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Glad you worked it out, Rob !
To return just the column numbers, we could use the MATCH part of the expressions viz, array-entered: =MATCH(TRUE,6:6<"",0) =MAX((6:6<"")*(COLUMN(6:6))) -- Max Singapore http://savefile.com/projects/236895 xdemechanik --- "rob_bates" wrote in message ... Max: I figured it out; I put reference numbers in row 5 and then changed it to: =INDEX(5:5,MATCH(TRUE,6:6<"",0)) Thanks so much for your help; I learned something new! |
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