every 25 rows. Is this what you're looking
for? If so, it seems it would have been easier to just manually type out the
25 rows, then fill down through 1000.

HTH,
Elkar



"markb" wrote:

Hi,

I need to create a series of 1000 cells down a column. They will be in this
format:

MM1A
MM1B
MM1C
MM1D
MM1E
MM3A
MM3B
MM3C
MM3D
MM3E
MM5A
MM5B
MM5C
.....

So, the first 2 characters are always the same, the 3rd character, an odd
number incriments by 2 every 6th row, and the fourth character changes
alphabetically through 5 rows, then it resets to "A"...

Please give me some ideas?

Thanks,
--
Markb

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Posts: 3,718
Default Creating a series of cells with multiple incrimenting characters

Try this:

="MM"&INT((ROWS($1:1)-1)/5)*2+1&CHAR(MOD(ROWS($1:1)-1,5)+65)

copy down as far as needed


"markb" wrote:

Hi,

I need to create a series of 1000 cells down a column. They will be in this
format:

MM1A
MM1B
MM1C
MM1D
MM1E
MM3A
MM3B
MM3C
MM3D
MM3E
MM5A
MM5B
MM5C
.....

So, the first 2 characters are always the same, the 3rd character, an odd
number incriments by 2 every 6th row, and the fourth character changes
alphabetically through 5 rows, then it resets to "A"...

Please give me some ideas?

Thanks,
--
Markb

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