Home |
Search |
Today's Posts |
#1
Posted to microsoft.public.excel.worksheet.functions
|
|||
|
|||
Invert a column
I need to invert the data in a column. The column is a mixture of text
numbers and blanks. Here is a small example in col A a1: a2: ssn a3: 123 a4: 45 a5: 6789 a6: a7: a8: tel a9: 189xx a10: 276xx What I need in col B b1: 276xx b2: 189xx b3: tel b4: b5: b6: 6789 b7: 45 b8: 123 b9: ssn b10: I am now doing this manually by first copying col A to col B, and then I put in a col of numbers like 1,2,3,4,€¦, and then I sort by this new col in descending order. I have to repeat this every time col A is changed. Is there a formula I can put in col B which could figure out where the last col A value is and to automatically do this for me? Thanks in advance for any help. -- jake |
#2
Posted to microsoft.public.excel.worksheet.functions
|
|||
|
|||
Invert a column
you could try this in B1 and copy down as far as needed
=INDEX(A:A,LOOKUP(2,1/($A$1:$A$65535<""),ROW($A$1:$A$65535))-ROWS(B$1:B1)+1) although it will return a 0 for empty cells (which can be hidden by using a custom format, such as General;General;;General). "Jakobshavn Isbrae" wrote: I need to invert the data in a column. The column is a mixture of text numbers and blanks. Here is a small example in col A a1: a2: ssn a3: 123 a4: 45 a5: 6789 a6: a7: a8: tel a9: 189xx a10: 276xx What I need in col B b1: 276xx b2: 189xx b3: tel b4: b5: b6: 6789 b7: 45 b8: 123 b9: ssn b10: I am now doing this manually by first copying col A to col B, and then I put in a col of numbers like 1,2,3,4,€¦, and then I sort by this new col in descending order. I have to repeat this every time col A is changed. Is there a formula I can put in col B which could figure out where the last col A value is and to automatically do this for me? Thanks in advance for any help. -- jake |
#3
Posted to microsoft.public.excel.worksheet.functions
|
|||
|
|||
Invert a column
Thank you very much. I don't think the problem of blanks showing as zeros is
crucial. By the way, your suggestion of using the special format hides both real zeros and zeros-as-blanks -- jake "JMB" wrote: you could try this in B1 and copy down as far as needed =INDEX(A:A,LOOKUP(2,1/($A$1:$A$65535<""),ROW($A$1:$A$65535))-ROWS(B$1:B1)+1) although it will return a 0 for empty cells (which can be hidden by using a custom format, such as General;General;;General). "Jakobshavn Isbrae" wrote: I need to invert the data in a column. The column is a mixture of text numbers and blanks. Here is a small example in col A a1: a2: ssn a3: 123 a4: 45 a5: 6789 a6: a7: a8: tel a9: 189xx a10: 276xx What I need in col B b1: 276xx b2: 189xx b3: tel b4: b5: b6: 6789 b7: 45 b8: 123 b9: ssn b10: I am now doing this manually by first copying col A to col B, and then I put in a col of numbers like 1,2,3,4,€¦, and then I sort by this new col in descending order. I have to repeat this every time col A is changed. Is there a formula I can put in col B which could figure out where the last col A value is and to automatically do this for me? Thanks in advance for any help. -- jake |
#4
Posted to microsoft.public.excel.worksheet.functions
|
|||
|
|||
Invert a column
Try this:
=IF(INDEX(DATA,ROWS(DATA)-ROWS($1:1)+1)=0,"",INDEX(DATA,ROWS(DATA)-ROWS($1:1)+1)) "Jakobshavn Isbrae" wrote: I need to invert the data in a column. The column is a mixture of text numbers and blanks. Here is a small example in col A a1: a2: ssn a3: 123 a4: 45 a5: 6789 a6: a7: a8: tel a9: 189xx a10: 276xx What I need in col B b1: 276xx b2: 189xx b3: tel b4: b5: b6: 6789 b7: 45 b8: 123 b9: ssn b10: I am now doing this manually by first copying col A to col B, and then I put in a col of numbers like 1,2,3,4,€¦, and then I sort by this new col in descending order. I have to repeat this every time col A is changed. Is there a formula I can put in col B which could figure out where the last col A value is and to automatically do this for me? Thanks in advance for any help. -- jake |
#5
Posted to microsoft.public.excel.worksheet.functions
|
|||
|
|||
Invert a column
I should note that I was assuming the range in column A was changing often so
did not hardcode the column A range reference into the formula. If your data set is very large, I am sure you will have problems w/calculation speed. In which case you should consider Teethless Mama's suggestion (I reposted it below): =IF(INDEX(DATA,ROWS(DATA)-ROWS($1:1)+1)="","",INDEX(DATA,ROWS(DATA)-ROWS($1:1)+1)) "Jakobshavn Isbrae" wrote: Thank you very much. I don't think the problem of blanks showing as zeros is crucial. By the way, your suggestion of using the special format hides both real zeros and zeros-as-blanks -- jake "JMB" wrote: you could try this in B1 and copy down as far as needed =INDEX(A:A,LOOKUP(2,1/($A$1:$A$65535<""),ROW($A$1:$A$65535))-ROWS(B$1:B1)+1) although it will return a 0 for empty cells (which can be hidden by using a custom format, such as General;General;;General). "Jakobshavn Isbrae" wrote: I need to invert the data in a column. The column is a mixture of text numbers and blanks. Here is a small example in col A a1: a2: ssn a3: 123 a4: 45 a5: 6789 a6: a7: a8: tel a9: 189xx a10: 276xx What I need in col B b1: 276xx b2: 189xx b3: tel b4: b5: b6: 6789 b7: 45 b8: 123 b9: ssn b10: I am now doing this manually by first copying col A to col B, and then I put in a col of numbers like 1,2,3,4,€¦, and then I sort by this new col in descending order. I have to repeat this every time col A is changed. Is there a formula I can put in col B which could figure out where the last col A value is and to automatically do this for me? Thanks in advance for any help. -- jake |
#6
Posted to microsoft.public.excel.worksheet.functions
|
|||
|
|||
Invert a column
This formula is a little shorter.
Enter it *anywhere*, and copy down 10 rows: =INDEX($A$1:$A$10,ROWS(1:$10)) Revise to match your actual range! -- HTH, RD --------------------------------------------------------------------------- Please keep all correspondence within the NewsGroup, so all may benefit ! --------------------------------------------------------------------------- "Jakobshavn Isbrae" wrote in message ... Thank you very much. I don't think the problem of blanks showing as zeros is crucial. By the way, your suggestion of using the special format hides both real zeros and zeros-as-blanks -- jake "JMB" wrote: you could try this in B1 and copy down as far as needed =INDEX(A:A,LOOKUP(2,1/($A$1:$A$65535<""),ROW($A$1:$A$65535))-ROWS(B$1:B1)+1) although it will return a 0 for empty cells (which can be hidden by using a custom format, such as General;General;;General). "Jakobshavn Isbrae" wrote: I need to invert the data in a column. The column is a mixture of text numbers and blanks. Here is a small example in col A a1: a2: ssn a3: 123 a4: 45 a5: 6789 a6: a7: a8: tel a9: 189xx a10: 276xx What I need in col B b1: 276xx b2: 189xx b3: tel b4: b5: b6: 6789 b7: 45 b8: 123 b9: ssn b10: I am now doing this manually by first copying col A to col B, and then I put in a col of numbers like 1,2,3,4,., and then I sort by this new col in descending order. I have to repeat this every time col A is changed. Is there a formula I can put in col B which could figure out where the last col A value is and to automatically do this for me? Thanks in advance for any help. -- jake |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|
Similar Threads | ||||
Thread | Forum | |||
invert Lines and column on Excel | Excel Discussion (Misc queries) | |||
How do I invert a column of numbers? (make the 1st last, etc) | Excel Discussion (Misc queries) | |||
reverse or invert column data | Excel Worksheet Functions | |||
how do you invert a column | Excel Discussion (Misc queries) | |||
How do I invert a column in Excel? | Excel Discussion (Misc queries) |