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comparing two columns in vba
Hello, I need help again. In excel sheet, I can compare two cells with "exact" command.However in vba, I need to use "exact" command in a loop, and I have to assign column names as variables. For example;
For j=1 To 10 For i = 1 To 100 Sheets("IS1").Cells(i, 4 + 3 * (j - 2)) = "=EXACT(C1;C2 )" Next Next works fine but It compares just 1st and 2nd columns. However, I want to compare for j'th column with j+1'th column. How can I do this. I will be very glad. Thanks a lot. |
#2
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comparing two columns in vba
oercim wrote:
Hello, I need help again. In excel sheet, I can compare two cells with "exact" command.However in vba, I need to use "exact" command in a loop, and I have to assign column names as variables. For example; For j=1 To 10 For i = 1 To 100 Sheets("IS1").Cells(i, 4 + 3 * (j - 2)) = "=EXACT(C1;C2 )" Next Next works fine but It compares just 1st and 2nd columns. However, I want to compare for j'th column with j+1'th column. How can I do this. I will be very glad. Somewhat like this: jOffset = 64 For j = 1 To 10 For i = 1 To 100 Sheets("IS1").Cells(i, 4 + 3 * (j - 2)) = "=EXACT(" & Chr(j + _ jOffset) & "1," & Chr(j + jOffset + 1) & "2)" Next Next Set jOffset equal to ASC(UCASE(starting column letter)) - 1. jOffset = 64 will start at column A, jOffset = 65 will start at column B, etc. -- - being bi-polar must suck - well yes and no |
#3
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comparing two columns in vba
Auric__ wrote:
oercim wrote: Hello, I need help again. In excel sheet, I can compare two cells with "exact" command.However in vba, I need to use "exact" command in a loop, and I have to assign column names as variables. For example; For j=1 To 10 For i = 1 To 100 Sheets("IS1").Cells(i, 4 + 3 * (j - 2)) = "=EXACT(C1;C2 )" Next Next works fine but It compares just 1st and 2nd columns. However, I want to compare for j'th column with j+1'th column. How can I do this. I will be very glad. Somewhat like this: jOffset = 64 For j = 1 To 10 For i = 1 To 100 Sheets("IS1").Cells(i, 4 + 3 * (j - 2)) = "=EXACT(" & Chr(j + _ jOffset) & "1," & Chr(j + jOffset + 1) & "2)" Next Next Set jOffset equal to ASC(UCASE(starting column letter)) - 1. jOffset = 64 will start at column A, jOffset = 65 will start at column B, etc. Ah, hell. My code doesn't account for columns beyond Z. This does... For j = 1 To 100 For i = 1 To 10 Sheets("IS1").Cells(i, 4 + 3 * (j - 2)).Formula = "=EXACT(" & _ Mid(Cells(i, j).Address, 2, InStr(2, Cells(i, j).Address, _ "$") - 2) & "1," & Mid(Cells(i, j + 1).Address, 2, InStr(2, _ Cells(i, j + 1).Address, "$") - 2) & "2)" Next Next Note that the need for jOffset has been removed. This code is somewhat more complex, but it doesn't need any tomfoolery to get the column, just grabs it straight from the Address property. -- Things heard on Hell's P.A. system: Attention, will the owner of a Pinto, license plate number... |
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