Maybe...

dim iCtr as long
dim X as long

x = 99
for ictr = 1 to x
msgbox ictr
next ictr



KAH wrote:

Is there any way I can have a variable number of nested For ... Next loops?
In other words, I want x loops. If x=2 there would be 2 loops, if x=3, 3
loops.

This is a follow-up to a question I posted May 29 about all permutations.
The answer I got was helpful and gave me ideas but didn't actually solve my
problem. I realize what I really need to figure out is the variable number of
loops.

Thanks for any help.

--

Dave Peterson