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rotating an Isoceles Triangle in the shape of a Gauge needle
Hi,
does anyone know how to rotate an Isosceles triange (in the shape of a Speedometer needle) from 0 to 100 (the speedometer dial is 240 deg in shape). i am basically finding the x & y to center the Isosceles needle in the center of the speedometer by taking the LEFT, WIDTH & TOP of the speedometer image. x=shp.Left+Shp.Width/2 y=shp.Top+Shp.Height/2 so the above would remain fixed for centering the Isosceles triangle. but how to calculate the Angle or the new X, Y positions for the point traversing the Speedometer Arc which is 240 degrees in shape based on a cell values ranging from 0 to 100? any help would be most appreciated. Please see attached file. |
#2
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rotating an Isoceles Triangle in the shape of a Gauge needle
Hi
If you don't absolutely have to use Excel, I would suggest using GeoGebra at www.geogebra.org. Click the download button then AppletStart. There are lots of good tutorial materials out there e.g. Geogebra Forum: http://www.geogebra.org/forum/ Community of Geogebra users, bug reports and feature requests. Geogebra Wiki: http://www.geogebra.org/en/wiki/index.php/English Collection of re-usable teaching resources. University of Limerick: http://www.ul.ie/cemtl/resources.htm Excellent GeoGebra step by step demos. Math 247: http://math247.pbworks.com/Learn-and-Use-GeoGebra Fantastic Step-by-Step Help on How to Use GeoGebra by Dr Linda Fahlberg- Stojanovska. Includes accessing Geogebra properties and methods using Javascript – very cool. If it must be Excel can you send me a personal email. I have several Word documents on creating animation using excel charts which might help. regards Paul On May 10, 11:26*am, noname wrote: * * Hi, * * does anyone know how to rotate an Isosceles triange (in the shape of a Speedometer needle) from 0 to 100 (the speedometer dial is 240 deg in shape). * * i am basically finding the x & y to center the Isosceles needle in the center of the speedometer by taking the LEFT, WIDTH & TOP of the speedometer image. * * x=shp.Left+Shp.Width/2 * * y=shp.Top+Shp.Height/2 * * so the above would remain fixed for centering the Isosceles triangle. * * but how to calculate the Angle or the new X, Y positions for the point traversing the Speedometer Arc which is 240 degrees in shape based on a cell values ranging from 0 to 100? * * any help would be most appreciated. * * Please see attached file. |
#3
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rotating an Isoceles Triangle in the shape of a Gauge needle
On May 10, 3:52*pm, Paul Robinson
wrote: Hi If you don't absolutely have to use Excel, I would suggest using GeoGebra atwww.geogebra.org. Click the download button then AppletStart. There are lots of good tutorial materials out there e.g. Geogebra Forum:http://www.geogebra.org/forum/ Community of Geogebra users, bug reports and feature requests. Geogebra Wiki: *http://www.geogebra.org/en/wiki/index.php/English Collection of re-usable teaching resources. University of Limerick:http://www.ul.ie/cemtl/resources.htm Excellent GeoGebra step by step demos. Math 247: * * * * * * *http://math247.pbworks.com/Learn-and-Use-GeoGebra Fantastic Step-by-Step Help on How to Use GeoGebra by Dr Linda Fahlberg- * * * Stojanovska. Includes accessing Geogebra properties and methods using Javascript – * *very cool. If it must be Excel can you send me a personal email. I have several Word documents on creating animation using excel charts which might help. regards Paul On May 10, 11:26*am, noname wrote: * * Hi, * * does anyone know how to rotate an Isosceles triange (in the shape of a Speedometer needle) from 0 to 100 (the speedometer dial is 240 deg in shape). * * i am basically finding the x & y to center the Isosceles needle in the center of the speedometer by taking the LEFT, WIDTH & TOP of the speedometer image. * * x=shp.Left+Shp.Width/2 * * y=shp.Top+Shp.Height/2 * * so the above would remain fixed for centering the Isosceles triangle. * * but how to calculate the Angle or the new X, Y positions for the point traversing the Speedometer Arc which is 240 degrees in shape based on a cell values ranging from 0 to 100? * * any help would be most appreciated. * * Please see attached file. Hi Paul, i have sent you a personal email. please send me a test mail n i shall send u the file. |
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