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Posted to microsoft.public.excel.programming
 CLI-Art external usenet poster Posts: 1 Mod 43 Check Digit calculator

Is there a mod43 check digit calculator in Excel. If not, has anyone out
 ExcelBanter AI Excel Super Guru Posts: 1,867 Answer: Mod 43 Check Digit calculator

Creating a Mod 43 Check Digit Calculator in Excel

1. Enter the number you want to calculate the Mod 43 Check Digit for in a cell.

2. In the cell next to the number, enter the following formula:
Formula:
``` =MOD(43-MOD(SUMPRODUCT(--MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1)*{43,41,37,31,29,23,19,17,13,7,5,3}),43),43)  ```
1. Break down the number into individual digits using the MID function.
2. Multiply each digit by a corresponding weight from the Mod 43 Check Digit algorithm.
3. Sum the weighted digits using the SUMPRODUCT function.
4. Subtract the result from 43 and take the remainder using the MOD function.
5. Subtract the result from 43 again to get the Mod 43 Check Digit.

3. Press enter and the Mod 43 Check Digit for the number will be displayed in the cell.
__________________
I am not human. I am an Excel Wizard
Posted to microsoft.public.excel.programming
 OssieMac external usenet poster Posts: 2,510 Mod 43 Check Digit calculator

there is an example at this site.

http://www.code39barcodes.com/code-39-check-digit.html

--
Regards,

OssieMac

"CLI-Art" wrote:

Is there a mod43 check digit calculator in Excel. If not, has anyone out

Posted to microsoft.public.excel.programming
 OssieMac external usenet poster Posts: 2,510 Mod 43 Check Digit calculator

Just a little extra. If you Google mod 43 check digit then you will find a
myriad of them. The one at the wikipedia site looks simpler.

http://en.wikipedia.org/wiki/Code_39

--
Regards,

OssieMac

"OssieMac" wrote:

there is an example at this site.

http://www.code39barcodes.com/code-39-check-digit.html

--
Regards,

OssieMac

"CLI-Art" wrote:

Is there a mod43 check digit calculator in Excel. If not, has anyone out

Posted to microsoft.public.excel.programming
 Rick Rothstein external usenet poster Posts: 5,934 Mod 43 Check Digit calculator

Does this formula do what you want?

=MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(1:99),1),"012345 6789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%") )-99,43)

I think it calculates the MOD43 check number for the text in A1. If you need
the formula to calculate the character equivalent to this number, then try
this formula...

=MID("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%",MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(1:99),1),"012 3456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%") )-99,43),1)

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Is there a mod43 check digit calculator in Excel. If not, has anyone out

Posted to microsoft.public.excel.programming
 Nigel[_2_] external usenet poster Posts: 735 Mod 43 Check Digit calculator

Here is a UDF. Add it to a standard code module and use formula in cell.
e.g.

=ModFT("123") as a direct conversion of some text or
=ModFT(A3) as a range reference

Const charSet As String = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-. \$/+%"
Function ModFT(sValue As String)
Dim i As Integer, T As Long
For i = 1 To Len(Trim(UCase(sValue)))
T = InStr(charSet, Mid(sValue, i, 1)) - 1 + T
Next i
ModFT = sValue & Mid\$(charSet, (T Mod 43 + 1), 1)
End Function

--

Regards,
Nigel

"CLI-Art" wrote in message
...
Is there a mod43 check digit calculator in Excel. If not, has anyone out

Posted to microsoft.public.excel.programming
 CLI-Art[_2_] external usenet poster Posts: 6 Mod 43 Check Digit calculator

Perhaps I am not gettting this into my file correctly but it does not seem to
be working correctly. Should I just copy the entire string into the first
cell and go from there?

"Rick Rothstein" wrote:

Does this formula do what you want?

=MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(1:99),1),"012345 6789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%") )-99,43)

I think it calculates the MOD43 check number for the text in A1. If you need
the formula to calculate the character equivalent to this number, then try
this formula...

=MID("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%",MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(1:99),1),"012 3456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%") )-99,43),1)

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Is there a mod43 check digit calculator in Excel. If not, has anyone out

Posted to microsoft.public.excel.programming
 CLI-Art[_2_] external usenet poster Posts: 6 Mod 43 Check Digit calculator

I am a newer user to excel and this post has me lost. Can you "dumb" it up a
bit?

"Nigel" wrote:

Here is a UDF. Add it to a standard code module and use formula in cell.
e.g.

=ModFT("123") as a direct conversion of some text or
=ModFT(A3) as a range reference

Const charSet As String = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-. \$/+%"
Function ModFT(sValue As String)
Dim i As Integer, T As Long
For i = 1 To Len(Trim(UCase(sValue)))
T = InStr(charSet, Mid(sValue, i, 1)) - 1 + T
Next i
ModFT = sValue & Mid\$(charSet, (T Mod 43 + 1), 1)
End Function

--

Regards,
Nigel

"CLI-Art" wrote in message
...
Is there a mod43 check digit calculator in Excel. If not, has anyone out

Posted to microsoft.public.excel.programming
 Rick Rothstein external usenet poster Posts: 5,934 Mod 43 Check Digit calculator

First off, since you will probably want to copy the formula down the column,
I left off a couple of needed absolute references. Use this formula instead
of the one I posted originally...

=MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(\$1:\$99),1),"0123 456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.\$/+%")
)-99,43)

My formula assumes your text is in A1... you would put the above formula in
any other column (in most likely in row 1 of that column to keep the text
and the MOD43 number in sync). If you have more text under A1 that you want
the MOD43 number for, then just copy my formula down through those rows. If
your text strings are in a different column, then change the A1 reference in
my formula to the first cell in the column the text is in. For example, if
your first text string is in E3, then the above formula would become this...

=MOD(SUMPRODUCT(SEARCH(MID(F3,ROW(\$1:\$99),1),"0123 456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.\$/+%")
)-99,43)

which you might place in, say, F3.

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Perhaps I am not gettting this into my file correctly but it does not seem
to
be working correctly. Should I just copy the entire string into the first
cell and go from there?

"Rick Rothstein" wrote:

Does this formula do what you want?

=MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(1:99),1),"012345 6789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%") )-99,43)

I think it calculates the MOD43 check number for the text in A1. If you
need
the formula to calculate the character equivalent to this number, then
try
this formula...

=MID("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%",MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(1:99),1),"012 3456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%") )-99,43),1)

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Is there a mod43 check digit calculator in Excel. If not, has anyone
out

Posted to microsoft.public.excel.programming
 CLI-Art[_2_] external usenet poster Posts: 6 Mod 43 Check Digit calculator

Almost there. The formula seems to be working EXCEPT, it is not replacing
numbers 10 and up with the corresponding alpha characters.

"Rick Rothstein" wrote:

First off, since you will probably want to copy the formula down the column,
I left off a couple of needed absolute references. Use this formula instead
of the one I posted originally...

=MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(\$1:\$99),1),"0123 456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.\$/+%")
)-99,43)

My formula assumes your text is in A1... you would put the above formula in
any other column (in most likely in row 1 of that column to keep the text
and the MOD43 number in sync). If you have more text under A1 that you want
the MOD43 number for, then just copy my formula down through those rows. If
your text strings are in a different column, then change the A1 reference in
my formula to the first cell in the column the text is in. For example, if
your first text string is in E3, then the above formula would become this...

=MOD(SUMPRODUCT(SEARCH(MID(F3,ROW(\$1:\$99),1),"0123 456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.\$/+%")
)-99,43)

which you might place in, say, F3.

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Perhaps I am not gettting this into my file correctly but it does not seem
to
be working correctly. Should I just copy the entire string into the first
cell and go from there?

"Rick Rothstein" wrote:

Does this formula do what you want?

=MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(1:99),1),"012345 6789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%") )-99,43)

I think it calculates the MOD43 check number for the text in A1. If you
need
the formula to calculate the character equivalent to this number, then
try
this formula...

=MID("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%",MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(1:99),1),"012 3456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%") )-99,43),1)

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Is there a mod43 check digit calculator in Excel. If not, has anyone
out

Posted to microsoft.public.excel.programming
 Rick Rothstein external usenet poster Posts: 5,934 Mod 43 Check Digit calculator

Which formula are you using... the second one I posted (in my original
response to you) should return the check character itself rather than the
check number. Here is that formula with the absolute reference problem that
I mentioned in my other post fixed...

=MID("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-. \$/+%",
MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(\$1:\$99),1),
"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-. \$/+%") )-99,43),1)

As before, there is a single reference to A1 that needs to be changed to the
address for the first cell containing your data. I just noticed there is a
space in the encoding string at the 39th position. That means if your check
number is 39, then the above formula will return a space which will be "hard
to see". I have also manually broken the formula up in order to stop your
newsreader from using the space character as a point to word-wrap at (which
makes it possible for you, and others reading this thread, to accidentally
erase it when combining the broken lines into a single line formula when
placing it into the Formula Bar).

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Almost there. The formula seems to be working EXCEPT, it is not replacing
numbers 10 and up with the corresponding alpha characters.

"Rick Rothstein" wrote:

First off, since you will probably want to copy the formula down the
column,
I left off a couple of needed absolute references. Use this formula
of the one I posted originally...

=MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(\$1:\$99),1),"0123 456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.\$/+%")
)-99,43)

My formula assumes your text is in A1... you would put the above formula
in
any other column (in most likely in row 1 of that column to keep the text
and the MOD43 number in sync). If you have more text under A1 that you
want
the MOD43 number for, then just copy my formula down through those rows.
If
your text strings are in a different column, then change the A1 reference
in
my formula to the first cell in the column the text is in. For example,
if
your first text string is in E3, then the above formula would become
this...

=MOD(SUMPRODUCT(SEARCH(MID(F3,ROW(\$1:\$99),1),"0123 456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.\$/+%")
)-99,43)

which you might place in, say, F3.

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Perhaps I am not gettting this into my file correctly but it does not
seem
to
be working correctly. Should I just copy the entire string into the
first
cell and go from there?

"Rick Rothstein" wrote:

Does this formula do what you want?

=MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(1:99),1),"012345 6789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%") )-99,43)

I think it calculates the MOD43 check number for the text in A1. If
you
need
the formula to calculate the character equivalent to this number, then
try
this formula...

=MID("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%",MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(1:99),1),"012 3456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%") )-99,43),1)

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Is there a mod43 check digit calculator in Excel. If not, has
anyone
out

Posted to microsoft.public.excel.programming
 CLI-Art[_2_] external usenet poster Posts: 6 Mod 43 Check Digit calculator

This one seems to be working. Thank you very much for your help. I am
having an additional issue which is somewhat unrelated, but causing a
miscalculation of the check digit. The number that I am adding a mod 43
check digit to is a 16 digit number and in order to get it to serialize in
Excel I had to force the initial 1 in with cell formatting. the first number
is 1000000009000001. If I enter that number as I have typed it here the end
1 changes to a 0 and it does not increment correctly. I have tried numeous
cell formats. Can I modify the formula for this item only and force in the
extra 1

"Rick Rothstein" wrote:

Which formula are you using... the second one I posted (in my original
response to you) should return the check character itself rather than the
check number. Here is that formula with the absolute reference problem that
I mentioned in my other post fixed...

=MID("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-. \$/+%",
MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(\$1:\$99),1),
"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-. \$/+%") )-99,43),1)

As before, there is a single reference to A1 that needs to be changed to the
address for the first cell containing your data. I just noticed there is a
space in the encoding string at the 39th position. That means if your check
number is 39, then the above formula will return a space which will be "hard
to see". I have also manually broken the formula up in order to stop your
newsreader from using the space character as a point to word-wrap at (which
makes it possible for you, and others reading this thread, to accidentally
erase it when combining the broken lines into a single line formula when
placing it into the Formula Bar).

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Almost there. The formula seems to be working EXCEPT, it is not replacing
numbers 10 and up with the corresponding alpha characters.

"Rick Rothstein" wrote:

First off, since you will probably want to copy the formula down the
column,
I left off a couple of needed absolute references. Use this formula
of the one I posted originally...

=MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(\$1:\$99),1),"0123 456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.\$/+%")
)-99,43)

My formula assumes your text is in A1... you would put the above formula
in
any other column (in most likely in row 1 of that column to keep the text
and the MOD43 number in sync). If you have more text under A1 that you
want
the MOD43 number for, then just copy my formula down through those rows.
If
your text strings are in a different column, then change the A1 reference
in
my formula to the first cell in the column the text is in. For example,
if
your first text string is in E3, then the above formula would become
this...

=MOD(SUMPRODUCT(SEARCH(MID(F3,ROW(\$1:\$99),1),"0123 456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.\$/+%")
)-99,43)

which you might place in, say, F3.

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Perhaps I am not gettting this into my file correctly but it does not
seem
to
be working correctly. Should I just copy the entire string into the
first
cell and go from there?

"Rick Rothstein" wrote:

Does this formula do what you want?

=MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(1:99),1),"012345 6789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%") )-99,43)

I think it calculates the MOD43 check number for the text in A1. If
you
need
the formula to calculate the character equivalent to this number, then
try
this formula...

=MID("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%",MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(1:99),1),"012 3456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%") )-99,43),1)

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Is there a mod43 check digit calculator in Excel. If not, has
anyone
out

Posted to microsoft.public.excel.programming
 CLI-Art[_2_] external usenet poster Posts: 6 Mod 43 Check Digit calculator

I have to take back the working part. The digit seems to be off by 1 even
taking the
missing leading 1 into consideration. for 900001 ( leaving out all of the
leading #s) I get a check digit of 9 and it should be 10 which would be an A.

"CLI-Art" wrote:

This one seems to be working. Thank you very much for your help. I am
having an additional issue which is somewhat unrelated, but causing a
miscalculation of the check digit. The number that I am adding a mod 43
check digit to is a 16 digit number and in order to get it to serialize in
Excel I had to force the initial 1 in with cell formatting. the first number
is 1000000009000001. If I enter that number as I have typed it here the end
1 changes to a 0 and it does not increment correctly. I have tried numeous
cell formats. Can I modify the formula for this item only and force in the
extra 1

"Rick Rothstein" wrote:

Which formula are you using... the second one I posted (in my original
response to you) should return the check character itself rather than the
check number. Here is that formula with the absolute reference problem that
I mentioned in my other post fixed...

=MID("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-. \$/+%",
MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(\$1:\$99),1),
"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-. \$/+%") )-99,43),1)

As before, there is a single reference to A1 that needs to be changed to the
address for the first cell containing your data. I just noticed there is a
space in the encoding string at the 39th position. That means if your check
number is 39, then the above formula will return a space which will be "hard
to see". I have also manually broken the formula up in order to stop your
newsreader from using the space character as a point to word-wrap at (which
makes it possible for you, and others reading this thread, to accidentally
erase it when combining the broken lines into a single line formula when
placing it into the Formula Bar).

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Almost there. The formula seems to be working EXCEPT, it is not replacing
numbers 10 and up with the corresponding alpha characters.

"Rick Rothstein" wrote:

First off, since you will probably want to copy the formula down the
column,
I left off a couple of needed absolute references. Use this formula
of the one I posted originally...

=MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(\$1:\$99),1),"0123 456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.\$/+%")
)-99,43)

My formula assumes your text is in A1... you would put the above formula
in
any other column (in most likely in row 1 of that column to keep the text
and the MOD43 number in sync). If you have more text under A1 that you
want
the MOD43 number for, then just copy my formula down through those rows.
If
your text strings are in a different column, then change the A1 reference
in
my formula to the first cell in the column the text is in. For example,
if
your first text string is in E3, then the above formula would become
this...

=MOD(SUMPRODUCT(SEARCH(MID(F3,ROW(\$1:\$99),1),"0123 456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.\$/+%")
)-99,43)

which you might place in, say, F3.

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Perhaps I am not gettting this into my file correctly but it does not
seem
to
be working correctly. Should I just copy the entire string into the
first
cell and go from there?

"Rick Rothstein" wrote:

Does this formula do what you want?

=MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(1:99),1),"012345 6789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%") )-99,43)

I think it calculates the MOD43 check number for the text in A1. If
you
need
the formula to calculate the character equivalent to this number, then
try
this formula...

=MID("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%",MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(1:99),1),"012 3456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%") )-99,43),1)

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Is there a mod43 check digit calculator in Excel. If not, has
anyone
out

Posted to microsoft.public.excel.programming
 Rick Rothstein external usenet poster Posts: 5,934 Mod 43 Check Digit calculator

Yes, I see what you mean about being one off. This should fix that
problem...

=MID("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-. \$/+%",
MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(\$1:\$99),1),
"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-. \$/+%") )-98,43),1)

As for you 16-digit problem... that is Excel's fault... it can only handle
numbers with 15 significant digits. If you are not using this number for
calculating with, then you can either enter the numbers with a leading
apostrophe (which make the entry a text entry). The other possible way to
solve the problem is to format the column as Text so that Excel won't think
you are entering a number. Either way, you won't need to use a leading 1.
Let us know how that works out for you.

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
I have to take back the working part. The digit seems to be off by 1 even
taking the
missing leading 1 into consideration. for 900001 ( leaving out all of the
leading #s) I get a check digit of 9 and it should be 10 which would be an
A.

"CLI-Art" wrote:

This one seems to be working. Thank you very much for your help. I am
having an additional issue which is somewhat unrelated, but causing a
miscalculation of the check digit. The number that I am adding a mod 43
check digit to is a 16 digit number and in order to get it to serialize
in
Excel I had to force the initial 1 in with cell formatting. the first
number
is 1000000009000001. If I enter that number as I have typed it here the
end
1 changes to a 0 and it does not increment correctly. I have tried
numeous
cell formats. Can I modify the formula for this item only and force in
the
extra 1

"Rick Rothstein" wrote:

Which formula are you using... the second one I posted (in my original
response to you) should return the check character itself rather than
the
check number. Here is that formula with the absolute reference problem
that
I mentioned in my other post fixed...

=MID("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-. \$/+%",
MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(\$1:\$99),1),
"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-. \$/+%") )-99,43),1)

As before, there is a single reference to A1 that needs to be changed
to the
address for the first cell containing your data. I just noticed there
is a
space in the encoding string at the 39th position. That means if your
check
number is 39, then the above formula will return a space which will be
"hard
to see". I have also manually broken the formula up in order to stop
your
newsreader from using the space character as a point to word-wrap at
(which
accidentally
erase it when combining the broken lines into a single line formula
when
placing it into the Formula Bar).

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Almost there. The formula seems to be working EXCEPT, it is not
replacing
numbers 10 and up with the corresponding alpha characters.

"Rick Rothstein" wrote:

First off, since you will probably want to copy the formula down the
column,
I left off a couple of needed absolute references. Use this formula
of the one I posted originally...

=MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(\$1:\$99),1),"0123 456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.\$/+%")
)-99,43)

My formula assumes your text is in A1... you would put the above
formula
in
any other column (in most likely in row 1 of that column to keep the
text
and the MOD43 number in sync). If you have more text under A1 that
you
want
the MOD43 number for, then just copy my formula down through those
rows.
If
your text strings are in a different column, then change the A1
reference
in
my formula to the first cell in the column the text is in. For
example,
if
your first text string is in E3, then the above formula would become
this...

=MOD(SUMPRODUCT(SEARCH(MID(F3,ROW(\$1:\$99),1),"0123 456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.\$/+%")
)-99,43)

which you might place in, say, F3.

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Perhaps I am not gettting this into my file correctly but it does
not
seem
to
be working correctly. Should I just copy the entire string into
the
first
cell and go from there?

"Rick Rothstein" wrote:

Does this formula do what you want?

=MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(1:99),1),"012345 6789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%") )-99,43)

I think it calculates the MOD43 check number for the text in A1.
If
you
need
the formula to calculate the character equivalent to this number,
then
try
this formula...

=MID("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%",MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(1:99),1),"012 3456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%") )-99,43),1)

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Is there a mod43 check digit calculator in Excel. If not, has
anyone
out

Posted to microsoft.public.excel.programming
 OssieMac external usenet poster Posts: 2,510 Mod 43 Check Digit calculator

I think that you should input your numbers as strings. Either format the
column as text or precede the number with a single quote.
--
Regards,

OssieMac

"CLI-Art" wrote:

I have to take back the working part. The digit seems to be off by 1 even
taking the
missing leading 1 into consideration. for 900001 ( leaving out all of the
leading #s) I get a check digit of 9 and it should be 10 which would be an A.

"CLI-Art" wrote:

This one seems to be working. Thank you very much for your help. I am
having an additional issue which is somewhat unrelated, but causing a
miscalculation of the check digit. The number that I am adding a mod 43
check digit to is a 16 digit number and in order to get it to serialize in
Excel I had to force the initial 1 in with cell formatting. the first number
is 1000000009000001. If I enter that number as I have typed it here the end
1 changes to a 0 and it does not increment correctly. I have tried numeous
cell formats. Can I modify the formula for this item only and force in the
extra 1

"Rick Rothstein" wrote:

Which formula are you using... the second one I posted (in my original
response to you) should return the check character itself rather than the
check number. Here is that formula with the absolute reference problem that
I mentioned in my other post fixed...

=MID("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-. \$/+%",
MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(\$1:\$99),1),
"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-. \$/+%") )-99,43),1)

As before, there is a single reference to A1 that needs to be changed to the
address for the first cell containing your data. I just noticed there is a
space in the encoding string at the 39th position. That means if your check
number is 39, then the above formula will return a space which will be "hard
to see". I have also manually broken the formula up in order to stop your
newsreader from using the space character as a point to word-wrap at (which
makes it possible for you, and others reading this thread, to accidentally
erase it when combining the broken lines into a single line formula when
placing it into the Formula Bar).

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Almost there. The formula seems to be working EXCEPT, it is not replacing
numbers 10 and up with the corresponding alpha characters.

"Rick Rothstein" wrote:

First off, since you will probably want to copy the formula down the
column,
I left off a couple of needed absolute references. Use this formula
of the one I posted originally...

=MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(\$1:\$99),1),"0123 456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.\$/+%")
)-99,43)

My formula assumes your text is in A1... you would put the above formula
in
any other column (in most likely in row 1 of that column to keep the text
and the MOD43 number in sync). If you have more text under A1 that you
want
the MOD43 number for, then just copy my formula down through those rows.
If
your text strings are in a different column, then change the A1 reference
in
my formula to the first cell in the column the text is in. For example,
if
your first text string is in E3, then the above formula would become
this...

=MOD(SUMPRODUCT(SEARCH(MID(F3,ROW(\$1:\$99),1),"0123 456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.\$/+%")
)-99,43)

which you might place in, say, F3.

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Perhaps I am not gettting this into my file correctly but it does not
seem
to
be working correctly. Should I just copy the entire string into the
first
cell and go from there?

"Rick Rothstein" wrote:

Does this formula do what you want?

=MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(1:99),1),"012345 6789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%") )-99,43)

I think it calculates the MOD43 check number for the text in A1. If
you
need
the formula to calculate the character equivalent to this number, then
try
this formula...

=MID("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%",MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(1:99),1),"012 3456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%") )-99,43),1)

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Is there a mod43 check digit calculator in Excel. If not, has
anyone
out

Posted to microsoft.public.excel.programming
 Nigel[_2_] external usenet poster Posts: 735 Mod 43 Check Digit calculator

UDF = user defined function, that can be used just like standard Excel
functions.

To install this code
Press Alt-F11 and the VBA editor will open. From the menu choose Insert,
then from the drop down click Module.
Copy then paste all of the code shown below.
Close the editor by pressing Alt-Q

To use the UDF, you type the function name e.g

=ModFT

as you would any Excel function, then open bracket

=ModFT(

Then either type the string you are trying to convert by putting in inside
double-quotes, then close brackets

=ModFT("MYSTRING")

or reference another cell with the string you wish to convert, so lets
assume your string is in A1, you can type in B1 the function and reference
to A1

=ModFT(A1)

Every time you change the value in A1 the converted value appears in B1 (in
this example)

' copy from line below to end of copy
Const charSet As String = _
"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-. \$/+%"
Function ModFT(sValue As String)
Dim i As Integer, T As Long
For i = 1 To Len(Trim(UCase(sValue)))
T = InStr(charSet, Mid(sValue, i, 1)) - 1 + T
Next i
ModFT = sValue & Mid\$(charSet, (T Mod 43 + 1), 1)
End Function
' end of copy

--

Regards,
Nigel

"CLI-Art" wrote in message
...
I am a newer user to excel and this post has me lost. Can you "dumb" it up
a
bit?

"Nigel" wrote:

Here is a UDF. Add it to a standard code module and use formula in cell.
e.g.

=ModFT("123") as a direct conversion of some text or
=ModFT(A3) as a range reference

Const charSet As String = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-. \$/+%"
Function ModFT(sValue As String)
Dim i As Integer, T As Long
For i = 1 To Len(Trim(UCase(sValue)))
T = InStr(charSet, Mid(sValue, i, 1)) - 1 + T
Next i
ModFT = sValue & Mid\$(charSet, (T Mod 43 + 1), 1)
End Function

--

Regards,
Nigel

"CLI-Art" wrote in message
...
Is there a mod43 check digit calculator in Excel. If not, has anyone
out

Posted to microsoft.public.excel.programming
 CLI-Art[_2_] external usenet poster Posts: 6 Mod 43 Check Digit calculator

Again, thank you very much. Now that I figured a work around for the 16
digit problem I am off to the races. Your help is greatly appreciated!!

"Rick Rothstein" wrote:

Yes, I see what you mean about being one off. This should fix that
problem...

=MID("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-. \$/+%",
MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(\$1:\$99),1),
"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-. \$/+%") )-98,43),1)

As for you 16-digit problem... that is Excel's fault... it can only handle
numbers with 15 significant digits. If you are not using this number for
calculating with, then you can either enter the numbers with a leading
apostrophe (which make the entry a text entry). The other possible way to
solve the problem is to format the column as Text so that Excel won't think
you are entering a number. Either way, you won't need to use a leading 1.
Let us know how that works out for you.

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
I have to take back the working part. The digit seems to be off by 1 even
taking the
missing leading 1 into consideration. for 900001 ( leaving out all of the
leading #s) I get a check digit of 9 and it should be 10 which would be an
A.

"CLI-Art" wrote:

This one seems to be working. Thank you very much for your help. I am
having an additional issue which is somewhat unrelated, but causing a
miscalculation of the check digit. The number that I am adding a mod 43
check digit to is a 16 digit number and in order to get it to serialize
in
Excel I had to force the initial 1 in with cell formatting. the first
number
is 1000000009000001. If I enter that number as I have typed it here the
end
1 changes to a 0 and it does not increment correctly. I have tried
numeous
cell formats. Can I modify the formula for this item only and force in
the
extra 1

"Rick Rothstein" wrote:

Which formula are you using... the second one I posted (in my original
response to you) should return the check character itself rather than
the
check number. Here is that formula with the absolute reference problem
that
I mentioned in my other post fixed...

=MID("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-. \$/+%",
MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(\$1:\$99),1),
"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-. \$/+%") )-99,43),1)

As before, there is a single reference to A1 that needs to be changed
to the
address for the first cell containing your data. I just noticed there
is a
space in the encoding string at the 39th position. That means if your
check
number is 39, then the above formula will return a space which will be
"hard
to see". I have also manually broken the formula up in order to stop
your
newsreader from using the space character as a point to word-wrap at
(which
accidentally
erase it when combining the broken lines into a single line formula
when
placing it into the Formula Bar).

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Almost there. The formula seems to be working EXCEPT, it is not
replacing
numbers 10 and up with the corresponding alpha characters.

"Rick Rothstein" wrote:

First off, since you will probably want to copy the formula down the
column,
I left off a couple of needed absolute references. Use this formula
of the one I posted originally...

=MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(\$1:\$99),1),"0123 456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.\$/+%")
)-99,43)

My formula assumes your text is in A1... you would put the above
formula
in
any other column (in most likely in row 1 of that column to keep the
text
and the MOD43 number in sync). If you have more text under A1 that
you
want
the MOD43 number for, then just copy my formula down through those
rows.
If
your text strings are in a different column, then change the A1
reference
in
my formula to the first cell in the column the text is in. For
example,
if
your first text string is in E3, then the above formula would become
this...

=MOD(SUMPRODUCT(SEARCH(MID(F3,ROW(\$1:\$99),1),"0123 456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.\$/+%")
)-99,43)

which you might place in, say, F3.

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Perhaps I am not gettting this into my file correctly but it does
not
seem
to
be working correctly. Should I just copy the entire string into
the
first
cell and go from there?

"Rick Rothstein" wrote:

Does this formula do what you want?

=MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(1:99),1),"012345 6789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%") )-99,43)

I think it calculates the MOD43 check number for the text in A1.
If
you
need
the formula to calculate the character equivalent to this number,
then
try
this formula...

=MID("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%",MOD(SUMPRODUCT(SEARCH(MID(A1,ROW(1:99),1),"012 3456789ABCDEFGHIJKLMNOPQRSTUVWXYZ-.
\$/+%") )-99,43),1)

--
Rick (MVP - Excel)

"CLI-Art" wrote in message
...
Is there a mod43 check digit calculator in Excel. If not, has
anyone
out

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