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#1
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Converting Test Scores to somewhat of a Linear Transformation
I have been trying to figure out an excel formula that will convert
test scores. I figured it out algebraically but not in Excel. First I will give the formula. Next the scenario. Test 1: has as passing point of 70 and a max of 100 Test 2: has a passing point of 50 and a max of 70 To do a linear transformation Call test1 y, and test2 x Substitute into y = ax+b At the passing score we get: 70 = a50+b At maximum score we get: 100 = a70+b Solve we a = 1.5 and b = -5 To convert test2 scores to a scale somewhat equivalent to test1 using the formula : 1.5x-5 So a score of 60 on test 2 will transform to a score of 85 y=(1.5) 60 - 5 = 90- 5= 85. What I would like to do is put Test1 scores in Range A. Test 2 scores in Range B. Then In range e1: 70, In range F1:100 In range E2: 50 and rangeF2: 70. Then have a formula in Range C that will give me the scores. |
#2
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Converting Test Scores to somewhat of a Linear Transformation
Hi,
I couldn't follow your exact problem here but I think you are looking for SLOPE and INTERSECT. In the equation y = mx +c m is your gradient (SLOPE in Excel) c is your y-intersection (INTERSECT in Excel) So your equation becomes y = SLOPE(Known Y's,Known X's)x + INTERSECT(Known Y's,Known X's) with your Known Y's + Known X's being your range of data. Does that help? Martin |
#3
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Converting Test Scores to somewhat of a Linear Transformation
Whooops!! That should read INTERCEPT not INTERSECT
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#4
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Converting Test Scores to somewhat of a Linear Transformation
Hi again,
Rereading your post wouldn't it be easier to express them in terms of percentages. Test 1 with a maximum of 100 is already in percent so pass is 70% Test 2 pass = 50/70*100 = 71.43% Actually the equivalent pass point of 70% is 49 not 50 a score of 60 =60/70*100 = 85.71% HTH Martin |
#5
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Converting Test Scores to somewhat of a Linear Transformation
OK forget the percentage we'll go back to Linear regression.
With E1:-70 F1:-100 E2:- 50 F2:-70 putting this formula in C1 will return B1 adjusted by linear regression. =SLOPE($E$1:$F$1,$E$2:$F$2)*B1+INTERCEPT($E$1:$F$1 ,$E$2:$F$2) HTH Martin |
#6
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Converting Test Scores to somewhat of a Linear Transformation
On Feb 11, 2:28 am, "MartinW" wrote:
OK forget the percentage we'll go back to Linear regression. With E1:-70 F1:-100 E2:- 50 F2:-70 putting this formula in C1 will return B1 adjusted by linear regression. =SLOPE($E$1:$F$1,$E$2:$F$2)*B1+INTERCEPT($E$1:$F$1 ,$E$2:$F$2) HTH Martin Thanks Martin, That did the trick. I appreciate the time that you took to review my post and the time that you put in to get me an answer. Thanks Again! |
#7
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Converting Test Scores to somewhat of a Linear Transformation
Thank you for the feedback, I should have paid more
attention when reading your original post. Regards Martin |
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