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Brilliant - the first option worked like a charm! Thanks.
"Jacob Skaria" wrote: --Cant you set the visible property of the chart to false from Sheets("TIA") worksheet_Change event referring to Range("A38") ...like Worksheets("TIA Analysis").ChartObjects("Chart name").Visible = False --If you really want to work on the shape object try the below code. You dont need to select the sheet or the text box...Again make use of the worksheet_Change event referring to Range("A38") Dim sh As Shape Set sh = Worksheets("TIA Analysis").Shapes.AddTextbox( _ msoTextOrientationHorizontal, 195, 18, 425, 268) With sh.TextFrame .Characters.Text = "No Data" .HorizontalAlignment = xlHAlignCenter .VerticalAlignment = xlVAlignCenter .Characters.Font.Name = "Arial" .Characters.Font.Size = 28 .Characters.Font.ColorIndex = 3 End With -- Jacob (MVP - Excel) "BoRed79" wrote: Hi. I have a graph in Excel which is populated with data based upon a selection from a drop down box. For some of the selections though there is no data and an error message comes up and the graph does not display properly. I want to (using VBA) have a command that executes if there is no data to populate the graph and temporarily display a text box over the graph to say data unavailable - that way the graph does not look untidy. I have put together some code - which is not working - and wondered if anyone can give me some advice to make it work and also to supress the error message. The code I have started is contained in the ThisWorkbook object and is as follows: Private Sub Workbook_SheetCalculate(ByVal Sh As Object) If Sheets("TIA").Range("A38") = 0 Then If Sh.Name = "TIA" Then Worksheets("TIA Analysis").Select ActiveSheet.Shapes.AddTextbox(msoTextOrientationHo rizontal, 195, 18, 425, 268).Select Selection.Characters.Text = "DATA UNAVAILABLE" Selection.HorizontalAlignment = xlCenter With Selection.Characters.Font .Name = "Arial" .FontStyle = "Regular" .Size = 28 .Strikethrough = False .Superscript = False .Subscript = False .OutlineFont = False .Shadow = False .Underline = xlUnderlineStyleNone .ColorIndex = 3 End With End If End If End Sub Any help would be welcomed. Thanks. Liz. |
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