When I try to compile the code below, I get a 'Loop without Do' error. The
code is designed to loop through an array and hide the rows that have a zero
value.

Thoughts?
Using Excel 2003.


Sub HideRow()

Range("B15").Select

Do Until ActiveCell = "STOP"
If ActiveCell.Value = 0 Then
ActiveCell.EntireRow.Hidden = True
ActiveCell.Offset(1, 0).Select
Else
ActiveCell.Offset(1, 0).Select
Loop

End Sub

In article ,
PJFry wrote:

When I try to compile the code below, I get a 'Loop without Do' error. The
code is designed to loop through an array and hide the rows that have a zero
value.

Thoughts?

You need an

End If

before the

Loop

statement.

Sub HideRow()

Range("B15").Select

Do Until ActiveCell = "STOP"
If ActiveCell.Value = 0 Then
ActiveCell.EntireRow.Hidden = True
ActiveCell.Offset(1, 0).Select
Else
ActiveCell.Offset(1, 0).Select
End if
Loop

End Sub

--
Regards,
Tom Ogilvy


"PJFry" wrote:

When I try to compile the code below, I get a 'Loop without Do' error. The
code is designed to loop through an array and hide the rows that have a zero
value.

Thoughts?
Using Excel 2003.


Sub HideRow()

Range("B15").Select

Do Until ActiveCell = "STOP"
If ActiveCell.Value = 0 Then
ActiveCell.EntireRow.Hidden = True
ActiveCell.Offset(1, 0).Select
Else
ActiveCell.Offset(1, 0).Select
Loop

End Sub

Ah! Works perfectly. Thanks!

"JE McGimpsey" wrote:

In article ,
PJFry wrote:

When I try to compile the code below, I get a 'Loop without Do' error. The
code is designed to loop through an array and hide the rows that have a zero
value.

Thoughts?

You need an

End If

before the

Loop

statement.