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Default Searching for a value in an Array

Probably it's easier to understand a bit faster version...

=INDEX(C1:C100,MATCH(1,IF(A1:A100="country",IF(B1: B100="machine",1)),0))

which still needs to be confirmed with control+shift+enter.

Jim May wrote:
Bob,
I'm getting closer and closer to understanding this stuff, but in this
example there is one small piece I haven't got yet,

Your Match() has 3 elements:
1) the 1,
2) the combination of the ranges (Col A and ColB as one parameter)
3) the 0, which is an exact match)

So 1 (in this case) is the lookup value, hummmm.. not sure I'm getting the
meaning here - I take 1 to be the value I'm looking for, confused

Tks in Advance,
Jim


"Bob Phillips" wrote:

=INDEX(C1:C100,MATCH(1,(A1:A100="country")*(B1:B10 0="machine"),0))

which is an array formula, it should be committed with Ctrl-Shift-Enter, not
just Enter.

--
HTH

Bob Phillips

(replace somewhere in email address with gmail if mailing direct)

"Farah" wrote in message
...
I have a master price list were I have in column A the country name, and

in
column B the machine model number and in column C the price.
Obviously you can find the same machine for many countries with different
prices, I need a formula were I can extract for a certain country the

price
of a certain machine.



 
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