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RegRat

countif programming function
 
Would someone please show me how to write an equation to count the number of
entries that meet more than 1 condition. I need to count the number of any
COLOR of "green" with an "Approved" STATUS (answer: 3)? Thanks a bunch,
A B
1 COLOR STATUS
2 Yellowgreen Pending
3 Green Approved
4 Green Pending
5 Bluegreen Approved
6 Red Approved
7 Yellow Approved
8 Green Approved
9 Bluegreen Pending


John Bundy

countif programming function
 
Put in a helper column with concantenate which will look like this
GreenApproved
with code like this
=B3&C3
then have your criteria in two seperate columns
=COUNTIF(D3:D9,D2&E2)
green in D2 and Approved in E2

I come back with 2 so are you wanting to get all approved that contain green
anywhere in the name?



--
-John Northwest11
Please rate when your question is answered to help us and others know what
is helpful.


"RegRat" wrote:

Would someone please show me how to write an equation to count the number of
entries that meet more than 1 condition. I need to count the number of any
COLOR of "green" with an "Approved" STATUS (answer: 3)? Thanks a bunch,
A B
1 COLOR STATUS
2 Yellowgreen Pending
3 Green Approved
4 Green Pending
5 Bluegreen Approved
6 Red Approved
7 Yellow Approved
8 Green Approved
9 Bluegreen Pending


Elkar

countif programming function
 
If you have more than one criteria, use the SUMPRODUCT function. Try this:

=SUMPRODUCT(--(NOT(ISERROR(SEARCH("green",A1:A8)))),--(B1:B8="approved"))

HTH,
Elkar


"RegRat" wrote:

Would someone please show me how to write an equation to count the number of
entries that meet more than 1 condition. I need to count the number of any
COLOR of "green" with an "Approved" STATUS (answer: 3)? Thanks a bunch,
A B
1 COLOR STATUS
2 Yellowgreen Pending
3 Green Approved
4 Green Pending
5 Bluegreen Approved
6 Red Approved
7 Yellow Approved
8 Green Approved
9 Bluegreen Pending


RegRat

countif programming function
 
Yes, I need a total count of all approved with green anywhere in the name.
thanks,

"John Bundy" wrote:

Put in a helper column with concantenate which will look like this
GreenApproved
with code like this
=B3&C3
then have your criteria in two seperate columns
=COUNTIF(D3:D9,D2&E2)
green in D2 and Approved in E2

I come back with 2 so are you wanting to get all approved that contain green
anywhere in the name?



--
-John Northwest11
Please rate when your question is answered to help us and others know what
is helpful.


"RegRat" wrote:

Would someone please show me how to write an equation to count the number of
entries that meet more than 1 condition. I need to count the number of any
COLOR of "green" with an "Approved" STATUS (answer: 3)? Thanks a bunch,
A B
1 COLOR STATUS
2 Yellowgreen Pending
3 Green Approved
4 Green Pending
5 Bluegreen Approved
6 Red Approved
7 Yellow Approved
8 Green Approved
9 Bluegreen Pending


JMB

countif programming function
 
I think you could eliminate the NOT function call:
=SUMPRODUCT(--ISNUMBER(SEARCH("green",A1:A8)),--(B1:B8="approved"))


"Elkar" wrote:

If you have more than one criteria, use the SUMPRODUCT function. Try this:

=SUMPRODUCT(--(NOT(ISERROR(SEARCH("green",A1:A8)))),--(B1:B8="approved"))

HTH,
Elkar


"RegRat" wrote:

Would someone please show me how to write an equation to count the number of
entries that meet more than 1 condition. I need to count the number of any
COLOR of "green" with an "Approved" STATUS (answer: 3)? Thanks a bunch,
A B
1 COLOR STATUS
2 Yellowgreen Pending
3 Green Approved
4 Green Pending
5 Bluegreen Approved
6 Red Approved
7 Yellow Approved
8 Green Approved
9 Bluegreen Pending



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