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Thanks p,
I'll take a look at that "p45cal" wrote: Just a note of caution; you've taken the first element in the series formula which is the Name of the series, often a single cell, but more importantly, it can be nothing, the same goes for the second element which are x axis categories/values, the third element is the y values range, which may be the one to go for because a series really should have some y-values! Some charts have non-contiguous ranges for y-values, so there may be more uncertainty there. There's more on more reliably finding a chart's source range (including a function) in John Walkenbach's book Excel 2002 Power Programming with VBA, on page 542, which is surprisingly, but happily, available on the web 'here' (http://tinyurl.com/y24qhol). It took a minute or two to load - I hope it's legal. David;706130 Wrote: Thanks Gary (i made sure to click the 'Yes' button) Here's my new code making use of your advice: Sub GETptNm() Dim txt As String Dim SourceRng As Range Dim ptRng As Range Dim rng As Range Dim pt As PivotTable Dim i As Integer Dim FirstComma As Integer Dim n As Integer '// get cell address for SERIES source data range within Pivot table '// from seriesCollection(1).Formula '// example: "=SERIES(PTs!$B$7,PTs!$A$8:$A$52,PTs!$B$8:$B$52,1) " txt = ActiveChart.SeriesCollection(1).Formula txt = Replace(txt, "=SERIES(", "") FirstComma = InStr(txt, ",") txt = Left(txt, FirstComma - 1) ' range address now identified '// Capture the range to enclose entire Pivot table Set SourceRng = Range(txt).CurrentRegion '// Test identified cell location against each pivot table n = PTs.PivotTables.Count '// 'PTs' is code name for sheet For i = 1 To n Set pt = PTs.PivotTables(i) Set ptRng = pt.TableRange2 Set rng = Intersect(SourceRng, ptRng) If Not rng Is Nothing Then ptNm = pt.Name Exit For End If Next i End Sub -- p45cal *p45cal* ------------------------------------------------------------------------ p45cal's Profile: http://www.thecodecage.com/forumz/member.php?u=558 View this thread: http://www.thecodecage.com/forumz/sh...d.php?t=196879 http://www.thecodecage.com/forumz . |
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