Is there a way to break out of a Find and Replace procedure that is looking
for a link that it cannot find. I had an instance where I did find all and
noted that there were 388 cells that included what I asked to be replaced.
Then I made the mistake of clicking Replace All and found that I had set a
loop going where the system was looking for a non-existent link and I could
not break out of and had to hit return in respect each instance

Is there a way of braking out of that?

TIA
Ron

I don't know of a way to break out of this, but there is a way to avoid it
that I use. After filling out the "find what" and "replace with" boxes,
check "find next" and "replace" two or three times to see if it's working
correctly. Only then do I click "replace all."

"Ron McCormick" wrote in message
...
Is there a way to break out of a Find and Replace procedure that is
looking
for a link that it cannot find. I had an instance where I did find all
and
noted that there were 388 cells that included what I asked to be replaced.
Then I made the mistake of clicking Replace All and found that I had set a
loop going where the system was looking for a non-existent link and I
could
not break out of and had to hit return in respect each instance

Is there a way of braking out of that?

TIA
Ron

Thanks Richard,

I was wondering if anyone knew if there was another way. I all too often
forget to a trial replace before setting the replace all

"Ron McCormick" wrote:

Is there a way to break out of a Find and Replace procedure that is looking
for a link that it cannot find. I had an instance where I did find all and
noted that there were 388 cells that included what I asked to be replaced.
Then I made the mistake of clicking Replace All and found that I had set a
loop going where the system was looking for a non-existent link and I could
not break out of and had to hit return in respect each instance

Is there a way of braking out of that?

TIA
Ron