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#1
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![]() Hey, I have excel 2000 and here's what i'm making and what my problem is: basically, i'm trying to collect a certain amount of money in a certain amount of time :) and i'd like to make it so it calculates how much i've gotten from day 1 and figures out how many more days it will take for me to reach my goal... hope you can get that. in short, what i need is a countdown function like =today()+(amount of days it will take with the average money made per day) ...or kind of like that. ![]() can anyone help me? -- simserob ------------------------------------------------------------------------ simserob's Profile: http://www.excelforum.com/member.php...o&userid=36635 View this thread: http://www.excelforum.com/showthread...hreadid=563830 |
#2
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![]() simserob Wrote: Hey, I have excel 2000 and here's what i'm making and what my problem is: basically, i'm trying to collect a certain amount of money in a certain amount of time :) and i'd like to make it so it calculates how much i've gotten from day 1 and figures out how many more days it will take for me to reach my goal... hope you can get that. in short, what i need is a countdown function like =today()+(amount of days it will take with the average money made per day) ...or kind of like that. ![]() can anyone help me? Try = today()+CEILING(AmountNeeded/AverageAmountPerDay) Where AmountNeeded and AverageAmountPerDay are references to whereever you have them. Scott -- Maistrye ------------------------------------------------------------------------ Maistrye's Profile: http://www.excelforum.com/member.php...o&userid=36078 View this thread: http://www.excelforum.com/showthread...hreadid=563830 |
#3
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![]() when i do that it says there's an error - i guess it doesn't recognize the significance of the numbers...i also would need a day counter to get the average amount earned per day. i think with the formula you gave me, it wouldn't come out to an amount of days...i'm not really sure though since i've never heard of the command "ceiling" -- simserob ------------------------------------------------------------------------ simserob's Profile: http://www.excelforum.com/member.php...o&userid=36635 View this thread: http://www.excelforum.com/showthread...hreadid=563830 |
#4
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![]() simserob Wrote: when i do that it says there's an error - i guess it doesn't recognize the significance of the numbers...i also would need a day counter to get the average amount earned per day. i think with the formula you gave me, it wouldn't come out to an amount of days...i'm not really sure though since i've never heard of the command "ceiling" Sorry, I forgot to put the significance into that equation. :-P Try = today()+CEILING(AmountNeeded/AverageAmountPerDay,1) My apologies. Scott -- Maistrye ------------------------------------------------------------------------ Maistrye's Profile: http://www.excelforum.com/member.php...o&userid=36078 View this thread: http://www.excelforum.com/showthread...hreadid=563830 |
#5
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![]() Yeah, now it works Thank you very much for your trouble, i really appreciate it -- simserob ------------------------------------------------------------------------ simserob's Profile: http://www.excelforum.com/member.php...o&userid=36635 View this thread: http://www.excelforum.com/showthread...hreadid=563830 |
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