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I need to sum a range of cells until a taget value is reached or just
under target value is reached. Once I have reached the target, I would like to get the cell address of tthe cell directly above that point. Simplified Example: A1:F1 contains Jan, Feb, Mar, Apr, May, Jun A2:F2 contains 2, 4, 7, 3, 1, 5 A5 contains the target, 16 I need the output to indicate "Apr" or the cell address "D1" I can do this in VBA; however in this instance, I would prefer to use cell-based formulas. I have tried to use array formulas, but with no success. Any ideas? Any help would be appreciated. |
#2
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very easy with a helper row.
in A3 enter =A2 in B3 enter =IF(A3+B2<=$A$5,A3+B2,-99999) and copy across to see: jan feb mar apr may jun 2 4 7 3 1 5 2 6 13 16 -99999 -99994 in any cell enter =OFFSET(A1,,MATCH(MAX(3:3),3:3,1)-1) -- Gary''s Student - gsnu200729 " wrote: I need to sum a range of cells until a taget value is reached or just under target value is reached. Once I have reached the target, I would like to get the cell address of tthe cell directly above that point. Simplified Example: A1:F1 contains Jan, Feb, Mar, Apr, May, Jun A2:F2 contains 2, 4, 7, 3, 1, 5 A5 contains the target, 16 I need the output to indicate "Apr" or the cell address "D1" I can do this in VBA; however in this instance, I would prefer to use cell-based formulas. I have tried to use array formulas, but with no success. Any ideas? Any help would be appreciated. |
#3
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![]() Many Thanks. I see how this works in the example I provided. If I change the target to say, 13, then I get "June" as a response, not "Mar". This appears to be due to the subtraction of 1 from the column argument of the OFFSET function, correct? Is there a way to make it solvable for whatever the target is (within reason)? |
#4
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The subtraction of one is O.K. My error was using 1 as the last argument of
MATCH. Here is the corrected formula: =OFFSET(A1,,MATCH(MAX(3:3),3:3,0)-1) sorry -- Gary''s Student - gsnu200729 " wrote: Many Thanks. I see how this works in the example I provided. If I change the target to say, 13, then I get "June" as a response, not "Mar". This appears to be due to the subtraction of 1 from the column argument of the OFFSET function, correct? Is there a way to make it solvable for whatever the target is (within reason)? |
#5
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On Jun 14, 2:14 pm, Gary''s Student
wrote: The subtraction of one is O.K. My error was using 1 as the last argument of MATCH. Here is the corrected formula: =OFFSET(A1,,MATCH(MAX(3:3),3:3,0)-1) sorry -- Gary''s Student - gsnu200729 Not a problem. I appreciate the assistance. |
#6
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In another post, Harlan constructed a formula which returns an array of
subtotals - which I believe can be used for your purposes. =INDEX(A1:F1,MATCH(A5,MMULT(--(TRANSPOSE(COLUMN(A2:F2))=COLUMN(A2:F2)),TRANSPOS E(A2:F2)),1)) array entered. " wrote: On Jun 14, 2:14 pm, Gary''s Student wrote: The subtraction of one is O.K. My error was using 1 as the last argument of MATCH. Here is the corrected formula: =OFFSET(A1,,MATCH(MAX(3:3),3:3,0)-1) sorry -- Gary''s Student - gsnu200729 Not a problem. I appreciate the assistance. |
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