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![]() From the list of items in column A, find each (if they exist) in Range("B2:F7") and list the header of that column (B1:F1) in column J. Column A items can occur under multiple headers in B1 to F1. I'm sure this is the culprit line... ..Range("J100").End(xlUp).Offset(1, 0) = i.Offset(Cells.End(xlUp), 0).Value Secondly, in column J where the header is listed, I am struggling to get the cell address of "i" next to header name in column K. So an example would be in col J = Col_B_Header and in col K = $B$5 Regards, Howard Option Explicit Sub ListHeader() Dim lngLstRow As Long Dim rngA As Range, i As Range With Sheets("Sheet2") lngLstRow = .UsedRange.Rows.Count For Each rngA In .Range("A2:A" & lngLstRow) For Each i In Range("B2:F7") If i.Value = rngA Then .Range("J100").End(xlUp).Offset(1, 0) _ = i.Offset(Cells.End(xlUp), 0).Value End If Next Next End With End Sub |
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