Type mismatch probably comes from the fact you are using "int"

int = CInt()

Int is an intrinsic function in VB. You shouldn't name a variable "int"

As for the other problem use Mid not Right to get the remaining portion of
the string

if left(a,1)="-" then a=mid(a,2)

"Philosophaie" wrote:

I have a string:

string(3) = "543"

I try to change it to an integer:

int = cint(string(3))

It gives me a 'Type Mismatch' Error.

Maybe there may be spaces before of after the numbers but does that matter?

How do I change from a string to an integer?