Home |
Search |
Today's Posts |
|
#1
![]()
Posted to microsoft.public.excel.programming
|
|||
|
|||
![]()
Hi everyone,
I am trying to create a "Gaps" program that cycles through ALL 13,983,816 combinations in a 6 from 49 Lotto and produces the following data. I would like it to work out the Gaps between each of the balls for EACH combination in a 6 from 49 Lotto with no replacement. For example, the combination 02 08 18 28 36 45 will have the Gaps of ... Ball 1 numbered 02 & Ball 2 numbered 08 = 05 Gaps ( 03 04 05 06 07 ) Ball 2 numbered 08 & Ball 3 numbered 18 = 09 Gaps ( 19 10 11 12 13 14 15 16 17 ) Ball 3 numbered 18 & Ball 4 numbered 28 = 08 Gaps ( 20 21 22 23 24 25 26 27 ) Ball 4 numbered 28 & Ball 5 numbered 36 = 07 Gaps ( 29 30 31 32 33 34 35 ) Ball 5 numbered 36 & Ball 6 numbered 45 = 08 Gaps ( 37 38 39 40 41 42 43 44 ) .... so the Gaps description for this particular combination will be 05 09 08 07 08. The Gaps difference between ball 1 and ball 2 is really ball 2 minus ball 1 - 1 and so on. I would like to have a Gaps description for each category and the Total combinations for each category associated with that list. So extracting three combinations from the Loop as an example ... Combination - 02 09 16 25 38 45 Combination - 04 15 19 36 37 49 Combination - 09 15 28 39 46 47 .... will give the answer ... Gaps 06 06 08 12 06 = x combinations ( x could be 925,365 combinations with the exact same Gaps between the balls 1-2, 2-3 ,3-4 ,4-5 & 5-6 ) Gaps 10 03 16 00 11 = x combinations ( x could be 236,258 combinations with the exact same Gaps between the balls 1-2, 2-3, 3-4, 4-5 & 5-6 ) Gaps 05 12 10 06 00 = x combinations ( x could be 756,258 combinations with the exact same Gaps between the balls 1-2, 2-3, 3-4, 4-5 & 5-6 ) .... etc. It would also be nice to have a Total at the bottom of the combinations list, which of course, should equal 13,983,816 combinations. I have written the following which has nothing to do with what I am trying to achieve above, but for some reason it does not work. It is supposed to give me a list of Gaps from 00 to 43 from ALL 13,983,816 combinations. The list of Gaps should be in cells B3:B45 and the total combinatios for each gap should be in cells C3:C45. Could somebody please have a glance at it. Option Explicit Option Base 1 Private Sub Gaps() Dim A As Integer Dim B As Integer Dim C As Integer Dim D As Integer Dim E As Integer Dim F As Integer Dim i As Integer Dim GapsTotal(43) As Long Application.ScreenUpdating = False For i = 1 To 43 GapsTotal(i) = 0 Next i For A = 1 To 44 For B = A + 1 To 45 For C = B + 1 To 46 For D = C + 1 To 47 For E = D + 1 To 48 For F = E + 1 To 49 If B - A - 1 = 0 Then GapsTotal(0) = GapsTotal(0) + 1 If C - B - 1 = 0 Then GapsTotal(0) = GapsTotal(0) + 1 If D - C - 1 = 0 Then GapsTotal(0) = GapsTotal(0) + 1 If E - D - 1 = 0 Then GapsTotal(0) = GapsTotal(0) + 1 If F - E - 1 = 0 Then GapsTotal(0) = GapsTotal(0) + 1 If B - A - 1 = 1 Then GapsTotal(1) = GapsTotal(1) + 1 If C - B - 1 = 1 Then GapsTotal(1) = GapsTotal(1) + 1 If D - C - 1 = 1 Then GapsTotal(1) = GapsTotal(1) + 1 If E - D - 1 = 1 Then GapsTotal(1) = GapsTotal(1) + 1 If F - E - 1 = 1 Then GapsTotal(1) = GapsTotal(1) + 1 .... continued all the way down to ... If B - A - 1 = 42 Then GapsTotal(42) = GapsTotal(42) + 1 If C - B - 1 = 42 Then GapsTotal(42) = GapsTotal(42) + 1 If D - C - 1 = 42 Then GapsTotal(42) = GapsTotal(42) + 1 If E - D - 1 = 42 Then GapsTotal(42) = GapsTotal(42) + 1 If F - E - 1 = 42 Then GapsTotal(42) = GapsTotal(42) + 1 If B - A - 1 = 43 Then GapsTotal(43) = GapsTotal(43) + 1 If C - B - 1 = 43 Then GapsTotal(43) = GapsTotal(43) + 1 If D - C - 1 = 43 Then GapsTotal(43) = GapsTotal(43) + 1 If E - D - 1 = 43 Then GapsTotal(43) = GapsTotal(43) + 1 If F - E - 1 = 43 Then GapsTotal(43) = GapsTotal(43) + 1 Next F Next E Next D Next C Next B Next A Sheets("Gaps Data").Select Range("B2").Value = "Gaps" Range("B3").Value = "Gaps of 00" Range("B4").Value = "Gaps of 01" .... continued all the way down to ... Range("B44").Value = "Gaps of 42" Range("B45").Value = "Gaps of 43" Range("C2").Value = "Total" Range("C3").Select For i = 1 To 43 ActiveCell.Offset(i, 0).Value = GapsTotal(i) Next i Application.ScreenUpdating = True End Sub Any help will be greatly appreciated. Thanks in Advance. All the Best. Paul |
#2
![]()
Posted to microsoft.public.excel.programming
|
|||
|
|||
![]()
I'm confused, and don't see how you get this:
Gaps 06 06 08 12 06 = x combinations ( x could be 925,365 combinations with the exact same Gaps between the balls 1-2, 2-3 ,3-4 ,4-5 & 5-6 ) Those 'gaps' can only be produced by 6 different combinations: 01 08 15 24 37 44 02 09 16 25 38 45 03 10 17 26 39 46 04 11 18 27 40 47 05 12 19 28 41 48 06 13 20 29 42 49 In general, the number of combinations for any gap combinations would be 49 - SUM(Gaps) - 5 For the example above, 49 - 38 - 5 = 6 combinations There will be lots of combinations of gaps that can only be produced by one combination. For example: Gaps 01 01 01 01 01 39 would be uniquely 01 03 05 07 09 49 HTH, Bernie MS Excel MVP "Paul Black" wrote in message oups.com... Hi everyone, I am trying to create a "Gaps" program that cycles through ALL 13,983,816 combinations in a 6 from 49 Lotto and produces the following data. I would like it to work out the Gaps between each of the balls for EACH combination in a 6 from 49 Lotto with no replacement. For example, the combination 02 08 18 28 36 45 will have the Gaps of ... Ball 1 numbered 02 & Ball 2 numbered 08 = 05 Gaps ( 03 04 05 06 07 ) Ball 2 numbered 08 & Ball 3 numbered 18 = 09 Gaps ( 19 10 11 12 13 14 15 16 17 ) Ball 3 numbered 18 & Ball 4 numbered 28 = 08 Gaps ( 20 21 22 23 24 25 26 27 ) Ball 4 numbered 28 & Ball 5 numbered 36 = 07 Gaps ( 29 30 31 32 33 34 35 ) Ball 5 numbered 36 & Ball 6 numbered 45 = 08 Gaps ( 37 38 39 40 41 42 43 44 ) ... so the Gaps description for this particular combination will be 05 09 08 07 08. The Gaps difference between ball 1 and ball 2 is really ball 2 minus ball 1 - 1 and so on. I would like to have a Gaps description for each category and the Total combinations for each category associated with that list. So extracting three combinations from the Loop as an example ... Combination - 02 09 16 25 38 45 Combination - 04 15 19 36 37 49 Combination - 09 15 28 39 46 47 ... will give the answer ... Gaps 06 06 08 12 06 = x combinations ( x could be 925,365 combinations with the exact same Gaps between the balls 1-2, 2-3 ,3-4 ,4-5 & 5-6 ) Gaps 10 03 16 00 11 = x combinations ( x could be 236,258 combinations with the exact same Gaps between the balls 1-2, 2-3, 3-4, 4-5 & 5-6 ) Gaps 05 12 10 06 00 = x combinations ( x could be 756,258 combinations with the exact same Gaps between the balls 1-2, 2-3, 3-4, 4-5 & 5-6 ) ... etc. It would also be nice to have a Total at the bottom of the combinations list, which of course, should equal 13,983,816 combinations. I have written the following which has nothing to do with what I am trying to achieve above, but for some reason it does not work. It is supposed to give me a list of Gaps from 00 to 43 from ALL 13,983,816 combinations. The list of Gaps should be in cells B3:B45 and the total combinatios for each gap should be in cells C3:C45. Could somebody please have a glance at it. Option Explicit Option Base 1 Private Sub Gaps() Dim A As Integer Dim B As Integer Dim C As Integer Dim D As Integer Dim E As Integer Dim F As Integer Dim i As Integer Dim GapsTotal(43) As Long Application.ScreenUpdating = False For i = 1 To 43 GapsTotal(i) = 0 Next i For A = 1 To 44 For B = A + 1 To 45 For C = B + 1 To 46 For D = C + 1 To 47 For E = D + 1 To 48 For F = E + 1 To 49 If B - A - 1 = 0 Then GapsTotal(0) = GapsTotal(0) + 1 If C - B - 1 = 0 Then GapsTotal(0) = GapsTotal(0) + 1 If D - C - 1 = 0 Then GapsTotal(0) = GapsTotal(0) + 1 If E - D - 1 = 0 Then GapsTotal(0) = GapsTotal(0) + 1 If F - E - 1 = 0 Then GapsTotal(0) = GapsTotal(0) + 1 If B - A - 1 = 1 Then GapsTotal(1) = GapsTotal(1) + 1 If C - B - 1 = 1 Then GapsTotal(1) = GapsTotal(1) + 1 If D - C - 1 = 1 Then GapsTotal(1) = GapsTotal(1) + 1 If E - D - 1 = 1 Then GapsTotal(1) = GapsTotal(1) + 1 If F - E - 1 = 1 Then GapsTotal(1) = GapsTotal(1) + 1 ... continued all the way down to ... If B - A - 1 = 42 Then GapsTotal(42) = GapsTotal(42) + 1 If C - B - 1 = 42 Then GapsTotal(42) = GapsTotal(42) + 1 If D - C - 1 = 42 Then GapsTotal(42) = GapsTotal(42) + 1 If E - D - 1 = 42 Then GapsTotal(42) = GapsTotal(42) + 1 If F - E - 1 = 42 Then GapsTotal(42) = GapsTotal(42) + 1 If B - A - 1 = 43 Then GapsTotal(43) = GapsTotal(43) + 1 If C - B - 1 = 43 Then GapsTotal(43) = GapsTotal(43) + 1 If D - C - 1 = 43 Then GapsTotal(43) = GapsTotal(43) + 1 If E - D - 1 = 43 Then GapsTotal(43) = GapsTotal(43) + 1 If F - E - 1 = 43 Then GapsTotal(43) = GapsTotal(43) + 1 Next F Next E Next D Next C Next B Next A Sheets("Gaps Data").Select Range("B2").Value = "Gaps" Range("B3").Value = "Gaps of 00" Range("B4").Value = "Gaps of 01" ... continued all the way down to ... Range("B44").Value = "Gaps of 42" Range("B45").Value = "Gaps of 43" Range("C2").Value = "Total" Range("C3").Select For i = 1 To 43 ActiveCell.Offset(i, 0).Value = GapsTotal(i) Next i Application.ScreenUpdating = True End Sub Any help will be greatly appreciated. Thanks in Advance. All the Best. Paul |
#3
![]()
Posted to microsoft.public.excel.programming
|
|||
|
|||
![]()
Bernie:
01 08 15 24 37 44 the numbers with X's represent the GAPS the number of numbers in the GAPS make up the pattern 06 06 08 12 06. You could repeat this pattern a total of 6 times until you ran out of numbers. 1 2x 3x 4x 6 5x 6x 7x 8 9x 10x 11x 12x 6 13x 14x 15 16x 17x 18x 19x 20x 8 21x 22x 23x 24 25x 26x 27x 28x 29x 30x 12 31x 32x 33x 34x 35x 36x 37 38x 39x 40x 6 41x 42x 43x 44 45 46 47 48 49 -- Regards, Tom Ogilvy "Bernie Deitrick" wrote: I'm confused, and don't see how you get this: Gaps 06 06 08 12 06 = x combinations ( x could be 925,365 combinations with the exact same Gaps between the balls 1-2, 2-3 ,3-4 ,4-5 & 5-6 ) Those 'gaps' can only be produced by 6 different combinations: 01 08 15 24 37 44 02 09 16 25 38 45 03 10 17 26 39 46 04 11 18 27 40 47 05 12 19 28 41 48 06 13 20 29 42 49 In general, the number of combinations for any gap combinations would be 49 - SUM(Gaps) - 5 For the example above, 49 - 38 - 5 = 6 combinations There will be lots of combinations of gaps that can only be produced by one combination. For example: Gaps 01 01 01 01 01 39 would be uniquely 01 03 05 07 09 49 HTH, Bernie MS Excel MVP "Paul Black" wrote in message oups.com... Hi everyone, I am trying to create a "Gaps" program that cycles through ALL 13,983,816 combinations in a 6 from 49 Lotto and produces the following data. I would like it to work out the Gaps between each of the balls for EACH combination in a 6 from 49 Lotto with no replacement. For example, the combination 02 08 18 28 36 45 will have the Gaps of ... Ball 1 numbered 02 & Ball 2 numbered 08 = 05 Gaps ( 03 04 05 06 07 ) Ball 2 numbered 08 & Ball 3 numbered 18 = 09 Gaps ( 19 10 11 12 13 14 15 16 17 ) Ball 3 numbered 18 & Ball 4 numbered 28 = 08 Gaps ( 20 21 22 23 24 25 26 27 ) Ball 4 numbered 28 & Ball 5 numbered 36 = 07 Gaps ( 29 30 31 32 33 34 35 ) Ball 5 numbered 36 & Ball 6 numbered 45 = 08 Gaps ( 37 38 39 40 41 42 43 44 ) ... so the Gaps description for this particular combination will be 05 09 08 07 08. The Gaps difference between ball 1 and ball 2 is really ball 2 minus ball 1 - 1 and so on. I would like to have a Gaps description for each category and the Total combinations for each category associated with that list. So extracting three combinations from the Loop as an example ... Combination - 02 09 16 25 38 45 Combination - 04 15 19 36 37 49 Combination - 09 15 28 39 46 47 ... will give the answer ... Gaps 06 06 08 12 06 = x combinations ( x could be 925,365 combinations with the exact same Gaps between the balls 1-2, 2-3 ,3-4 ,4-5 & 5-6 ) Gaps 10 03 16 00 11 = x combinations ( x could be 236,258 combinations with the exact same Gaps between the balls 1-2, 2-3, 3-4, 4-5 & 5-6 ) Gaps 05 12 10 06 00 = x combinations ( x could be 756,258 combinations with the exact same Gaps between the balls 1-2, 2-3, 3-4, 4-5 & 5-6 ) ... etc. It would also be nice to have a Total at the bottom of the combinations list, which of course, should equal 13,983,816 combinations. I have written the following which has nothing to do with what I am trying to achieve above, but for some reason it does not work. It is supposed to give me a list of Gaps from 00 to 43 from ALL 13,983,816 combinations. The list of Gaps should be in cells B3:B45 and the total combinatios for each gap should be in cells C3:C45. Could somebody please have a glance at it. Option Explicit Option Base 1 Private Sub Gaps() Dim A As Integer Dim B As Integer Dim C As Integer Dim D As Integer Dim E As Integer Dim F As Integer Dim i As Integer Dim GapsTotal(43) As Long Application.ScreenUpdating = False For i = 1 To 43 GapsTotal(i) = 0 Next i For A = 1 To 44 For B = A + 1 To 45 For C = B + 1 To 46 For D = C + 1 To 47 For E = D + 1 To 48 For F = E + 1 To 49 If B - A - 1 = 0 Then GapsTotal(0) = GapsTotal(0) + 1 If C - B - 1 = 0 Then GapsTotal(0) = GapsTotal(0) + 1 If D - C - 1 = 0 Then GapsTotal(0) = GapsTotal(0) + 1 If E - D - 1 = 0 Then GapsTotal(0) = GapsTotal(0) + 1 If F - E - 1 = 0 Then GapsTotal(0) = GapsTotal(0) + 1 If B - A - 1 = 1 Then GapsTotal(1) = GapsTotal(1) + 1 If C - B - 1 = 1 Then GapsTotal(1) = GapsTotal(1) + 1 If D - C - 1 = 1 Then GapsTotal(1) = GapsTotal(1) + 1 If E - D - 1 = 1 Then GapsTotal(1) = GapsTotal(1) + 1 If F - E - 1 = 1 Then GapsTotal(1) = GapsTotal(1) + 1 ... continued all the way down to ... If B - A - 1 = 42 Then GapsTotal(42) = GapsTotal(42) + 1 If C - B - 1 = 42 Then GapsTotal(42) = GapsTotal(42) + 1 If D - C - 1 = 42 Then GapsTotal(42) = GapsTotal(42) + 1 If E - D - 1 = 42 Then GapsTotal(42) = GapsTotal(42) + 1 If F - E - 1 = 42 Then GapsTotal(42) = GapsTotal(42) + 1 If B - A - 1 = 43 Then GapsTotal(43) = GapsTotal(43) + 1 If C - B - 1 = 43 Then GapsTotal(43) = GapsTotal(43) + 1 If D - C - 1 = 43 Then GapsTotal(43) = GapsTotal(43) + 1 If E - D - 1 = 43 Then GapsTotal(43) = GapsTotal(43) + 1 If F - E - 1 = 43 Then GapsTotal(43) = GapsTotal(43) + 1 Next F Next E Next D Next C Next B Next A Sheets("Gaps Data").Select Range("B2").Value = "Gaps" Range("B3").Value = "Gaps of 00" Range("B4").Value = "Gaps of 01" ... continued all the way down to ... Range("B44").Value = "Gaps of 42" Range("B45").Value = "Gaps of 43" Range("C2").Value = "Total" Range("C3").Select For i = 1 To 43 ActiveCell.Offset(i, 0).Value = GapsTotal(i) Next i Application.ScreenUpdating = True End Sub Any help will be greatly appreciated. Thanks in Advance. All the Best. Paul |
#4
![]()
Posted to microsoft.public.excel.programming
|
|||
|
|||
![]() Tom, You could repeat this pattern a total of 6 times until you ran out of numbers. I think we're in agreement: Those 'gaps' can only be produced by 6 different combinations: 01 08 15 24 37 44 02 09 16 25 38 45 03 10 17 26 39 46 04 11 18 27 40 47 05 12 19 28 41 48 06 13 20 29 42 49 But I have no idea how the OP got 925,365 combinations: Gaps 06 06 08 12 06 = x combinations ( x could be 925,365 combinations with the exact same Gaps between the balls 1-2, 2-3 ,3-4 ,4-5 & 5-6 ) Bernie |
#5
![]()
Posted to microsoft.public.excel.programming
|
|||
|
|||
![]()
Whoops!
mistook your explantion for part of your question <face red. Have to confess I didn't read the original post so thought it was all a quote. -- Regards, Tom Ogilvy "Bernie Deitrick" wrote: Tom, You could repeat this pattern a total of 6 times until you ran out of numbers. I think we're in agreement: Those 'gaps' can only be produced by 6 different combinations: 01 08 15 24 37 44 02 09 16 25 38 45 03 10 17 26 39 46 04 11 18 27 40 47 05 12 19 28 41 48 06 13 20 29 42 49 But I have no idea how the OP got 925,365 combinations: Gaps 06 06 08 12 06 = x combinations ( x could be 925,365 combinations with the exact same Gaps between the balls 1-2, 2-3 ,3-4 ,4-5 & 5-6 ) Bernie |
#6
![]()
Posted to microsoft.public.excel.programming
|
|||
|
|||
![]()
Thanks for the code Bernie.
I don't have access to Excel at the moment so am unable to test the code. Does the code apply to my original request or to my Private Sub Gaps() effort please. I assume it applies to my effort. It is my original request that is the most important one. Thanks in Advance. All the Best. Paul On Jul 10, 5:04 pm, Tom Ogilvy wrote: Whoops! mistook your explantion for part of your question <face red. Have to confess I didn't read the original post so thought it was all a quote. -- Regards, Tom Ogilvy "Bernie Deitrick" wrote: Tom, You could repeat this pattern a total of 6 times until you ran out of numbers. I think we're in agreement: Those 'gaps' can only be produced by 6 different combinations: 01 08 15 24 37 44 02 09 16 25 38 45 03 10 17 26 39 46 04 11 18 27 40 47 05 12 19 28 41 48 06 13 20 29 42 49 But I have no idea how the OP got 925,365 combinations: Gaps 06 06 08 12 06 = x combinations ( x could be 925,365 combinations with the exact same Gaps between the balls 1-2, 2-3 ,3-4 ,4-5 & 5-6 ) Bernie- Hide quoted text - - Show quoted text - |
#7
![]()
Posted to microsoft.public.excel.programming
|
|||
|
|||
![]()
Thanks for the reply Bernie,
The Gaps 06 06 08 12 06 = x combinations ( x could be 925,365 combinations with the exact same Gaps between the balls 1 & 2, and 2 & 3, and 3 & 4, and 4 & 5, and 5 & 6 ) is only an example figure, I have no idea what the actual figure is, or come to it, how to code it. There can only be 5 criteria for each combination. These are the gaps between balls ... 1 and 2 2 and 3 3 and 4 4 and 5 5 and 6 .... obviously with ALL 13,983,816 combinations there will be quite a few categories. The Gaps are produced for each category using all the 6 numbers within each combination. Begin Quote :- Gaps 01 01 01 01 01 39 ( how did you get the 6 sets of numbers? ) ... .... would be uniquely 01 03 05 07 09 49 End Quote. I don't quite understand it when you say ... Begin Quote :- Gaps 06 06 08 12 06 = x combinations ( x could be 925,365 combinations with the exact same Gaps between the balls 1-2, 2-3 ,3-4 ,4-5 & 5-6 ) Those 'Gaps' can only be produced by 6 different combinations :- 01 08 15 24 37 44 02 09 16 25 38 45 03 10 17 26 39 46 04 11 18 27 40 47 05 12 19 28 41 48 06 13 20 29 42 49 In general, the number of combinations for any gap combinations would be 49 - SUM(Gaps) - 5 For the example above, 49 - 38 - 5 = 6 combinations. There will be lots of combinations of Gaps that can only be produced by one combination. End Quote. Thanks again. All the Best. Paul |
#8
![]()
Posted to microsoft.public.excel.programming
|
|||
|
|||
![]()
Paul,
Try the macro below HTH, Bernie MS Excel MVP Private Sub Gaps2() Dim A As Integer Dim B As Integer Dim C As Integer Dim D As Integer Dim E As Integer Dim F As Integer Dim i As Integer Dim GapsTotal(0 To 43) As Long Application.ScreenUpdating = False For i = 0 To 43 GapsTotal(i) = 0 Next i For A = 1 To 44 For B = A + 1 To 45 For C = B + 1 To 46 For D = C + 1 To 47 For E = D + 1 To 48 For F = E + 1 To 49 GapsTotal(B - A - 1) = GapsTotal(B - A - 1) + 1 GapsTotal(C - B - 1) = GapsTotal(C - B - 1) + 1 GapsTotal(D - C - 1) = GapsTotal(D - C - 1) + 1 GapsTotal(E - D - 1) = GapsTotal(E - D - 1) + 1 GapsTotal(F - E - 1) = GapsTotal(F - E - 1) + 1 Next F Next E Next D Next C Next B Next A Sheets("Gaps Data").Range("B2").Value = "Gaps" Sheets("Gaps Data").Range("C2").Value = "Total" For i = 0 To 43 Sheets("Gaps Data").Cells(i + 3, 2).Value = "Gaps of " & Format(i, "00") Sheets("Gaps Data").Cells(i + 3, 3).Value = GapsTotal(i) Next i Application.ScreenUpdating = True End Sub "Paul Black" wrote in message oups.com... Thanks for the reply Bernie, The Gaps 06 06 08 12 06 = x combinations ( x could be 925,365 combinations with the exact same Gaps between the balls 1 & 2, and 2 & 3, and 3 & 4, and 4 & 5, and 5 & 6 ) is only an example figure, I have no idea what the actual figure is, or come to it, how to code it. There can only be 5 criteria for each combination. These are the gaps between balls ... 1 and 2 2 and 3 3 and 4 4 and 5 5 and 6 ... obviously with ALL 13,983,816 combinations there will be quite a few categories. The Gaps are produced for each category using all the 6 numbers within each combination. Begin Quote :- Gaps 01 01 01 01 01 39 ( how did you get the 6 sets of numbers? ) ... ... would be uniquely 01 03 05 07 09 49 End Quote. I don't quite understand it when you say ... Begin Quote :- Gaps 06 06 08 12 06 = x combinations ( x could be 925,365 combinations with the exact same Gaps between the balls 1-2, 2-3 ,3-4 ,4-5 & 5-6 ) Those 'Gaps' can only be produced by 6 different combinations :- 01 08 15 24 37 44 02 09 16 25 38 45 03 10 17 26 39 46 04 11 18 27 40 47 05 12 19 28 41 48 06 13 20 29 42 49 In general, the number of combinations for any gap combinations would be 49 - SUM(Gaps) - 5 For the example above, 49 - 38 - 5 = 6 combinations. There will be lots of combinations of Gaps that can only be produced by one combination. End Quote. Thanks again. All the Best. Paul |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Possible to auto-fill in gaps between numbers on straight line bas | Excel Worksheet Functions | |||
Transpose Column With Gaps to Column With no gaps | Excel Discussion (Misc queries) | |||
VBA: Calculating Complex Numbers | Excel Discussion (Misc queries) | |||
serial numbers how to find gaps | New Users to Excel | |||
Transpose Column With Gaps to Row With No Gaps? | Excel Discussion (Misc queries) |