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#1
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how would i get the man hours to do a load. I have 4 workers and it took
them 1:30 to load 1023 cases. |
#2
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One way:
=4*1.5/1023 === 0.005865103 mh/case In article , bkk wrote: how would i get the man hours to do a load. I have 4 workers and it took them 1:30 to load 1023 cases. |
#3
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Assuming
#workers in A2: 4, time taken in B2: 1:30 (time format), total cases in C2: 1023, Place In D2: =A2*(B2*24) In E2: =D2/C2 Format D2 and E2 as number to taste D2 returns the total manhours (= #workers x time taken*) *with the time in B2 converted to decimal time via the "x 24" bit E2 returns the required manhours per case (= total manhours / total cases) You could select D2:E2 and simply copy down to return corresponding results for other sets of inputs in A3:C3. A4:C4, etc -- Max Singapore http://savefile.com/projects/236895 xdemechanik --- "bkk" wrote: how would i get the man hours to do a load. I have 4 workers and it took them 1:30 to load 1023 cases. |
#4
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what function should i use, I did what you said and the function just stayed
their. "Max" wrote: Assuming #workers in A2: 4, time taken in B2: 1:30 (time format), total cases in C2: 1023, Place In D2: =A2*(B2*24) In E2: =D2/C2 Format D2 and E2 as number to taste D2 returns the total manhours (= #workers x time taken*) *with the time in B2 converted to decimal time via the "x 24" bit E2 returns the required manhours per case (= total manhours / total cases) You could select D2:E2 and simply copy down to return corresponding results for other sets of inputs in A3:C3. A4:C4, etc -- Max Singapore http://savefile.com/projects/236895 xdemechanik --- "bkk" wrote: how would i get the man hours to do a load. I have 4 workers and it took them 1:30 to load 1023 cases. |
#5
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If you type or copied Max's formulas to D2 and E2 and it remains a formula in
the cell, could be your cell was formatted as text. Re-format the cell to General then hit F2 and ENTER. Gord Dibben MS Excel MVP On Sat, 10 Mar 2007 15:30:00 -0800, bkk wrote: what function should i use, I did what you said and the function just stayed their. "Max" wrote: Assuming #workers in A2: 4, time taken in B2: 1:30 (time format), total cases in C2: 1023, Place In D2: =A2*(B2*24) In E2: =D2/C2 Format D2 and E2 as number to taste D2 returns the total manhours (= #workers x time taken*) *with the time in B2 converted to decimal time via the "x 24" bit E2 returns the required manhours per case (= total manhours / total cases) You could select D2:E2 and simply copy down to return corresponding results for other sets of inputs in A3:C3. A4:C4, etc -- Max Singapore http://savefile.com/projects/236895 xdemechanik --- "bkk" wrote: how would i get the man hours to do a load. I have 4 workers and it took them 1:30 to load 1023 cases. |
#6
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I changed the format and that worked but my man hours per case wasn't but
0.01 and I don't think that could be right. I have 4 workers it took 9:00 hours to load 5700 cases. "Gord Dibben" wrote: If you type or copied Max's formulas to D2 and E2 and it remains a formula in the cell, could be your cell was formatted as text. Re-format the cell to General then hit F2 and ENTER. Gord Dibben MS Excel MVP On Sat, 10 Mar 2007 15:30:00 -0800, bkk wrote: what function should i use, I did what you said and the function just stayed their. "Max" wrote: Assuming #workers in A2: 4, time taken in B2: 1:30 (time format), total cases in C2: 1023, Place In D2: =A2*(B2*24) In E2: =D2/C2 Format D2 and E2 as number to taste D2 returns the total manhours (= #workers x time taken*) *with the time in B2 converted to decimal time via the "x 24" bit E2 returns the required manhours per case (= total manhours / total cases) You could select D2:E2 and simply copy down to return corresponding results for other sets of inputs in A3:C3. A4:C4, etc -- Max Singapore http://savefile.com/projects/236895 xdemechanik --- "bkk" wrote: how would i get the man hours to do a load. I have 4 workers and it took them 1:30 to load 1023 cases. |
#7
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OK, what answer do *you* think Excel's arithmetic should give when it is
dividing 36 man hours by 5700? 0.006316 if you want a few more decimal places, or about 23 seconds per case. -- David Biddulph "bkk" wrote in message ... I changed the format and that worked but my man hours per case wasn't but 0.01 and I don't think that could be right. I have 4 workers it took 9:00 hours to load 5700 cases. "Gord Dibben" wrote: If you type or copied Max's formulas to D2 and E2 and it remains a formula in the cell, could be your cell was formatted as text. Re-format the cell to General then hit F2 and ENTER. Gord Dibben MS Excel MVP On Sat, 10 Mar 2007 15:30:00 -0800, bkk wrote: what function should i use, I did what you said and the function just stayed their. "Max" wrote: Assuming #workers in A2: 4, time taken in B2: 1:30 (time format), total cases in C2: 1023, Place In D2: =A2*(B2*24) In E2: =D2/C2 Format D2 and E2 as number to taste D2 returns the total manhours (= #workers x time taken*) *with the time in B2 converted to decimal time via the "x 24" bit E2 returns the required manhours per case (= total manhours / total cases) You could select D2:E2 and simply copy down to return corresponding results for other sets of inputs in A3:C3. A4:C4, etc -- Max Singapore http://savefile.com/projects/236895 xdemechanik --- "bkk" wrote: how would i get the man hours to do a load. I have 4 workers and it took them 1:30 to load 1023 cases. |
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