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I'd use:
Dim myChars as Variant dim cCtr as long mychars = array("$", "-") for cctr = lbound(mychars) to ubound(mychars) selection.replace what:=mychars(cctr), replacement:="", ..... next cctr Be careful. That $ could be used in formulas, too: =$a$1*c99 Not sure if that's a problem. joemeshuggah wrote: is it possible to do a find and replace with one statement using a variable? for example instead of: Selection.Replace What:="$", Replacement:="", LookAt:=xlPart, _ SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _ ReplaceFormat:=False Selection.Replace What:="-", Replacement:="", LookAt:=xlPart, _ SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _ ReplaceFormat:=False is it possible to use Selection.Replace What:=MyChar, Replacement:="", LookAt:=xlPart, _ SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _ ReplaceFormat:=False instead? or can you not assign more than one character to a variable? -- Dave Peterson |
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