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#1
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passing an argument
this is a 2 part because i dont think the first part is possible
1) i'd like to have a function that has no arguments but references the cell that the formula for the function is being input into and just takes the value of the first non empty cell to the left (i dont think its possible to reference the cell with the formula though???) 2) because of this i wrote the following passing one range variable but i get a #value error, i know it has to do with the passing of the range because if i hard code a cell it works fine for that row. the code is: Function diag(rng) diag = Range("rng").End(xlToLeft) End Function any ideas???? thanks |
#2
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passing an argument
Try this:
function Diag(adrs as string) as string diag = Range(adrs).end(xltoleft).address end function The input here is a string, eg "D7" and the result is a string containing the address of the cell it finds. " wrote: this is a 2 part because i dont think the first part is possible 1) i'd like to have a function that has no arguments but references the cell that the formula for the function is being input into and just takes the value of the first non empty cell to the left (i dont think its possible to reference the cell with the formula though???) 2) because of this i wrote the following passing one range variable but i get a #value error, i know it has to do with the passing of the range because if i hard code a cell it works fine for that row. the code is: Function diag(rng) diag = Range("rng").End(xlToLeft) End Function any ideas???? thanks |
#3
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passing an argument
Function diag() As Variant Application.Volatile diag = Application.Caller.End(xlToLeft).Value End Function Jim Cone San Francisco, USA http://www.realezsites.com/bus/primitivesoftware (Excel Add-ins / Excel Programming) wrote in message this is a 2 part because i dont think the first part is possible 1) i'd like to have a function that has no arguments but references the cell that the formula for the function is being input into and just takes the value of the first non empty cell to the left (i dont think its possible to reference the cell with the formula though???) 2) because of this i wrote the following passing one range variable but i get a #value error, i know it has to do with the passing of the range because if i hard code a cell it works fine for that row. the code is: Function diag(rng) diag = Range("rng").End(xlToLeft) End Function any ideas???? thanks |
#4
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passing an argument
Function nextleft() As Variant
nextleft = "" i = Application.Caller.Row j = Application.Caller.Column - 1 For k = 1 To j If Cells(i, k).Value = "" Then Else nextleft = Cells(i, k).Value End If Next End Function will do what you want, but it is not volatile. It is better to use args. They will force re-calculation was values are added or removed. -- Gary''s Student - gsnu2007c " wrote: this is a 2 part because i dont think the first part is possible 1) i'd like to have a function that has no arguments but references the cell that the formula for the function is being input into and just takes the value of the first non empty cell to the left (i dont think its possible to reference the cell with the formula though???) 2) because of this i wrote the following passing one range variable but i get a #value error, i know it has to do with the passing of the range because if i hard code a cell it works fine for that row. the code is: Function diag(rng) diag = Range("rng").End(xlToLeft) End Function any ideas???? thanks |
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