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On May 3, 1:20 pm, "T. Valko" wrote:
You can reduce that to (still array entered): =IF(COUNTIF($U$26:$U$43,TRUE)=ROW(A1),SMALL(IF($U $26:$U$43,$T$26:$T$43),RO*W(A1)),"") Biff "Toppers" wrote in message ... Minor correction .... =IF(COUNTIF($U$26:$U$43,TRUE)=ROW(A1),SMALL(IF($U $26:$U$43=TRUE,($T$26:$T$*43)*($U$26:$U$43),""),RO W(A1)),"") "Toppers" wrote: Try this entered with Ctrl+Shift+Enter in W25: =IF(COUNTIF($U$26:$U$43,TRUE)=ROW(A1),SMALL(IF($U $26:$U$43=TRUE,($T$26:$T$*43)*($U$26:$U$43),""),RO W(A1))) Copy down. "Nikki" wrote: Hello Everyone, I seem to have come across another problem I cannot figure out how to solve in Excel. In column T, rows 26:43, I have certain "Slice Thicknesses", values ranging from 0.5 to 10, no real method to the madness of the intervals between numbers-- (0.5, 0.625, 1, 1.25, 1.5, 2, 2.5, 3, 3.75, 4, 5, 6, 7, 7.5, 8, 9, 10). T44 is "Other". In column U, rows 26:44, is the TRUE/FALSE result from checkboxes of the user filled worksheet, corresponding to the slice thicknesses available. I would like to return, in a single cell (ideally), or array of cells starting at W25, the slice thicknesses available - all the values that return TRUE. If in a single cell, a string value with the thicknesses available separated by ",". For now, we can ignore the "Other" option, I'll brainstorm how to conquer that particular problem later. A note: it is possible to have all the given slice thicknesses, as well as any combination, or even just one or two selected. Any help is appreciated, Thank you in advance! Nikki- Hide quoted text - - Show quoted text - Thanks Biff, Works great!! Nikki |
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