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Hi all,
I have a workbook that has been running fine for a very long time. Last week I noticed that all of a sudden I am getting an error that states "Code execution has been interrupted". The macro still completes the operation, but the error box comes up. I have not altered the code in any way for quite some time, but this error mysteriously started happening last week seemingly out of the blue. Any clues as to what it could be and fixes for this? Public Sub Print_Visible_Worksheets() Application.ScreenUpdating = False Dim sh As Worksheet Dim arr() As String Dim N As Long Const sStr As String = "Main" For Each sh In ThisWorkbook.Worksheets With sh If .Visible = xlSheetVisible Then If StrComp(.Name, sStr, vbTextCompare) Then N = N + 1 ReDim Preserve arr(1 To N) arr(N) = .Name End If End If End With Next sh With ThisWorkbook .Worksheets(arr).PrintOut .Worksheets(1).Select <-----ERROR IS ON THIS LINE End With Application.ScreenUpdating = True End Sub |
#2
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Hi Tom
Try placing the following line at the start of your code (after your sub name): Application.EnableCancelKey = xlDisabled and see if the error goes away. Richard On 4 Feb, 11:24, Tom wrote: Hi all, I have a workbook that has been running fine for a very long time. Last week I noticed that all of a sudden I am getting an error that states "Code execution has been interrupted". The macro still completes the operation, but the error box comes up. I have not altered the code in any way for quite some time, but this error mysteriously started happening last week seemingly out of the blue. Any clues as to what it could be and fixes for this? Public Sub Print_Visible_Worksheets() * * Application.ScreenUpdating = False * * Dim sh As Worksheet * * Dim arr() As String * * Dim N As Long * * Const sStr As String = "Main" * * For Each sh In ThisWorkbook.Worksheets * * * * With sh * * * * * * If .Visible = xlSheetVisible Then * * * * * * * * If StrComp(.Name, sStr, vbTextCompare) Then * * * * * * * * * * N = N + 1 * * * * * * * * * * ReDim Preserve arr(1 To N) * * * * * * * * * * arr(N) = .Name * * * * * * * * End If * * * * * * End If * * * * End With * * Next sh * * With ThisWorkbook * * * * .Worksheets(arr).PrintOut * * * * .Worksheets(1).Select *<-----ERROR IS ON THIS LINE * * End With * * Application.ScreenUpdating = True End Sub |
#3
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Hi Richard,
That seems to fix the problem. Now, in order that I can understand this....WHY would this fix the problem...and why, all of a sudden, would it start causing a problem to begin with? I have had this macro written for almost a year without this error...so why did it start all of a sudden? "RichardSchollar" wrote: Hi Tom Try placing the following line at the start of your code (after your sub name): Application.EnableCancelKey = xlDisabled and see if the error goes away. Richard On 4 Feb, 11:24, Tom wrote: Hi all, I have a workbook that has been running fine for a very long time. Last week I noticed that all of a sudden I am getting an error that states "Code execution has been interrupted". The macro still completes the operation, but the error box comes up. I have not altered the code in any way for quite some time, but this error mysteriously started happening last week seemingly out of the blue. Any clues as to what it could be and fixes for this? Public Sub Print_Visible_Worksheets() Application.ScreenUpdating = False Dim sh As Worksheet Dim arr() As String Dim N As Long Const sStr As String = "Main" For Each sh In ThisWorkbook.Worksheets With sh If .Visible = xlSheetVisible Then If StrComp(.Name, sStr, vbTextCompare) Then N = N + 1 ReDim Preserve arr(1 To N) arr(N) = .Name End If End If End With Next sh With ThisWorkbook .Worksheets(arr).PrintOut .Worksheets(1).Select <-----ERROR IS ON THIS LINE End With Application.ScreenUpdating = True End Sub |
#4
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Tom
I'm afraid I can't answer that - there's nothing wrong with your code. It seems to be an Excel bug, and disabling the cancel key seems to be a workaround for it. Sorry I can't be any more helpful than that! Richard On 4 Feb, 11:55, Tom wrote: Hi Richard, That seems to fix the problem. Now, in order that I can understand this....WHY would this fix the problem...and why, all of a sudden, would it start causing a problem to begin with? I have had this macro written for almost a year without this error...so why did it start all of a sudden? "RichardSchollar" wrote: Hi Tom Try placing the following line at the start of your code (after your sub name): Application.EnableCancelKey = xlDisabled and see if the error goes away. Richard On 4 Feb, 11:24, Tom wrote: Hi all, I have a workbook that has been running fine for a very long time. Last week I noticed that all of a sudden I am getting an error that states "Code execution has been interrupted". The macro still completes the operation, but the error box comes up. I have not altered the code in any way for quite some time, but this error mysteriously started happening last week seemingly out of the blue. Any clues as to what it could be and fixes for this? Public Sub Print_Visible_Worksheets() * * Application.ScreenUpdating = False * * Dim sh As Worksheet * * Dim arr() As String * * Dim N As Long * * Const sStr As String = "Main" * * For Each sh In ThisWorkbook.Worksheets * * * * With sh * * * * * * If .Visible = xlSheetVisible Then * * * * * * * * If StrComp(.Name, sStr, vbTextCompare) Then * * * * * * * * * * N = N + 1 * * * * * * * * * * ReDim Preserve arr(1 To N) * * * * * * * * * * arr(N) = .Name * * * * * * * * End If * * * * * * End If * * * * End With * * Next sh * * With ThisWorkbook * * * * .Worksheets(arr).PrintOut * * * * .Worksheets(1).Select *<-----ERROR IS ON THIS LINE * * End With * * Application.ScreenUpdating = True End Sub- Hide quoted text - - Show quoted text - |
#5
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I guess I'll just put it under the "strange but true" category and just
accept it. Thanks for the fix to the problem Richard...it's very much appreciated. "RichardSchollar" wrote: Tom I'm afraid I can't answer that - there's nothing wrong with your code. It seems to be an Excel bug, and disabling the cancel key seems to be a workaround for it. Sorry I can't be any more helpful than that! Richard On 4 Feb, 11:55, Tom wrote: Hi Richard, That seems to fix the problem. Now, in order that I can understand this....WHY would this fix the problem...and why, all of a sudden, would it start causing a problem to begin with? I have had this macro written for almost a year without this error...so why did it start all of a sudden? "RichardSchollar" wrote: Hi Tom Try placing the following line at the start of your code (after your sub name): Application.EnableCancelKey = xlDisabled and see if the error goes away. Richard On 4 Feb, 11:24, Tom wrote: Hi all, I have a workbook that has been running fine for a very long time. Last week I noticed that all of a sudden I am getting an error that states "Code execution has been interrupted". The macro still completes the operation, but the error box comes up. I have not altered the code in any way for quite some time, but this error mysteriously started happening last week seemingly out of the blue. Any clues as to what it could be and fixes for this? Public Sub Print_Visible_Worksheets() Application.ScreenUpdating = False Dim sh As Worksheet Dim arr() As String Dim N As Long Const sStr As String = "Main" For Each sh In ThisWorkbook.Worksheets With sh If .Visible = xlSheetVisible Then If StrComp(.Name, sStr, vbTextCompare) Then N = N + 1 ReDim Preserve arr(1 To N) arr(N) = .Name End If End If End With Next sh With ThisWorkbook .Worksheets(arr).PrintOut .Worksheets(1).Select <-----ERROR IS ON THIS LINE End With Application.ScreenUpdating = True End Sub- Hide quoted text - - Show quoted text - |
#6
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MANY THANKS TOM, BUT WHERE DO I GO TO SET THIS CODE - SORRY BUT I'M NOT AS
COMPUTER LITERATE AS YOU ARE UNFORTUNATELY. "Tom" wrote: Hi all, I have a workbook that has been running fine for a very long time. Last week I noticed that all of a sudden I am getting an error that states "Code execution has been interrupted". The macro still completes the operation, but the error box comes up. I have not altered the code in any way for quite some time, but this error mysteriously started happening last week seemingly out of the blue. Any clues as to what it could be and fixes for this? Public Sub Print_Visible_Worksheets() Application.ScreenUpdating = False Dim sh As Worksheet Dim arr() As String Dim N As Long Const sStr As String = "Main" For Each sh In ThisWorkbook.Worksheets With sh If .Visible = xlSheetVisible Then If StrComp(.Name, sStr, vbTextCompare) Then N = N + 1 ReDim Preserve arr(1 To N) arr(N) = .Name End If End If End With Next sh With ThisWorkbook .Worksheets(arr).PrintOut .Worksheets(1).Select <-----ERROR IS ON THIS LINE End With Application.ScreenUpdating = True End Sub |
#7
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If you're new to macros:
Debra Dalgleish has some notes how to implement macros he http://www.contextures.com/xlvba01.html David McRitchie has an intro to macros: http://www.mvps.org/dmcritchie/excel/getstarted.htm Ron de Bruin's intro to macros: http://www.rondebruin.nl/code.htm (General, Regular and Standard modules all describe the same thing.) CAROLYN wrote: MANY THANKS TOM, BUT WHERE DO I GO TO SET THIS CODE - SORRY BUT I'M NOT AS COMPUTER LITERATE AS YOU ARE UNFORTUNATELY. "Tom" wrote: Hi all, I have a workbook that has been running fine for a very long time. Last week I noticed that all of a sudden I am getting an error that states "Code execution has been interrupted". The macro still completes the operation, but the error box comes up. I have not altered the code in any way for quite some time, but this error mysteriously started happening last week seemingly out of the blue. Any clues as to what it could be and fixes for this? Public Sub Print_Visible_Worksheets() Application.ScreenUpdating = False Dim sh As Worksheet Dim arr() As String Dim N As Long Const sStr As String = "Main" For Each sh In ThisWorkbook.Worksheets With sh If .Visible = xlSheetVisible Then If StrComp(.Name, sStr, vbTextCompare) Then N = N + 1 ReDim Preserve arr(1 To N) arr(N) = .Name End If End If End With Next sh With ThisWorkbook .Worksheets(arr).PrintOut .Worksheets(1).Select <-----ERROR IS ON THIS LINE End With Application.ScreenUpdating = True End Sub -- Dave Peterson |
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