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Greetings, I'm sure the solution to this, is easier than I think, but for the
life of me I can't figure this out. I have two variables of data type Date. DateFrom DateTo I'm attempting to get it so I can work out how many days there are between these two dates. DateFrom = 01/04/08 DateTo = 04/04/08 The Result should be 4. I was thinking just grab the Day from the date and that'd be easy, but the problem arises when you have dates that span a few months in distance. Thank you for any help thrown in this general direction :) . |
#2
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Maybe
datefrom = #4/1/2008# dateto = #4/4/2008# diffference = dateto - datefrom + 1 Mike "NateBuckley" wrote: Greetings, I'm sure the solution to this, is easier than I think, but for the life of me I can't figure this out. I have two variables of data type Date. DateFrom DateTo I'm attempting to get it so I can work out how many days there are between these two dates. DateFrom = 01/04/08 DateTo = 04/04/08 The Result should be 4. I was thinking just grab the Day from the date and that'd be easy, but the problem arises when you have dates that span a few months in distance. Thank you for any help thrown in this general direction :) . |
#3
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What does the hash character mean?
And That worked great cheers :) "Mike H" wrote: Maybe datefrom = #4/1/2008# dateto = #4/4/2008# diffference = dateto - datefrom + 1 Mike "NateBuckley" wrote: Greetings, I'm sure the solution to this, is easier than I think, but for the life of me I can't figure this out. I have two variables of data type Date. DateFrom DateTo I'm attempting to get it so I can work out how many days there are between these two dates. DateFrom = 01/04/08 DateTo = 04/04/08 The Result should be 4. I was thinking just grab the Day from the date and that'd be easy, but the problem arises when you have dates that span a few months in distance. Thank you for any help thrown in this general direction :) . |
#4
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It's part of the syntax for formatting a user date in VB
"NateBuckley" wrote: What does the hash character mean? And That worked great cheers :) "Mike H" wrote: Maybe datefrom = #4/1/2008# dateto = #4/4/2008# diffference = dateto - datefrom + 1 Mike "NateBuckley" wrote: Greetings, I'm sure the solution to this, is easier than I think, but for the life of me I can't figure this out. I have two variables of data type Date. DateFrom DateTo I'm attempting to get it so I can work out how many days there are between these two dates. DateFrom = 01/04/08 DateTo = 04/04/08 The Result should be 4. I was thinking just grab the Day from the date and that'd be easy, but the problem arises when you have dates that span a few months in distance. Thank you for any help thrown in this general direction :) . |
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