Hi everyone,

I have the code ...

Option Explicit

Dim A As Integer, B As Integer, C As Integer, D As Integer, E As
Integer, F As Integer
Dim nVal As Double, nLex As Double

Sub LexToNumbers()
nVal = Range("A1").Value
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If nLex = nVal Then
Range("B1").Value = A
Range("C1").Value = B
Range("D1").Value = C
Range("E1").Value = D
Range("F1").Value = E
Range("G1").Value = F
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

.... which calculates and produces the 6 numbers associated with the
Lexicographic Index Number entered in cell "A1".
How can I get the Lexicographic Index Number from the numbers entered
in cells "B1:G1" please.
Tom Ogilvy produced the following code which might be of help :-

Function LexNumber()
LexNumber = False
a = IIf(44 - Range("O14").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
b = IIf(45 - Range("P14").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
c = IIf(46 - Range("Q14").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
d = IIf(47 - Range("R14").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
e = IIf(48 - Range("S14").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
f = IIf(49 - Range("T14").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
lNumber = Application.Combin(49, 6) _
- a - b - c - d - e - f
If lNumber 22500 And lNumber < 50000 Then
LexNumber = True
End if
End Function

Thanks in Advance.
All the Best.
Paul

Function NumbersToLex()
A = IIf(44 - Range("B1").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
B = IIf(45 - Range("C1").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
C = IIf(46 - Range("D1").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
D = IIf(47 - Range("E1").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
E = IIf(48 - Range("F1").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
F = IIf(49 - Range("G1").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
NumbersToLex = Application.Combin(49, 6) _
- A - B - C - D - E - F
End Function

seems to do it, use in a spreadsheet in any cell thus:
NumbersToLex()
I suspect the numbers will have to be in ascending order first though.
--
p45cal

ps. another longwinded way is to make small adjustments to your code:

Sub NumbersToLex2()
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If Range("B1").Value = A And Range("C1").Value = B And Range("D1").Value = C
And Range("E1").Value = D And Range("F1").Value = E And Range("G1").Value = F
Then
nVal = nLex
Range("H1") = nVal
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

I say long winded 'cos it could take a llllooonnnggg time.
p45cal
______

"Paul Black" wrote:

Hi everyone,

I have the code ...

Option Explicit

Dim A As Integer, B As Integer, C As Integer, D As Integer, E As
Integer, F As Integer
Dim nVal As Double, nLex As Double

Sub LexToNumbers()
nVal = Range("A1").Value
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If nLex = nVal Then
Range("B1").Value = A
Range("C1").Value = B
Range("D1").Value = C
Range("E1").Value = D
Range("F1").Value = E
Range("G1").Value = F
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

.... which calculates and produces the 6 numbers associated with the
Lexicographic Index Number entered in cell "A1".
How can I get the Lexicographic Index Number from the numbers entered
in cells "B1:G1" please.
Tom Ogilvy produced the following code which might be of help :-

Function LexNumber()
LexNumber = False
a = IIf(44 - Range("O14").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
b = IIf(45 - Range("P14").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
c = IIf(46 - Range("Q14").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
d = IIf(47 - Range("R14").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
e = IIf(48 - Range("S14").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
f = IIf(49 - Range("T14").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
lNumber = Application.Combin(49, 6) _
- a - b - c - d - e - f
If lNumber 22500 And lNumber < 50000 Then
LexNumber = True
End if
End Function

Thanks in Advance.
All the Best.
Paul

a small mistake; I said:
use in a spreadsheet in any cell thus:
NumbersToLex()

it should have been:
use in a spreadsheet in any cell thus:
=NumbersToLex()

---
p45cal


"p45cal" wrote:

Function NumbersToLex()
A = IIf(44 - Range("B1").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
B = IIf(45 - Range("C1").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
C = IIf(46 - Range("D1").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
D = IIf(47 - Range("E1").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
E = IIf(48 - Range("F1").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
F = IIf(49 - Range("G1").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
NumbersToLex = Application.Combin(49, 6) _
- A - B - C - D - E - F
End Function

seems to do it, use in a spreadsheet in any cell thus:
NumbersToLex()
I suspect the numbers will have to be in ascending order first though.
--
p45cal

ps. another longwinded way is to make small adjustments to your code:

Sub NumbersToLex2()
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If Range("B1").Value = A And Range("C1").Value = B And Range("D1").Value = C
And Range("E1").Value = D And Range("F1").Value = E And Range("G1").Value = F
Then
nVal = nLex
Range("H1") = nVal
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

I say long winded 'cos it could take a llllooonnnggg time.
p45cal
______

"Paul Black" wrote:

Hi everyone,

I have the code ...

Option Explicit

Dim A As Integer, B As Integer, C As Integer, D As Integer, E As
Integer, F As Integer
Dim nVal As Double, nLex As Double

Sub LexToNumbers()
nVal = Range("A1").Value
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If nLex = nVal Then
Range("B1").Value = A
Range("C1").Value = B
Range("D1").Value = C
Range("E1").Value = D
Range("F1").Value = E
Range("G1").Value = F
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

.... which calculates and produces the 6 numbers associated with the
Lexicographic Index Number entered in cell "A1".
How can I get the Lexicographic Index Number from the numbers entered
in cells "B1:G1" please.
Tom Ogilvy produced the following code which might be of help :-

Function LexNumber()
LexNumber = False
a = IIf(44 - Range("O14").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
b = IIf(45 - Range("P14").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
c = IIf(46 - Range("Q14").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
d = IIf(47 - Range("R14").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
e = IIf(48 - Range("S14").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
f = IIf(49 - Range("T14").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
lNumber = Application.Combin(49, 6) _
- a - b - c - d - e - f
If lNumber 22500 And lNumber < 50000 Then
LexNumber = True
End if
End Function

Thanks in Advance.
All the Best.
Paul

Thanks for the reply p45cal,

I really wanted it in a seperate sub so I could attach each of the
subs to a button please.

Thanks in Advance.
All the Best.
Paul

On Oct 3, 2:49 pm, p45cal wrote:
a small mistake; I said:
use in a spreadsheet in any cell thus:
NumbersToLex()

it should have been:
use in a spreadsheet in any cell thus:
=NumbersToLex()

---
p45cal



"p45cal" wrote:
Function NumbersToLex()
A = IIf(44 - Range("B1").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
B = IIf(45 - Range("C1").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
C = IIf(46 - Range("D1").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
D = IIf(47 - Range("E1").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
E = IIf(48 - Range("F1").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
F = IIf(49 - Range("G1").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
NumbersToLex = Application.Combin(49, 6) _
- A - B - C - D - E - F
End Function

seems to do it, use in a spreadsheet in any cell thus:
NumbersToLex()
I suspect the numbers will have to be in ascending order first though.
--
p45cal

ps. another longwinded way is to make small adjustments to your code:

Sub NumbersToLex2()
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If Range("B1").Value = A And Range("C1").Value = B And Range("D1").Value = C
And Range("E1").Value = D And Range("F1").Value = E And Range("G1").Value = F
Then
nVal = nLex
Range("H1") = nVal
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

I say long winded 'cos it could take a llllooonnnggg time.
p45cal
______

"Paul Black" wrote:

Hi everyone,

I have the code ...

Option Explicit

Dim A As Integer, B As Integer, C As Integer, D As Integer, E As
Integer, F As Integer
Dim nVal As Double, nLex As Double

Sub LexToNumbers()
nVal = Range("A1").Value
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If nLex = nVal Then
Range("B1").Value = A
Range("C1").Value = B
Range("D1").Value = C
Range("E1").Value = D
Range("F1").Value = E
Range("G1").Value = F
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

.... which calculates and produces the 6 numbers associated with the
Lexicographic Index Number entered in cell "A1".
How can I get the Lexicographic Index Number from the numbers entered
in cells "B1:G1" please.
Tom Ogilvy produced the following code which might be of help :-

Function LexNumber()
LexNumber = False
a = IIf(44 - Range("O14").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
b = IIf(45 - Range("P14").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
c = IIf(46 - Range("Q14").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
d = IIf(47 - Range("R14").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
e = IIf(48 - Range("S14").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
f = IIf(49 - Range("T14").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
lNumber = Application.Combin(49, 6) _
- a - b - c - d - e - f
If lNumber 22500 And lNumber < 50000 Then
LexNumber = True
End if
End Function

Thanks in Advance.
All the Best.
Paul- Hide quoted text -

- Show quoted text -

Thanks for the reply p45cal,

I really wanted the seperate sub which is great.
I put in numbers 44 45 46 47 48 49 and it took ages to calculate
13983816.
Is it quicker than calling the function from the sub, if so, how do I
do I call the function please?.

Thanks in Advance.
All the Best.
Paul

On Oct 3, 2:49 pm, p45cal wrote:
a small mistake; I said:
use in a spreadsheet in any cell thus:
NumbersToLex()

it should have been:
use in a spreadsheet in any cell thus:
=NumbersToLex()

---
p45cal



"p45cal" wrote:
Function NumbersToLex()
A = IIf(44 - Range("B1").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
B = IIf(45 - Range("C1").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
C = IIf(46 - Range("D1").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
D = IIf(47 - Range("E1").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
E = IIf(48 - Range("F1").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
F = IIf(49 - Range("G1").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
NumbersToLex = Application.Combin(49, 6) _
- A - B - C - D - E - F
End Function

seems to do it, use in a spreadsheet in any cell thus:
NumbersToLex()
I suspect the numbers will have to be in ascending order first though.
--
p45cal

ps. another longwinded way is to make small adjustments to your code:

Sub NumbersToLex2()
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If Range("B1").Value = A And Range("C1").Value = B And Range("D1").Value = C
And Range("E1").Value = D And Range("F1").Value = E And Range("G1").Value = F
Then
nVal = nLex
Range("H1") = nVal
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

I say long winded 'cos it could take a llllooonnnggg time.
p45cal
______

"Paul Black" wrote:

Hi everyone,

I have the code ...

Option Explicit

Dim A As Integer, B As Integer, C As Integer, D As Integer, E As
Integer, F As Integer
Dim nVal As Double, nLex As Double

Sub LexToNumbers()
nVal = Range("A1").Value
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If nLex = nVal Then
Range("B1").Value = A
Range("C1").Value = B
Range("D1").Value = C
Range("E1").Value = D
Range("F1").Value = E
Range("G1").Value = F
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

.... which calculates and produces the 6 numbers associated with the
Lexicographic Index Number entered in cell "A1".
How can I get the Lexicographic Index Number from the numbers entered
in cells "B1:G1" please.
Tom Ogilvy produced the following code which might be of help :-

Function LexNumber()
LexNumber = False
a = IIf(44 - Range("O14").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
b = IIf(45 - Range("P14").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
c = IIf(46 - Range("Q14").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
d = IIf(47 - Range("R14").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
e = IIf(48 - Range("S14").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
f = IIf(49 - Range("T14").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
lNumber = Application.Combin(49, 6) _
- a - b - c - d - e - f
If lNumber 22500 And lNumber < 50000 Then
LexNumber = True
End if
End Function

Thanks in Advance.
All the Best.
Paul- Hide quoted text -

- Show quoted text -

I put in numbers 44 45 46 47 48 49 and it took ages to calculate
13983816.

Hi. As a side note, in Combinations, what you are asking for is the Rank of
a Subset.
Your initial code "Sub LexToNumbers()" is trying to "UnRank" the subset.
Code is usually written much different than the above by taking advantage of
certain properties.
For example, the number 1 can only occur in so many subsets.
Search for something like "RankKSubset" where you must supply the initial
size of your array. (ie 49 as the first item)

t = Timer
Debug.Print RankKSubset(49, 44, 45, 46, 47, 48, 49)
Debug.Print Timer - t

returns
13983816
0 (ie seconds)

--
Dana DeLouis


"Paul Black" wrote in message
oups.com...
Thanks for the reply p45cal,

I really wanted the seperate sub which is great.
I put in numbers 44 45 46 47 48 49 and it took ages to calculate
13983816.
Is it quicker than calling the function from the sub, if so, how do I
do I call the function please?.

Thanks in Advance.
All the Best.
Paul

On Oct 3, 2:49 pm, p45cal wrote:
a small mistake; I said:
use in a spreadsheet in any cell thus:
NumbersToLex()

it should have been:
use in a spreadsheet in any cell thus:
=NumbersToLex()

---
p45cal



"p45cal" wrote:
Function NumbersToLex()
A = IIf(44 - Range("B1").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
B = IIf(45 - Range("C1").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
C = IIf(46 - Range("D1").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
D = IIf(47 - Range("E1").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
E = IIf(48 - Range("F1").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
F = IIf(49 - Range("G1").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
NumbersToLex = Application.Combin(49, 6) _
- A - B - C - D - E - F
End Function

seems to do it, use in a spreadsheet in any cell thus:
NumbersToLex()
I suspect the numbers will have to be in ascending order first though.
--
p45cal

ps. another longwinded way is to make small adjustments to your code:

Sub NumbersToLex2()
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If Range("B1").Value = A And Range("C1").Value = B And
Range("D1").Value = C
And Range("E1").Value = D And Range("F1").Value = E And
Range("G1").Value = F
Then
nVal = nLex
Range("H1") = nVal
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

I say long winded 'cos it could take a llllooonnnggg time.
p45cal
______

"Paul Black" wrote:

Hi everyone,

I have the code ...

Option Explicit

Dim A As Integer, B As Integer, C As Integer, D As Integer, E As
Integer, F As Integer
Dim nVal As Double, nLex As Double

Sub LexToNumbers()
nVal = Range("A1").Value
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If nLex = nVal Then
Range("B1").Value = A
Range("C1").Value = B
Range("D1").Value = C
Range("E1").Value = D
Range("F1").Value = E
Range("G1").Value = F
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

.... which calculates and produces the 6 numbers associated with the
Lexicographic Index Number entered in cell "A1".
How can I get the Lexicographic Index Number from the numbers entered
in cells "B1:G1" please.
Tom Ogilvy produced the following code which might be of help :-

Function LexNumber()
LexNumber = False
a = IIf(44 - Range("O14").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
b = IIf(45 - Range("P14").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
c = IIf(46 - Range("Q14").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
d = IIf(47 - Range("R14").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
e = IIf(48 - Range("S14").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
f = IIf(49 - Range("T14").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
lNumber = Application.Combin(49, 6) _
- a - b - c - d - e - f
If lNumber 22500 And lNumber < 50000 Then
LexNumber = True
End if
End Function

Thanks in Advance.
All the Best.
Paul- Hide quoted text -

- Show quoted text -

Sub NumbersToLex()
A = IIf(44 - Range("B1").Value 0, _
Application.Combin(49 - _
Range("B1").Value, 6), 0)
B = IIf(45 - Range("C1").Value 0, _
Application.Combin(49 - _
Range("C1").Value, 5), 0)
C = IIf(46 - Range("D1").Value 0, _
Application.Combin(49 - _
Range("D1").Value, 4), 0)
D = IIf(47 - Range("E1").Value 0, _
Application.Combin(49 - _
Range("E1").Value, 3), 0)
E = IIf(48 - Range("F1").Value 0, _
Application.Combin(49 - _
Range("F1").Value, 2), 0)
F = IIf(49 - Range("G1").Value 0, _
Application.Combin(49 - _
Range("G1").Value, 1), 0)
Range("A1") = Application.Combin(49, 6) _
- A - B - C - D - E - F
End Sub

was almost instantaneous for me.

--
Regards,
Tom Ogilvy


"Paul Black" wrote:

Thanks for the reply p45cal,

I really wanted the seperate sub which is great.
I put in numbers 44 45 46 47 48 49 and it took ages to calculate
13983816.
Is it quicker than calling the function from the sub, if so, how do I
do I call the function please?.

Thanks in Advance.
All the Best.
Paul

On Oct 3, 2:49 pm, p45cal wrote:
a small mistake; I said:
use in a spreadsheet in any cell thus:
NumbersToLex()

it should have been:
use in a spreadsheet in any cell thus:
=NumbersToLex()

---
p45cal



"p45cal" wrote:
Function NumbersToLex()
A = IIf(44 - Range("B1").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
B = IIf(45 - Range("C1").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
C = IIf(46 - Range("D1").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
D = IIf(47 - Range("E1").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
E = IIf(48 - Range("F1").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
F = IIf(49 - Range("G1").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
NumbersToLex = Application.Combin(49, 6) _
- A - B - C - D - E - F
End Function

seems to do it, use in a spreadsheet in any cell thus:
NumbersToLex()
I suspect the numbers will have to be in ascending order first though.
--
p45cal

ps. another longwinded way is to make small adjustments to your code:

Sub NumbersToLex2()
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If Range("B1").Value = A And Range("C1").Value = B And Range("D1").Value = C
And Range("E1").Value = D And Range("F1").Value = E And Range("G1").Value = F
Then
nVal = nLex
Range("H1") = nVal
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

I say long winded 'cos it could take a llllooonnnggg time.
p45cal
______

"Paul Black" wrote:

Hi everyone,

I have the code ...

Option Explicit

Dim A As Integer, B As Integer, C As Integer, D As Integer, E As
Integer, F As Integer
Dim nVal As Double, nLex As Double

Sub LexToNumbers()
nVal = Range("A1").Value
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If nLex = nVal Then
Range("B1").Value = A
Range("C1").Value = B
Range("D1").Value = C
Range("E1").Value = D
Range("F1").Value = E
Range("G1").Value = F
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

.... which calculates and produces the 6 numbers associated with the
Lexicographic Index Number entered in cell "A1".
How can I get the Lexicographic Index Number from the numbers entered
in cells "B1:G1" please.
Tom Ogilvy produced the following code which might be of help :-

Function LexNumber()
LexNumber = False
a = IIf(44 - Range("O14").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
b = IIf(45 - Range("P14").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
c = IIf(46 - Range("Q14").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
d = IIf(47 - Range("R14").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
e = IIf(48 - Range("S14").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
f = IIf(49 - Range("T14").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
lNumber = Application.Combin(49, 6) _
- a - b - c - d - e - f
If lNumber 22500 And lNumber < 50000 Then
LexNumber = True
End if
End Function

Thanks in Advance.
All the Best.
Paul- Hide quoted text -

- Show quoted text -

Thanks everyone for your time and help, especially Tom, it works like
a dream.

All the Best.
Paul

On Oct 3, 6:19 pm, Tom Ogilvy
wrote:
Sub NumbersToLex()
A = IIf(44 - Range("B1").Value 0, _
Application.Combin(49 - _
Range("B1").Value, 6), 0)
B = IIf(45 - Range("C1").Value 0, _
Application.Combin(49 - _
Range("C1").Value, 5), 0)
C = IIf(46 - Range("D1").Value 0, _
Application.Combin(49 - _
Range("D1").Value, 4), 0)
D = IIf(47 - Range("E1").Value 0, _
Application.Combin(49 - _
Range("E1").Value, 3), 0)
E = IIf(48 - Range("F1").Value 0, _
Application.Combin(49 - _
Range("F1").Value, 2), 0)
F = IIf(49 - Range("G1").Value 0, _
Application.Combin(49 - _
Range("G1").Value, 1), 0)
Range("A1") = Application.Combin(49, 6) _
- A - B - C - D - E - F
End Sub

was almost instantaneous for me.

--
Regards,
Tom Ogilvy



"Paul Black" wrote:
Thanks for the reply p45cal,

I really wanted the seperate sub which is great.
I put in numbers 44 45 46 47 48 49 and it took ages to calculate
13983816.
Is it quicker than calling the function from the sub, if so, how do I
do I call the function please?.

Thanks in Advance.
All the Best.
Paul

On Oct 3, 2:49 pm, p45cal wrote:
a small mistake; I said:
use in a spreadsheet in any cell thus:
NumbersToLex()

it should have been:
use in a spreadsheet in any cell thus:
=NumbersToLex()

---
p45cal

"p45cal" wrote:
Function NumbersToLex()
A = IIf(44 - Range("B1").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
B = IIf(45 - Range("C1").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
C = IIf(46 - Range("D1").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
D = IIf(47 - Range("E1").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
E = IIf(48 - Range("F1").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
F = IIf(49 - Range("G1").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
NumbersToLex = Application.Combin(49, 6) _
- A - B - C - D - E - F
End Function

seems to do it, use in a spreadsheet in any cell thus:
NumbersToLex()
I suspect the numbers will have to be in ascending order first though.
--
p45cal

ps. another longwinded way is to make small adjustments to your code:

Sub NumbersToLex2()
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If Range("B1").Value = A And Range("C1").Value = B And Range("D1").Value = C
And Range("E1").Value = D And Range("F1").Value = E And Range("G1").Value = F
Then
nVal = nLex
Range("H1") = nVal
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

I say long winded 'cos it could take a llllooonnnggg time.
p45cal
______

"Paul Black" wrote:

Hi everyone,

I have the code ...

Option Explicit

Dim A As Integer, B As Integer, C As Integer, D As Integer, E As
Integer, F As Integer
Dim nVal As Double, nLex As Double

Sub LexToNumbers()
nVal = Range("A1").Value
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If nLex = nVal Then
Range("B1").Value = A
Range("C1").Value = B
Range("D1").Value = C
Range("E1").Value = D
Range("F1").Value = E
Range("G1").Value = F
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

.... which calculates and produces the 6 numbers associated with the
Lexicographic Index Number entered in cell "A1".
How can I get the Lexicographic Index Number from the numbers entered
in cells "B1:G1" please.
Tom Ogilvy produced the following code which might be of help :-

Function LexNumber()
LexNumber = False
a = IIf(44 - Range("O14").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
b = IIf(45 - Range("P14").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
c = IIf(46 - Range("Q14").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
d = IIf(47 - Range("R14").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
e = IIf(48 - Range("S14").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
f = IIf(49 - Range("T14").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
lNumber = Application.Combin(49, 6) _
- a - b - c - d - e - f
If lNumber 22500 And lNumber < 50000 Then
LexNumber = True
End if
End Function

Thanks in Advance.
All the Best.
Paul- Hide quoted text -

- Show quoted text -- Hide quoted text -

- Show quoted text -

call the function in a sub thus:

Sub test()
Range("H1") = LexToNumber
End Sub

t-timer was zero here too Tom!
--
p45cal


"Paul Black" wrote:

Thanks for the reply p45cal,

I really wanted it in a seperate sub so I could attach each of the
subs to a button please.

Thanks in Advance.
All the Best.
Paul

On Oct 3, 2:49 pm, p45cal wrote:
a small mistake; I said:
use in a spreadsheet in any cell thus:
NumbersToLex()

it should have been:
use in a spreadsheet in any cell thus:
=NumbersToLex()

---
p45cal



"p45cal" wrote:
Function NumbersToLex()
A = IIf(44 - Range("B1").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
B = IIf(45 - Range("C1").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
C = IIf(46 - Range("D1").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
D = IIf(47 - Range("E1").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
E = IIf(48 - Range("F1").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
F = IIf(49 - Range("G1").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
NumbersToLex = Application.Combin(49, 6) _
- A - B - C - D - E - F
End Function

seems to do it, use in a spreadsheet in any cell thus:
NumbersToLex()
I suspect the numbers will have to be in ascending order first though.
--
p45cal

ps. another longwinded way is to make small adjustments to your code:

Sub NumbersToLex2()
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If Range("B1").Value = A And Range("C1").Value = B And Range("D1").Value = C
And Range("E1").Value = D And Range("F1").Value = E And Range("G1").Value = F
Then
nVal = nLex
Range("H1") = nVal
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

I say long winded 'cos it could take a llllooonnnggg time.
p45cal
______

"Paul Black" wrote:

Hi everyone,

I have the code ...

Option Explicit

Dim A As Integer, B As Integer, C As Integer, D As Integer, E As
Integer, F As Integer
Dim nVal As Double, nLex As Double

Sub LexToNumbers()
nVal = Range("A1").Value
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If nLex = nVal Then
Range("B1").Value = A
Range("C1").Value = B
Range("D1").Value = C
Range("E1").Value = D
Range("F1").Value = E
Range("G1").Value = F
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

.... which calculates and produces the 6 numbers associated with the
Lexicographic Index Number entered in cell "A1".
How can I get the Lexicographic Index Number from the numbers entered
in cells "B1:G1" please.
Tom Ogilvy produced the following code which might be of help :-

Function LexNumber()
LexNumber = False
a = IIf(44 - Range("O14").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
b = IIf(45 - Range("P14").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
c = IIf(46 - Range("Q14").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
d = IIf(47 - Range("R14").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
e = IIf(48 - Range("S14").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
f = IIf(49 - Range("T14").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
lNumber = Application.Combin(49, 6) _
- a - b - c - d - e - f
If lNumber 22500 And lNumber < 50000 Then
LexNumber = True
End if
End Function

Thanks in Advance.
All the Best.
Paul- Hide quoted text -

- Show quoted text -

Thanks everyone for your time and help.
It all works great and VERY fast.
I went with Tom's sub in the end. One interesting point though, when I
"Dimmed" the variables it gave me an overflow 6 error.
Is there better coding for ...

Option Explicit

Dim A As Integer, B As Integer, C As Integer, D As Integer, E As
Integer, F As Integer
Dim nVal As Double, nLex As Double

Sub LexToNumbers()
nVal = Range("A1").Value
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If nLex = nVal Then
Range("B1").Value = A
Range("C1").Value = B
Range("D1").Value = C
Range("E1").Value = D
Range("F1").Value = E
Range("G1").Value = F
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

.... to make it more efficient?.

Thanks in Advance.
All the Best.
Paul

On Oct 4, 12:02 am, p45cal wrote:
call the function in a sub thus:

Sub test()
Range("H1") = LexToNumber
End Sub

t-timer was zero here too Tom!
--
p45cal



"Paul Black" wrote:
Thanks for the reply p45cal,

I really wanted it in a seperate sub so I could attach each of the
subs to a button please.

Thanks in Advance.
All the Best.
Paul

On Oct 3, 2:49 pm, p45cal wrote:
a small mistake; I said:
use in a spreadsheet in any cell thus:
NumbersToLex()

it should have been:
use in a spreadsheet in any cell thus:
=NumbersToLex()

---
p45cal

"p45cal" wrote:
Function NumbersToLex()
A = IIf(44 - Range("B1").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
B = IIf(45 - Range("C1").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
C = IIf(46 - Range("D1").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
D = IIf(47 - Range("E1").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
E = IIf(48 - Range("F1").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
F = IIf(49 - Range("G1").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
NumbersToLex = Application.Combin(49, 6) _
- A - B - C - D - E - F
End Function

seems to do it, use in a spreadsheet in any cell thus:
NumbersToLex()
I suspect the numbers will have to be in ascending order first though.
--
p45cal

ps. another longwinded way is to make small adjustments to your code:

Sub NumbersToLex2()
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If Range("B1").Value = A And Range("C1").Value = B And Range("D1").Value = C
And Range("E1").Value = D And Range("F1").Value = E And Range("G1").Value = F
Then
nVal = nLex
Range("H1") = nVal
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

I say long winded 'cos it could take a llllooonnnggg time.
p45cal
______

"Paul Black" wrote:

Hi everyone,

I have the code ...

Option Explicit

Dim A As Integer, B As Integer, C As Integer, D As Integer, E As
Integer, F As Integer
Dim nVal As Double, nLex As Double

Sub LexToNumbers()
nVal = Range("A1").Value
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If nLex = nVal Then
Range("B1").Value = A
Range("C1").Value = B
Range("D1").Value = C
Range("E1").Value = D
Range("F1").Value = E
Range("G1").Value = F
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

.... which calculates and produces the 6 numbers associated with the
Lexicographic Index Number entered in cell "A1".
How can I get the Lexicographic Index Number from the numbers entered
in cells "B1:G1" please.
Tom Ogilvy produced the following code which might be of help :-

Function LexNumber()
LexNumber = False
a = IIf(44 - Range("O14").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
b = IIf(45 - Range("P14").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
c = IIf(46 - Range("Q14").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
d = IIf(47 - Range("R14").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
e = IIf(48 - Range("S14").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
f = IIf(49 - Range("T14").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
lNumber = Application.Combin(49, 6) _
- a - b - c - d - e - f
If lNumber 22500 And lNumber < 50000 Then
LexNumber = True
End if
End Function

Thanks in Advance.
All the Best.
Paul- Hide quoted text -

- Show quoted text -- Hide quoted text -

- Show quoted text -

Change your integers to longs.

Dim A as long
....



Paul Black wrote:

Thanks everyone for your time and help.
It all works great and VERY fast.
I went with Tom's sub in the end. One interesting point though, when I
"Dimmed" the variables it gave me an overflow 6 error.
Is there better coding for ...

Option Explicit

Dim A As Integer, B As Integer, C As Integer, D As Integer, E As
Integer, F As Integer
Dim nVal As Double, nLex As Double

Sub LexToNumbers()
nVal = Range("A1").Value
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If nLex = nVal Then
Range("B1").Value = A
Range("C1").Value = B
Range("D1").Value = C
Range("E1").Value = D
Range("F1").Value = E
Range("G1").Value = F
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

... to make it more efficient?.

Thanks in Advance.
All the Best.
Paul

On Oct 4, 12:02 am, p45cal wrote:
call the function in a sub thus:

Sub test()
Range("H1") = LexToNumber
End Sub

t-timer was zero here too Tom!
--
p45cal



"Paul Black" wrote:
Thanks for the reply p45cal,

I really wanted it in a seperate sub so I could attach each of the
subs to a button please.

Thanks in Advance.
All the Best.
Paul

On Oct 3, 2:49 pm, p45cal wrote:
a small mistake; I said:
use in a spreadsheet in any cell thus:
NumbersToLex()

it should have been:
use in a spreadsheet in any cell thus:
=NumbersToLex()

---
p45cal

"p45cal" wrote:
Function NumbersToLex()
A = IIf(44 - Range("B1").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
B = IIf(45 - Range("C1").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
C = IIf(46 - Range("D1").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
D = IIf(47 - Range("E1").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
E = IIf(48 - Range("F1").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
F = IIf(49 - Range("G1").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
NumbersToLex = Application.Combin(49, 6) _
- A - B - C - D - E - F
End Function

seems to do it, use in a spreadsheet in any cell thus:
NumbersToLex()
I suspect the numbers will have to be in ascending order first though.
--
p45cal

ps. another longwinded way is to make small adjustments to your code:

Sub NumbersToLex2()
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If Range("B1").Value = A And Range("C1").Value = B And Range("D1").Value = C
And Range("E1").Value = D And Range("F1").Value = E And Range("G1").Value = F
Then
nVal = nLex
Range("H1") = nVal
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

I say long winded 'cos it could take a llllooonnnggg time.
p45cal
______

"Paul Black" wrote:

Hi everyone,

I have the code ...

Option Explicit

Dim A As Integer, B As Integer, C As Integer, D As Integer, E As
Integer, F As Integer
Dim nVal As Double, nLex As Double

Sub LexToNumbers()
nVal = Range("A1").Value
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If nLex = nVal Then
Range("B1").Value = A
Range("C1").Value = B
Range("D1").Value = C
Range("E1").Value = D
Range("F1").Value = E
Range("G1").Value = F
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

.... which calculates and produces the 6 numbers associated with the
Lexicographic Index Number entered in cell "A1".
How can I get the Lexicographic Index Number from the numbers entered
in cells "B1:G1" please.
Tom Ogilvy produced the following code which might be of help :-

Function LexNumber()
LexNumber = False
a = IIf(44 - Range("O14").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
b = IIf(45 - Range("P14").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
c = IIf(46 - Range("Q14").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
d = IIf(47 - Range("R14").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
e = IIf(48 - Range("S14").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
f = IIf(49 - Range("T14").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
lNumber = Application.Combin(49, 6) _
- a - b - c - d - e - f
If lNumber 22500 And lNumber < 50000 Then
LexNumber = True
End if
End Function

Thanks in Advance.
All the Best.
Paul- Hide quoted text -

- Show quoted text -- Hide quoted text -

- Show quoted text -

--

Dave Peterson

Hi. Just for Gee Wiz, here is something one would think Excel could not do.
Suppose you had a set of 300, instead of 49.
Suppose you also picked a random size of numbers, say 15.

{4, 15, 31, 53, 71, 80, 109, 122, 140, 152, 173, 175, 196, 198, 220}

Without changing the code, the above numbers are the
1,234,567,890,123,456,789,012,345
th item in the list.

Sub Demo()
Dim T
T = Timer
Debug.Print NF(RankKSubset(300, 4, 15, 31, 53, 71, 80, 109, 122, 140, 152,
173, 175, 196, 198, 220))
Debug.Print Timer - T
End Sub

Returns
1,234,567,890,123,456,789,012,345
0 (Seconds)

(Large number chosen for its pattern as a visual check)
Just a topic I find interesting. :o
--
Dana DeLouis



"Paul Black" wrote in message
ups.com...
Thanks everyone for your time and help, especially Tom, it works like
a dream.

All the Best.
Paul

On Oct 3, 6:19 pm, Tom Ogilvy
wrote:
Sub NumbersToLex()
A = IIf(44 - Range("B1").Value 0, _
Application.Combin(49 - _
Range("B1").Value, 6), 0)
B = IIf(45 - Range("C1").Value 0, _
Application.Combin(49 - _
Range("C1").Value, 5), 0)
C = IIf(46 - Range("D1").Value 0, _
Application.Combin(49 - _
Range("D1").Value, 4), 0)
D = IIf(47 - Range("E1").Value 0, _
Application.Combin(49 - _
Range("E1").Value, 3), 0)
E = IIf(48 - Range("F1").Value 0, _
Application.Combin(49 - _
Range("F1").Value, 2), 0)
F = IIf(49 - Range("G1").Value 0, _
Application.Combin(49 - _
Range("G1").Value, 1), 0)
Range("A1") = Application.Combin(49, 6) _
- A - B - C - D - E - F
End Sub

was almost instantaneous for me.

--
Regards,
Tom Ogilvy



"Paul Black" wrote:
Thanks for the reply p45cal,

I really wanted the seperate sub which is great.
I put in numbers 44 45 46 47 48 49 and it took ages to calculate
13983816.
Is it quicker than calling the function from the sub, if so, how do I
do I call the function please?.

Thanks in Advance.
All the Best.
Paul

On Oct 3, 2:49 pm, p45cal wrote:
a small mistake; I said:
use in a spreadsheet in any cell thus:
NumbersToLex()

it should have been:
use in a spreadsheet in any cell thus:
=NumbersToLex()

---
p45cal

"p45cal" wrote:
Function NumbersToLex()
A = IIf(44 - Range("B1").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
B = IIf(45 - Range("C1").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
C = IIf(46 - Range("D1").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
D = IIf(47 - Range("E1").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
E = IIf(48 - Range("F1").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
F = IIf(49 - Range("G1").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
NumbersToLex = Application.Combin(49, 6) _
- A - B - C - D - E - F
End Function

seems to do it, use in a spreadsheet in any cell thus:
NumbersToLex()
I suspect the numbers will have to be in ascending order first
though.
--
p45cal

ps. another longwinded way is to make small adjustments to your
code:

Sub NumbersToLex2()
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If Range("B1").Value = A And Range("C1").Value = B And
Range("D1").Value = C
And Range("E1").Value = D And Range("F1").Value = E And
Range("G1").Value = F
Then
nVal = nLex
Range("H1") = nVal
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

I say long winded 'cos it could take a llllooonnnggg time.
p45cal
______

"Paul Black" wrote:

Hi everyone,

I have the code ...

Option Explicit

Dim A As Integer, B As Integer, C As Integer, D As Integer, E As
Integer, F As Integer
Dim nVal As Double, nLex As Double

Sub LexToNumbers()
nVal = Range("A1").Value
nLex = 0
For A = 1 To 44
For B = A + 1 To 45
For C = B + 1 To 46
For D = C + 1 To 47
For E = D + 1 To 48
For F = E + 1 To 49
nLex = nLex + 1
If nLex = nVal Then
Range("B1").Value = A
Range("C1").Value = B
Range("D1").Value = C
Range("E1").Value = D
Range("F1").Value = E
Range("G1").Value = F
Exit Sub
End If
Next F
Next E
Next D
Next C
Next B
Next A
End Sub

.... which calculates and produces the 6 numbers associated with
the
Lexicographic Index Number entered in cell "A1".
How can I get the Lexicographic Index Number from the numbers
entered
in cells "B1:G1" please.
Tom Ogilvy produced the following code which might be of help :-

Function LexNumber()
LexNumber = False
a = IIf(44 - Range("O14").Value 0, _
Application.Combin(49 - _
Range("O14").Value, 6), 0)
b = IIf(45 - Range("P14").Value 0, _
Application.Combin(49 - _
Range("P14").Value, 5), 0)
c = IIf(46 - Range("Q14").Value 0, _
Application.Combin(49 - _
Range("Q14").Value, 4), 0)
d = IIf(47 - Range("R14").Value 0, _
Application.Combin(49 - _
Range("R14").Value, 3), 0)
e = IIf(48 - Range("S14").Value 0, _
Application.Combin(49 - _
Range("S14").Value, 2), 0)
f = IIf(49 - Range("T14").Value 0, _
Application.Combin(49 - _
Range("T14").Value, 1), 0)
lNumber = Application.Combin(49, 6) _
- a - b - c - d - e - f
If lNumber 22500 And lNumber < 50000 Then
LexNumber = True
End if
End Function

Thanks in Advance.
All the Best.
Paul- Hide quoted text -

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