On Jan 20, 5:57*pm, JLGWhiz wrote:
This code does what you described that you
wanted.

If you use the starting point of 6 for j and
38 for i then changes occur in columns f, h,
j, l, n, p and r for rows 38, 40, 42, 44, 46,
48, 50, 52 and 54. So you can adjust the rows
to change by adusting the starting rows and columns.

Sub makeZero()
For i = 38 To 54 Step 2
* For j = 6 To 18 Step 2
* * If Cells(i, j) < 0 Then
* * * Cells(i, j) = 0
* * End If
* Next j
Next i
End Sub



" wrote:
On Jan 20, 5:08 pm, FSt1 wrote:
hi
your code is full of syntax errors. What are you trying to do?
I'm guessing search range F35 to R54 for negative numbers?

regards
FSt1

" wrote:
Iam trying to create a loop that searches through a table of columns
and rows to zero and negative values. *My columns portion of the code
is causing an error. *How should I change the code to have it work
properly.

Sub Search()
LastColumn = "R"
NewColumnCount = "F"
For ColumnCount = NewColumnCount To LastColumn
LastRow = 54
NewRowCount = 38
For RowCount = NewRowCount To LastRow
* *If Range(ColumnCount & RowCount) < 0 Then
* * * Range(ColumnCount & RowCount) = 0
* * * NewRowCount = NewRowCount + 2
* *End If
Next RowCount
NewColumnCount = NewColumnCount + 2
Next ColumnCount
End Sub

Frank- Hide quoted text -

- Show quoted text -

I realize my code has errors, since I am a novice, and need help. I am
trying to search through a table from F38 through R54 and zero any
value that is below zero. *I need to search only through every send
row, of every second column through this table.

Frank- Hide quoted text -

- Show quoted text -

Thanks for your help. I got this thing working fine. There is always
many ways of doing what you want, some are less complicated than
others. The simple solution is always preferred.

Cheers,
Frank