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#1
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Counting conditionally
I have a table with a column that has data like this:
Gov Br SAP Br, SAP Comp Br, Gov Br, SAP Comp Br, SAP Is there a formula I can put in a cell at the bottom that will count the occurences of "Br" and return 5 rather than 2? Thanks in advance. |
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#2
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Counting conditionally
=COUNTIF(A1:A10,"=*Br*") -- Regards, OssieMac "Slim Slender" wrote: I have a table with a column that has data like this: Gov Br SAP Br, SAP Comp Br, Gov Br, SAP Comp Br, SAP Is there a formula I can put in a cell at the bottom that will count the occurences of "Br" and return 5 rather than 2? Thanks in advance. |
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#3
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Counting conditionally
Try this
=SUMPRODUCT((LEFT(A1:A10,2)="Br")*(1)) Mike "Slim Slender" wrote: I have a table with a column that has data like this: Gov Br SAP Br, SAP Comp Br, Gov Br, SAP Comp Br, SAP Is there a formula I can put in a cell at the bottom that will count the occurences of "Br" and return 5 rather than 2? Thanks in advance. |
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#4
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Counting conditionally
=SUMPRODUCT(--ISERROR(SEARCH("br",A1:A10)))
Regards, Stefi €˛Slim Slender€¯ ezt Ć*rta: I have a table with a column that has data like this: Gov Br SAP Br, SAP Comp Br, Gov Br, SAP Comp Br, SAP Is there a formula I can put in a cell at the bottom that will count the occurences of "Br" and return 5 rather than 2? Thanks in advance. |
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#5
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Counting conditionally
Sorry, this is the right one:
=SUMPRODUCT(--NOT(ISERROR(SEARCH("br",A1:A10)))) stefi €˛Slim Slender€¯ ezt Ć*rta: I have a table with a column that has data like this: Gov Br SAP Br, SAP Comp Br, Gov Br, SAP Comp Br, SAP Is there a formula I can put in a cell at the bottom that will count the occurences of "Br" and return 5 rather than 2? Thanks in advance. |
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#6
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Counting conditionally
Or
=SUMPRODUCT(1-ISERROR(SEARCH("br",A1:A10))) Regards, Bernd |
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#7
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Counting conditionally
On Apr 21, 8:02*am, Bernd P wrote:
Or =SUMPRODUCT(1-ISERROR(SEARCH("br",A1:A10))) Regards, Bernd Thanks to everyone for answers. Problem solved! |
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