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When I try to run this macro I pop box says, "Excel cannot complete
this task with available resources. Choose less data". What am I doing wrong? ActiveCell.FormulaR1C1 = "=IF(ISNA(VLOOKUP(RC[-5],'Fall 2006 Cohort'! R2C1:R65536C28,13,FALSE)=TRUE),"""", VLOOKUP(RC[-5],'Fall 2006 Cohort'! R2C1:R65536C28,13,FALSE))" ActiveCell.Offset(0, 1).Select Thanks in advance. |
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The part of the VLOOKUP function that refers to the lookup table refers
to R2C1:R65536C28. This is 1.8 million + cells of data. Do you really have a lookup table that is that large??? You probably should find a way to set a range variable to just the actual data area. Assuming that the data is in a list, where row 1 is the column labels, then the following technique would locate the data area first, then build the VLOOKUP formula, and finally build the entire formula: Also, I don't think you need the "=TRUE" part in your formula where you are checking to see if the result of the VLOOKUP function ISNA. You had something of the form: "=IF(ISNA(VLOOKUP(...)=TRUE,"""",VLOOKUP(...)) " It should be: "=IF(ISNA(VLOOKUP(...),"""",VLOOKUP(...))" Dim wsData As Worksheet Dim rngDataArea As Range Dim strVLookupFormula As String Dim strFormula As String Set wsData = Worksheets("Fall 2006 Cohort") With wsData.UsedRange 'Actual data area is the used range less the column labels. Set rngDataArea = .Offset(1).Resize(.Rows.Count - 1) End With strVLookupFormula = "VLOOKUP(RC[-5]," _ & rngDataArea.Address(ReferenceStyle:=xlR1C1, _ External:=True) & ",13,FALSE)" strFormula = "=IF(ISNA(" & strVLookupFormula _ & "),""""," & strVLookupFormula & ")" ActiveCell.FormulaR1C1 = strFormula ActiveCell.Offset(0, 1).Select Also, you should probably check what column the ActiveCell is in before running this macro, as an error will result if it is less than 5 columns from the left side of the worksheet (the "RC[-5]" part of the VLOOKUP formula). -- Regards, Bill Renaud |
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