I have two ranges A1:A100, B1:B100 each containing single digit numbers
typically between 3 and 8. (No blank cells.
I would like to count all the instances of each time row B contains a number
one less than that in the equivalent A cell. eg if A5 contains 6 and B5
contains 5 then that would count as one instance. The pairs have to be the
same numbers. further eg A10 containing 6 and B10 containing 5 would count
as a second instance but A12 containing 7 and B12 containing 6 would not. Am
I making sense?
TIA
Sandy

I would create a helper column, say in Column C, with the following formula:
=IF(A1=B1+5,1,0) and fill that down, then sum column C. That sum would be
your count of rows for which the value in column A is one more than the value
in column C.

Dave
--
A hint to posters: Specific, detailed questions are more likely to be
answered than questions that provide no detail about your problem.


"Sandy" wrote:

I have two ranges A1:A100, B1:B100 each containing single digit numbers
typically between 3 and 8. (No blank cells.
I would like to count all the instances of each time row B contains a number
one less than that in the equivalent A cell. eg if A5 contains 6 and B5
contains 5 then that would count as one instance. The pairs have to be the
same numbers. further eg A10 containing 6 and B10 containing 5 would count
as a second instance but A12 containing 7 and B12 containing 6 would not. Am
I making sense?
TIA
Sandy

I mean: That sum would be your count of rows for which the value in column A
is one more than the value in column B.

--
A hint to posters: Specific, detailed questions are more likely to be
answered than questions that provide no detail about your problem.


"Dave F" wrote:

I would create a helper column, say in Column C, with the following formula:
=IF(A1=B1+5,1,0) and fill that down, then sum column C. That sum would be
your count of rows for which the value in column A is one more than the value
in column C.

Dave
--
A hint to posters: Specific, detailed questions are more likely to be
answered than questions that provide no detail about your problem.


"Sandy" wrote:

I have two ranges A1:A100, B1:B100 each containing single digit numbers
typically between 3 and 8. (No blank cells.
I would like to count all the instances of each time row B contains a number
one less than that in the equivalent A cell. eg if A5 contains 6 and B5
contains 5 then that would count as one instance. The pairs have to be the
same numbers. further eg A10 containing 6 and B10 containing 5 would count
as a second instance but A12 containing 7 and B12 containing 6 would not. Am
I making sense?
TIA
Sandy

Put these values in C1:C6 - 3, 4, 5, 6, 7, 8, then in D1 enter this
formula:

=SUMPRODUCT((A$1:A$100=C1)*(B$1:B$100=C1-1))

then copy the formula down into D2:D6. It will give you the count of
the number of instances where A is one more than B, for the values of
A given in column C.

Hope this helps.

Pete

On Mar 30, 4:20 pm, "Sandy" wrote:
I have two ranges A1:A100, B1:B100 each containing single digit numbers
typically between 3 and 8. (No blank cells.
I would like to count all the instances of each time row B contains a number
one less than that in the equivalent A cell. eg if A5 contains 6 and B5
contains 5 then that would count as one instance. The pairs have to be the
same numbers. further eg A10 containing 6 and B10 containing 5 would count
as a second instance but A12 containing 7 and B12 containing 6 would not. Am
I making sense?
TIA
Sandy

One way

=SUMPRODUCT(--(A1:A100-B1:B100=1),--(A1:A100=6))


Regards,

Peo Sjoblom


"Sandy" wrote in message
...
I have two ranges A1:A100, B1:B100 each containing single digit numbers
typically between 3 and 8. (No blank cells.
I would like to count all the instances of each time row B contains a
number one less than that in the equivalent A cell. eg if A5 contains 6
and B5 contains 5 then that would count as one instance. The pairs have to
be the same numbers. further eg A10 containing 6 and B10 containing 5
would count as a second instance but A12 containing 7 and B12 containing 6
would not. Am I making sense?
TIA
Sandy

Thank you thats perfect
Sandy
"Peo Sjoblom" wrote in message
...
One way

=SUMPRODUCT(--(A1:A100-B1:B100=1),--(A1:A100=6))


Regards,

Peo Sjoblom


"Sandy" wrote in message
...
I have two ranges A1:A100, B1:B100 each containing single digit numbers
typically between 3 and 8. (No blank cells.
I would like to count all the instances of each time row B contains a
number one less than that in the equivalent A cell. eg if A5 contains 6
and B5 contains 5 then that would count as one instance. The pairs have
to be the same numbers. further eg A10 containing 6 and B10 containing 5
would count as a second instance but A12 containing 7 and B12 containing
6 would not. Am I making sense?
TIA
Sandy