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#1
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test for number
Hi,
In VBA, if I want to test a cell to see if it contains a formula, I use the HasFormula property. How do I test for a cell to see if contains a number (without using the ISNUMBER worksheet function)? Help has not been helpful. Regards - Dave. |
#2
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test for number
You could use:
if isnumeric(myCell.value) then but isnumeric is pretty forgiving. Values that could be interpreted as a number (empty cells, or cells that contain text that looks like numbers: '123 or 1E5) will be called a number. If you want the same stringent test as you get with the worksheet function =isnumber(), you could use: if application.isnumber(mycell.value) then Dave wrote: Hi, In VBA, if I want to test a cell to see if it contains a formula, I use the HasFormula property. How do I test for a cell to see if contains a number (without using the ISNUMBER worksheet function)? Help has not been helpful. Regards - Dave. -- Dave Peterson |
#3
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test for number
Hi Dave,
OK, thanks. Looks like it'll have to be the worksheet function. Regards - Dave. |
#4
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test for number
OK, thanks. Looks like it'll have to be the worksheet function.
Here is something you may want to consider. It is from a previous posting of mine over in the compiled VB newsgroups. Initially, it deals with the problems associated with the IsNumeric function built into VB (and to which Dave alluded to in his post); afterwards, it gives a couple of VB functions you can use within your own code to "proof" numbers as being numbers (note, they return false for E-notation numbers such as 12E34... it is only for digits and/or digits plus decimal point and optional plus/minus signs). Anyway, here is is for your consideration... Rick From a previous post of mine... I usually try and steer people away from using IsNumeric to "proof" supposedly numeric text. Consider this (also see note below): ReturnValue = IsNumeric("($1,23,,3.4,,,5,,E67$)") Most people would not expect THAT to return True. IsNumeric has some "flaws" in what it considers a proper number and what most programmers are looking for. I had a short tip published by Pinnacle Publishing in their Visual Basic Developer magazine that covered some of these flaws. Originally, the tip was free to view but is now viewable only by subscribers.. Basically, it said that IsNumeric returned True for things like -- currency symbols being located in front or in back of the number as shown in my example (also applies to plus, minus and blanks too); numbers surrounded by parentheses as shown in my example (some people use these to mark negative numbers); numbers containing any number of commas before a decimal point as shown in my example; numbers in scientific notation (a number followed by an upper or lower case "D" or "E", followed by a number equal to or less than 305 -- the maximum power of 10 in VB); and Octal/Hexadecimal numbers (&H for Hexadecimal, &O or just & in front of the number for Octal). NOTE: ====== In the above example and in the referenced tip, I refer to $ signs and commas and dots -- these were meant to refer to your currency, thousands separator and decimal point symbols as defined in your local settings -- substitute your local regional symbols for these if appropriate. As for your question about checking numbers, here are two functions that I have posted in the past for similar questions..... one is for digits only and the other is for "regular" numbers: Function IsDigitsOnly(Value As String) As Boolean IsDigitsOnly = Len(Value) 0 And _ Not Value Like "*[!0-9]*" End Function Function IsNumber(ByVal Value As String) As Boolean ' Leave the next statement out if you don't ' want to provide for plus/minus signs If Value Like "[+-]*" Then Value = Mid$(Value, 2) IsNumber = Not Value Like "*[!0-9.]*" And _ Not Value Like "*.*.*" And _ Len(Value) 0 And Value < "." And _ Value < vbNullString End Function Here are revisions to the above functions that deal with the local settings for decimal points (and thousand's separators) that are different than used in the US (this code works in the US too, of course). Function IsNumber(ByVal Value As String) As Boolean Dim DP As String ' Get local setting for decimal point DP = Format$(0, ".") ' Leave the next statement out if you don't ' want to provide for plus/minus signs If Value Like "[+-]*" Then Value = Mid$(Value, 2) IsNumber = Not Value Like "*[!0-9" & DP & "]*" And _ Not Value Like "*" & DP & "*" & DP & "*" And _ Len(Value) 0 And Value < DP And _ Value < vbNullString End Function I'm not as concerned by the rejection of entries that include one or more thousand's separators, but we can handle this if we don't insist on the thousand's separator being located in the correct positions (in other words, we'll allow the user to include them for their own purposes... we'll just tolerate their presence). Function IsNumber(ByVal Value As String) As Boolean Dim DP As String Dim TS As String ' Get local setting for decimal point DP = Format$(0, ".") ' Get local setting for thousand's separator ' and eliminate them. Remove the next two lines ' if you don't want your users being able to ' type in the thousands separator at all. TS = Mid$(Format$(1000, "#,###"), 2, 1) Value = Replace$(Value, TS, "") ' Leave the next statement out if you don't ' want to provide for plus/minus signs If Value Like "[+-]*" Then Value = Mid$(Value, 2) IsNumber = Not Value Like "*[!0-9" & DP & "]*" And _ Not Value Like "*" & DP & "*" & DP & "*" And _ Len(Value) 0 And Value < DP And _ Value < vbNullString End Function |
#5
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test for number
Hi Rick, Thanks for that. And there I was thinking I'd asked such a simple
question... Dave. |
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